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Chapter 8

Statistics

Nepal Rastra Bank past exam questions

Past questions and answers

2 questions set from this chapter. Most repeated first.

  • 2082 · 1st · 2+2+2+4 marks

Find the value of median and mode from the data given below.
Class interval30-4040-5050-6060-7070-8080-9090-100
Frequency357111031

Answer

Total frequency: N=3+5+7+11+10+3+1=40N = 3+5+7+11+10+3+1 = 40

Class intervalFrequency (ff)Cumulative frequency (cfcf)
30–4033
40–5058
50–60715
60–701126
70–801036
80–90339
90–100140

Median

N2=402=20\frac{N}{2}=\frac{40}{2}=20

The cumulative frequency just greater than 20 is 26, so the median class is 60–70.

L=60,cf=15,f=11,h=10L=60,\quad cf=15,\quad f=11,\quad h=10

Median=L+N2−cff×h\text{Median}=L+\frac{\frac{N}{2}-cf}{f}\times h

=60+20−1511×10=60+\frac{20-15}{11}\times 10

=60+5011=60+4.55=64.55=60+\frac{50}{11}=60+4.55=64.55

Median=64.55\boxed{\text{Median}=64.55}

Mode

The highest frequency is 11, so the modal class is 60–70.

L=60,f1=11,f0=7,f2=10,h=10L=60,\quad f_1=11,\quad f_0=7,\quad f_2=10,\quad h=10

Mode=L+f1−f02f1−f0−f2×h\text{Mode}=L+\frac{f_1-f_0}{2f_1-f_0-f_2}\times h

=60+11−72(11)−7−10×10=60+\frac{11-7}{2(11)-7-10}\times 10

=60+422−17×10=60+\frac{4}{22-17}\times 10

=60+45×10=60+8=68=60+\frac{4}{5}\times 10=60+8=68

Mode=68\boxed{\text{Mode}=68}

Answer: Median = 64.55, Mode = 68.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2082 · 1st · 2+2+2+4 marks

Using Laspeyres method and Paasche method, find the Price Index Number from the given data.
ItemsBase Year dataCurrent year data
P0Q0
A110
B512
C85

Answer

Given:

ItemsP0P_0Q0Q_0P1P_1Q1Q_1
A1101.58
B5126.010
C8510.02

Here P0,Q0P_0, Q_0 are base-year price and quantity, and P1,Q1P_1, Q_1 are current-year price and quantity. Prices are in Rs.


1. Laspeyres Price Index Number

Formula:

P01L=∑P1Q0∑P0Q0×100P_{01}^{L}=\frac{\sum P_1Q_0}{\sum P_0Q_0}\times 100

Calculation table:

ItemsP0Q0P_0Q_0P1Q0P_1Q_0
A1×10=101\times 10=101.5×10=151.5\times 10=15
B5×12=605\times 12=606×12=726\times 12=72
C8×5=408\times 5=4010×5=5010\times 5=50
Total∑P0Q0=110\sum P_0Q_0=110∑P1Q0=137\sum P_1Q_0=137
P01L=137110×100P_{01}^{L}=\frac{137}{110}\times 100 P01L=124.5454≈124.55P_{01}^{L}=124.5454\approx \boxed{124.55}

So, by Laspeyres method, the Price Index Number is 124.55.


2. Paasche Price Index Number

Formula:

P01P=∑P1Q1∑P0Q1×100P_{01}^{P}=\frac{\sum P_1Q_1}{\sum P_0Q_1}\times 100

Calculation table:

ItemsP0Q1P_0Q_1P1Q1P_1Q_1
A1×8=81\times 8=81.5×8=121.5\times 8=12
B5×10=505\times 10=506×10=606\times 10=60
C8×2=168\times 2=1610×2=2010\times 2=20
Total∑P0Q1=74\sum P_0Q_1=74∑P1Q1=92\sum P_1Q_1=92
P01P=9274×100P_{01}^{P}=\frac{92}{74}\times 100 P01P=124.3243≈124.32P_{01}^{P}=124.3243\approx \boxed{124.32}

So, by Paasche method, the Price Index Number is 124.32.


Answer:

  • Laspeyres Price Index Number = 124.55
  • Paasche Price Index Number = 124.32

Answer checked by Claude Sonnet · Oct 21, 2026

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