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Chapter 1

Mathematics

TU BCA entrance past exam questions

Past questions and answers

351 questions set from this chapter, 5 of them more than once. Most repeated first.

  • Asked 2 times
  • 2076 · 1 mark
  • 2022 · 1 mark

If the relation R={(1,2),(2,3),(3,4),(4,5)}R=\{(1,2),(2,3),(3,4),(4,5)\} then its range is, (a) {2,3,4,5}\{2,3,4,5\} (b) {1,2,3,4}\{1,2,3,4\} (c) {1,2,3,5}\{1,2,3,5\} (d) {1,3,4,5}\{1,3,4,5\}

Answer

(a) {2,3,4,5}\{2,3,4,5\}

The range is the set of second elements of the ordered pairs.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 2 times
  • 2076 · 1 mark
  • 2022 · 1 mark

The value of 2128+1622\sqrt{128}+\sqrt{162} is , (a) 25225\sqrt2 (b) 434\sqrt3 (c) 0 (d) 60

Answer

(a) 25225\sqrt2

2128=2⋅82=1622\sqrt{128}=2\cdot8\sqrt2=16\sqrt2 and 162=92\sqrt{162}=9\sqrt2, so the sum is 25225\sqrt2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 2 times
  • 2022 · 1 mark
  • 2023 · 1 mark

If £ 7 = USD 11 and USD 2 = Rs. 213, then how many pound (£) can be exchange for Rs. 117150? (a) 750 (b) 650 (c) 700 (d) 850

Answer

(c) 700

USD2=Rs 213USD 2=\text{Rs }213, so Rs 117150=117150×2213=USD1100117150=\dfrac{117150\times 2}{213}=USD 1100.

USD11=£7USD 11=£7, so USD1100=1100×711=£700USD 1100=\dfrac{1100\times 7}{11}=£700.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 2 times
  • 2022 · 1 mark
  • 2023 · 1 mark

A mobile is sold for Rs. 11000, with a profit of Rs. 1000, then the percentage profit is (a) 9% (b) 10% (c) 12% (d) 14%

Answer

(b) 10%

Cost price =11000−1000=Rs 10000=11000-1000=\text{Rs }10000.

Profit%=100010000×100=10%\text{Profit}\%=\frac{1000}{10000}\times100=10\%

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 2 times
  • 2022 · 1 mark
  • 2023 · 1 mark

The fifth term of the sequence 12,45,78,…\frac12,\frac45,\frac78,\ldots is (a) 1112\frac{11}{12} (b) 1213\frac{12}{13} (c) 1314\frac{13}{14} (d) 1415\frac{14}{15}

Answer

(c) 1314\frac{13}{14}

The numerators are 1,4,7,…1,4,7,\ldots and the denominators are 2,5,8,…2,5,8,\ldots, so tn=3n−23n−1t_n=\frac{3n-2}{3n-1}. Then t5=1314t_5=\frac{13}{14}.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2074 · 1 mark

The sum of first five prime numbers is: (a) 11 (b) 18 (c) 26 (d) 28

Similar questions: What is the sum of first five prime numbers? (2075)

Answer

(d) 28

The first five prime numbers are 2, 3, 5, 7 and 11. Their sum is 2+3+5+7+11=282+3+5+7+11 = 28.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2074 · 1 mark

The product of two consecutive even number is 224. Then the numbers are: (a) 16, 18 (b) 12, 14 (c) 14, 16 (d) 18, 20

Similar questions: If the product of two consecutive even number is 288, then... (2075)

Answer

(c) 14, 16

Because 14×16=22414 \times 16 = 224, and 14 and 16 are consecutive even numbers.

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  • 2074 · 1 mark

If the ratio of two numbers is 2:3 and sum of these numbers is 30, then which are these numbers? (a) 14, 16 (b) 10, 20 (c) 12, 18 (d) 18, 12

Similar questions: Two numbers are in the ratio of 6:7 and their sum is 117,... (2075)

Answer

(c) 12, 18

Let the numbers be 2x2x and 3x3x. Then 2x+3x=30⇒5x=30⇒x=62x+3x=30 \Rightarrow 5x=30 \Rightarrow x=6. So the numbers are 2x=122x=12 and 3x=183x=18.

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  • 2074 · 1 mark

If the cost of 9 kg sugar is Rs. 270/-, how much sugar can be purchased for Rs. 390/-? (a) 11 (b) 12 (c) 13 (d) 14

Similar questions: If the cost of 7 kg sugar is Rs. 210, how much sugar can be... (2075)

Answer

(c) 13

Cost of 1 kg sugar = Rs. 270 ÷ 9 = Rs. 30.
So, sugar for Rs. 390 = 390 ÷ 30 = 13 kg.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2074 · 1 mark

The cardinal number of a vowel set V = {a, e, i, o, u} is: (a) 4 (b) 5 (c) 6 (d) 7

Similar questions: What is the cardinal number of a vowel set V= a,e,i,o,u ? (2075)

Answer

(b) 5

The cardinal number of a set is the number of distinct elements it contains. The set V = {a, e, i, o, u} has five elements, so its cardinal number is 5.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2075 · 1 mark

