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Chapter 2

Mathematics

+2 college entrance (after SEE) past exam questions

Past questions and answers

20 questions set from this chapter. Most repeated first.

  • 2026 Set A · 1 mark

The possible number of subsets for a set PP is 16 then the set PP is (a) P={a,b}P=\{a,b\} (b) P={a,b,c}P=\{a,b,c\} (c) P={a,b,c,d}P=\{a,b,c,d\} (d) P={a,b,c,d,e}P=\{a,b,c,d,e\}

Similar questions: If the possible number of subsets (2026 Set B)

Answer

(c) P={a,b,c,d}P=\{a,b,c,d\}

A set with nn elements has 2n2^n subsets. Here 2n=16=242^n=16=2^4, so n=4n=4, and only option (c) has 4 elements.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2026 Set A · 1 mark

What is the simple interest earned on Rs.4000 at the rate of 10% yearly for 18 months? (a) Rs.300 (b) Rs.400 (c) Rs.500 (d) Rs.600

Similar questions: What is the simple interest earned (2026 Set B)

Answer

(d) Rs.600

I=PTR100=4000×1.5×10100=Rs 600I=\frac{PTR}{100}=\frac{4000\times 1.5\times 10}{100}=\text{Rs }600

Here 18 months is 1.51.5 years.

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  • 2026 Set A · 1 mark

If lines represented by the homogeneous equation 3x2−5xy−by2=03x^2-5xy-by^2=0 are orthogonal then (a) b=3b=3 (b) b=15b=15 (c) b=−3b=-3 (d) b=−2512b=-\frac{25}{12}

Similar questions: If lines represented by the homogeneous (2026 Set B)

Answer

(a) b=3b=3

For ax2+2hxy+by2=0ax^2+2hxy+by^2=0 the lines are perpendicular when a+b=0a+b=0 (coefficient of x2x^2 plus coefficient of y2y^2). Here 3+(−b)=03+(-b)=0, so b=3b=3.

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  • 2026 Set B · 1 mark

If the possible number of subsets for a set RR is 64, then the number of elements in set RR is: (a) 44 (b) 55 (c) 66 (d) 88

Similar questions: The possible number of subsets for (2026 Set A)

Answer

(c) 66

A set with nn elements has 2n2^n subsets, so 2n=64=262^n = 64 = 2^6, giving n=6n = 6.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2026 Set B · 1 mark

What is the simple interest earned on Rs. 12,000 at the rate of 8% yearly for 9 months? (a) Rs. 960 (b) Rs. 720 (c) Rs. 840 (d) Rs. 600

Similar questions: What is the simple interest earned (2026 Set A)

Answer

(b) Rs. 720

I=PTR100=12000×912×8100=12000×0.75×8100=Rs. 720I = \frac{PTR}{100} = \frac{12000 \times \frac{9}{12} \times 8}{100} = \frac{12000 \times 0.75 \times 8}{100} = \text{Rs. } 720

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  • 2026 Set B · 1 mark

If lines represented by the homogeneous equation kx2+4xy−5y2=0kx^2+4xy-5y^2=0 are orthogonal, then: (a) k=4k=4 (b) k=5k=5 (c) k=−5k=-5 (d) k=0k=0

Similar questions: If lines represented by the homogeneous (2026 Set A)

Answer

(b) k=5k=5

For ax2+2hxy+by2=0ax^2+2hxy+by^2=0 the lines are perpendicular when a+b=0a+b=0. Here a=ka=k, b=−5b=-5, so k−5=0k-5=0, giving k=5k=5.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2026 Set A · 1 mark

If a:b=2:5a:b=2:5 and a:c=1:4a:c=1:4. Then b:c=b:c= ? (a) 1:101:10 (b) 5:85:8 (c) 1:51:5 (d) 1:21:2

Answer

(b) 5:85:8

Make aa equal in both ratios: a:b=2:5a:b=2:5 and a:c=1:4=2:8a:c=1:4=2:8. Then b:c=5:8b:c=5:8.

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  • 2026 Set A · 1 mark

The H.C.F. of a3−1a^3-1 and a4+a2+1a^4+a^2+1 is (a) a+1a+1 (b) a−1a-1 (c) a2−a+1a^2-a+1 (d) a2+a+1a^2+a+1

Answer

(d) a2+a+1a^2+a+1

a3−1=(a−1)(a2+a+1)a^3-1=(a-1)(a^2+a+1)

a4+a2+1=(a2+1)2−a2=(a2+a+1)(a2−a+1)a^4+a^2+1=(a^2+1)^2-a^2=(a^2+a+1)(a^2-a+1)

The common factor is a2+a+1a^2+a+1.

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  • 2026 Set A · 1 mark

If x2+1x2=18x^2+\frac{1}{x^2}=18, what is the value of x−1xx-\frac{1}{x}? (a) 44 (b) ±4\pm4 (c) 22 (d) ±2\pm2

Answer

(b) ±4\pm4

(x−1x)2=x2+1x2−2=18−2=16\left(x-\frac1x\right)^2=x^2+\frac1{x^2}-2=18-2=16

So x−1x=±4x-\frac1x=\pm4.

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  • 2026 Set A · 1 mark

What is the ratio of circumference to diameter of the circle? (a) π:1\pi:1 (b) 2π:12\pi:1 (c) π:2\pi:2 (d) 2:π2:\pi

Answer

(a) π:1\pi:1

Circumference is C=πdC=\pi d, so C:d=π:1C:d=\pi:1.