What is the sum of first five prime numbers? (a) 18 (b) 25 (c) 26 (d) 28

Similar questions: The sum of first five prime numbers (2074)

Answer

(d) 28

The first five primes are 2, 3, 5, 7, 11, and +3+5+7+11=28$.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If the product of two consecutive even number is 288, then what are these numbers from following? (a) 14, 12 (b) 14, 16 (c) 16, 18 (d) 22, 24

Similar questions: The product of two consecutive even number (2074)

Answer

(c) 16, 18

Let the numbers be xx and x+2x+2. Then x(x+2)=288x(x+2)=288, so x2+2x−288=0x^2+2x-288=0, giving (x+18)(x−16)=0(x+18)(x-16)=0. Taking x=16x=16 gives 16 and 18, and 16×18=28816\times18=288.

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  • 2075 · 1 mark

If the cost of 7 kg sugar is Rs. 210, how much sugar can be purchased for Rs. 330? (a) 11kg (b) 12kg (c) 13kg (d) 14kg

Similar questions: If the cost of 9 kg sugar (2074)

Answer

(a) 11kg

1 kg costs 210/7=210/7= Rs 30, so Rs 330 buys 330/30=11330/30=11 kg.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Two numbers are in the ratio of 6:7 and their sum is 117, then what are these numbers? (a) 56, 58 (b) 63, 54 (c) 54, 63 (d) 48, 56

Similar questions: If the ratio of two numbers is (2074)

Answer

(c) 54, 63

One part =117/(6+7)=9=117/(6+7)=9, so the numbers are 6×9=546\times9=54 and 7×9=637\times9=63.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the rate percentage per anum that a sum of money trebles itself in 25 years? (a) 2% (b) 4% (c) 6% (d) 8%

Similar questions: The rate percentage per annum that a sum of money trebles... (2077)

Answer

(d) 8%

The sum trebles, so the interest equals twice the principal: 2P=P×r×251002P=\frac{P\times r\times25}{100}, which gives r=8%r=8\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the cardinal number of a vowel set V={a,e,i,o,u}V=\{a,e,i,o,u\}? (a) 4 (b) 5 (c) 6 (d) 7

Similar questions: The cardinal number of a vowel set (2074)

Answer

(b) 5

The cardinal number is the number of elements, and VV has five: a,e,i,o,ua,e,i,o,u.

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  • 2075 · 1 mark

The area of 4 walls of square room is 120 m2120\,m^2. If the height is 5 m, then what is the area of its floor? (a) 26 m226\,m^2 (b) 56 m256\,m^2 (c) 25 m225\,m^2 (d) 36 m236\,m^2

Similar questions: The area of 4 walls of square room is 120 ,m 2. if the... (2077)

Answer

(d) 36 m236\,m^2

Area of four walls =2(l+b)h==2(l+b)h= perimeter ×h\times h. So perimeter =120/5=24=120/5=24 m and side =6=6 m. Floor area =62=36 m2=6^2=36\,m^2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Of a group of 120 students, 90 takes mathematics and 72 takes statistics. If 10 students neither of two, the number of student taking both subjects are: (a) 50 (b) 45 (c) 52 (d) 58

Similar questions: Of a group of 120 students, 80 takes mathematics and 62... (2022)

Answer

(c) 52

Students taking at least one subject =120−10=110=120-10=110.

n(M∩S)=90+72−110=52n(M\cap S)=90+72-110=52

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

−5<x<7-5<x<7 can be written in the absolute value sign as: (a) ∣x−1∣<7|x-1|<7 (b) ∣x−1∣<6|x-1|<6 (c) ∣x−1∣<2|x-1|<2 (d) ∣x−1∣<−1|x-1|<-1

Similar questions: -5<x<9 can be written in the absolute value sign as: (2022)

Answer

(b) ∣x−1∣<6|x-1|<6

The midpoint of −5-5 and 77 is 11 and the half-width is 66, so −5<x<7  ⟺  ∣x−1∣<6-5<x<7\iff |x-1|<6.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

How many stones each of area 0.16 cm square are required for paving a courtyard 5.5 m long and 4.8 m wide? (a) 60 (b) 100 (c) 50 (d) 165

Similar questions: How many stones each of area 22 ,cm square are required for... (2022)

Answer

(d) 165

The courtyard area is 5.5×4.8=26.4 m25.5\times4.8=26.4\ \text{m}^2. Taking the stone area as 0.16 m20.16\ \text{m}^2 (the only reading that matches the options):

26.40.16=165\frac{26.4}{0.16}=165

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  • 2076 · 1 mark

The discount percent of marked price is Rs. 5,800 and discount amount is Rs. 696 then the discount percent is, (a) 12% (b) 20% (c) 5% (d) 38%

Similar questions: The discount of marked price is Rs. 5,800 the amount Rs.... (2022)

Answer

(a) 12%

6965800×100=12%\frac{696}{5800}\times100=12\%

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  • 2076 · 1 mark

If 4 is subtracted from a square of a number, its result is 21. The number is, (a) 5 (b) 4 (c) 6 (d) 3

Similar questions: If 5 is subtracted from the square of a number and the... (2077)

Answer

(a) 5

x2−4=21⇒x2=25⇒x=5x^2-4=21\Rightarrow x^2=25\Rightarrow x=5 (the option given; −5-5 also satisfies it).