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  • 2026 Set A · 1 mark

What is the total surface area of a cubical tank of length of side 10 m? (a) 600 m2600\ m^2 (b) 500 m2500\ m^2 (c) 400 m2400\ m^2 (d) 300 m2300\ m^2

Answer

(a) 600 m2600\ m^2

For a cube, TSA=6a2=6×102=600 m2TSA=6a^2=6\times10^2=600\ m^2.

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  • 2026 Set A · 1 mark

If Xˉ=150\bar{X}=150, N=10N=10, then the value of ∑fx\sum fx is (a) 2424 (b) 600600 (c) 12001200 (d) 15001500

Answer

(d) 15001500

Xˉ=∑fxN⇒∑fx=150×10=1500\bar X=\frac{\sum fx}{N}\Rightarrow \sum fx=150\times10=1500

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  • 2026 Set A · 1 mark

From the normal pack of 52 cards, a card is drawn at random, the probability of getting a king is... (a) 14\frac14 (b) 126\frac{1}{26} (c) 113\frac{1}{13} (d) 12\frac12

Answer

(c) 113\frac{1}{13}

There are 4 kings in 52 cards, so P=452=113P=\frac4{52}=\frac1{13}.

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  • 2026 Set B · 1 mark

If x:y=3:4x:y=3:4 and x:z=2:5x:z=2:5. Then y:z=y:z= ? (a) 3:103:10 (b) 8:158:15 (c) 15:815:8 (d) 4:54:5

Answer

(b) 8:158:15

Make xx equal in both ratios: LCM of 3 and 2 is 6, so x:y=6:8x:y = 6:8 and x:z=6:15x:z = 6:15.

Hence y:z=8:15y:z = 8:15.

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  • 2026 Set B · 1 mark

The H.C.F. of x3−64x^3-64 and x2−16x^2-16 is: (a) x−4x-4 (b) x+4x+4 (c) x2+4x+16x^2+4x+16 (d) (x−4)2(x-4)^2

Answer

(a) x−4x-4

x3−64=(x−4)(x2+4x+16)x^3-64 = (x-4)(x^2+4x+16) and x2−16=(x−4)(x+4)x^2-16 = (x-4)(x+4).

The common factor is x−4x-4, so the H.C.F. is x−4x-4.

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  • 2026 Set B · 1 mark

If x2+1x2=14x^2+\frac{1}{x^2}=14, what is the positive value of x−1xx-\frac{1}{x}? (a) 33 (b) 44 (c) 55 (d) 1616

Answer

(a) 33 (nearest option)

(x−1x)2=x2+1x2−2=14−2=12\left(x-\frac{1}{x}\right)^2 = x^2+\frac{1}{x^2}-2 = 14-2 = 12

So x−1x=12=23≈3.46x-\frac{1}{x} = \sqrt{12} = 2\sqrt{3} \approx 3.46. This is not exactly any of the listed options, and 33 is the closest. (For x2+1x2=11x^2+\frac{1}{x^2}=11 the value would be exactly 33.)

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2026 Set B · 1 mark

If the radius of a circle is doubled, the ratio of the new area to the original area is: (a) 2:12:1 (b) 4:14:1 (c) 1:21:2 (d) 8:18:1

Answer

(b) 4:14:1

Original area =πr2=\pi r^2; new area =π(2r)2=4πr2=\pi(2r)^2 = 4\pi r^2. Ratio =4πr2:πr2=4:1= 4\pi r^2 : \pi r^2 = 4:1.

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  • 2026 Set B · 1 mark

What is the total surface area of a cubical tank if its volume is 216 m3216\ m^3? (a) 216 m2216\ m^2 (b) 144 m2144\ m^2 (c) 36 m236\ m^2 (d) 180 m2180\ m^2

Answer

(a) 216 m2216\ m^2

a3=216⇒a=6a^3 = 216 \Rightarrow a = 6 m.

TSA=6a2=6×36=216 m2\text{TSA} = 6a^2 = 6 \times 36 = 216\ m^2

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  • 2026 Set B · 1 mark

If Xˉ=45\bar{X}=45, N=20N=20, then the value of ∑fx\sum fx is (a) 450450 (b) 900900 (c) 10001000 (d) 9090

Answer

(b) 900900

Xˉ=∑fxN⇒∑fx=Xˉ×N=45×20=900\bar{X} = \frac{\sum fx}{N} \Rightarrow \sum fx = \bar{X}\times N = 45 \times 20 = 900

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  • 2026 Set B · 1 mark

From a normal pack of 52 cards, the probability of getting a red queen is: (a) 113\frac{1}{13} (b) 126\frac{1}{26} (c) 152\frac{1}{52} (d) 14\frac14

Answer

(b) 126\frac{1}{26}

There are 2 red queens (hearts and diamonds) in 52 cards, so

P=252=126P = \frac{2}{52} = \frac{1}{26}

Answer checked by Claude Sonnet · Oct 21, 2026

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Questions from National School of Sciences, Faculty of Management, Entrance Model Question Set A (College-published model question set (30 minutes, 25 marks), 2026) and National School of Sciences, Faculty of Management, Entrance Model Question Set B (College-published model question set (30 minutes, 25 marks), 2026). Answers are written for this site; check them against your class notes.