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  • 2077 · 1 mark

The area of 4 walls of square room is 120 m2120\,m^2. if the height is 5m, the area of its floor is (a) 56 m256\,m^2 (b) 36 m236\,m^2 (c) 46 m246\,m^2 (d) 26 m226\,m^2

Similar questions: The area of 4 walls of square room is 120 ,m 2. If the... (2075)

Answer

(b) 36 m236\,m^2

Area of four walls =4×side×height=4\times\text{side}\times\text{height}.

4×s×5=120⇒s=6 m4\times s\times5=120\Rightarrow s=6\ \text{m}

Floor area =62=36 m2=6^2=36\ m^2.

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  • 2077 · 1 mark

The rate percentage per annum that a sum of money trebles itself in 25 years is : (a) 25 % (b) 10% (c) 4% (d) 8%

Similar questions: What is the rate percentage per anum that a sum of money... (2075)

Answer

(d) 8%

Money trebles, so interest =3P−P=2P=3P-P=2P. Using I=PTR100I=\frac{PTR}{100}:

2P=P×25×R100⇒R=8%2P=\frac{P\times25\times R}{100}\Rightarrow R=8\%

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  • 2077 · 1 mark

If 5 is subtracted from the square of a number and the result is 20, the number is : (a) ±5\pm5 (b) ±6\pm6 (c) ±7\pm7 (d) ±9\pm9

Similar questions: If 4 is subtracted from a square of a number, its result is... (2076)

Answer

(a) ±5\pm5

x2−5=20⇒x2=25⇒x=±5x^2-5=20\Rightarrow x^2=25\Rightarrow x=\pm5

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  • 2022 · 1 mark

The Marked Price of an article is Rs. 8500. If a discount of 10% is allowed the selling price is (a) 7550 (b) 7650 (c) 7750 (d) 7850

Similar questions: Marked price of an article is Rs. 8500. If a discount of... (2023)

Answer

(b) 7650

Discount =10%=10\% of 8500=8500 = Rs 850.

SP=8500−850=Rs 7650SP = 8500-850 = \text{Rs } 7650

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  • 2022 · 1 mark

Radius of cylinder is 7 cm height is 12 cm then it's volume is (a) 1848 cm31848\,cm^3 (b) 1748 cm31748\,cm^3 (c) 1648 cm31648\,cm^3 (d) 1548 cm31548\,cm^3

Similar questions: Radius of the cylinder is 7 cm height is 3 cm then it's... (2023)

Answer

(a) 1848 cm31848\,cm^3

V=πr2h=227×49×12=1848 cm3V=\pi r^2h=\frac{22}{7}\times 49\times 12=1848\,cm^3

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  • 2022 · 1 mark

Single equation represented by two straight lines x=2yx=2y and 2x=y2x=y is (a) 2x2−3xy+2y2=02x^2-3xy+2y^2=0 (b) x2−3xy+2y2=0x^2-3xy+2y^2=0 (c) 2x2−xy+2y2=02x^2-xy+2y^2=0 (d) 2x2−3xy+y2=02x^2-3xy+y^2=0

Similar questions: A single equation represented by two straight lines x=2y... (2023)

Answer

(a) 2x2−3xy+2y2=02x^2-3xy+2y^2=0

The product of the two line equations gives (x−2y)(2x−y)=2x2−5xy+2y2=0(x-2y)(2x-y)=2x^2-5xy+2y^2=0. Of the options, only (a) has the correct x2x^2 and y2y^2 coefficients, so it is the intended choice (the middle coefficient in the printed option differs from the exact −5-5).

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  • 2022 · 1 mark

Of a group of 120 students, 80 takes mathematics and 62 takes statistics. If 20 students neither if two, the number of students taking both subjects are (a) 50 (b) 42 (c) 52 (d) 55

Similar questions: Of a group of 120 students, 90 takes mathematics and 72... (2076)

Answer

(b) 42

Students taking at least one subject: 120−20=100120-20=100. Using n(M∪S)=n(M)+n(S)−n(M∩S)n(M\cup S)=n(M)+n(S)-n(M\cap S):

100=80+62−x⇒x=42100=80+62-x \Rightarrow x=42

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  • 2022 · 1 mark

−5<x<9-5<x<9 can be written in the absolute value sign as: (a) ∣x−2∣<5|x-2|<5 (b) ∣x−2∣<7|x-2|<7 (c) ∣x−2∣<9|x-2|<9 (d) ∣x+2∣<5|x+2|<5

Similar questions: -5<x<7 can be written in the absolute value sign as: (2076)

Answer

(b) ∣x−2∣<7|x-2|<7

The interval −5<x<9-5<x<9 has midpoint −5+92=2\frac{-5+9}{2}=2 and half-width 9−(−5)2=7\frac{9-(-5)}{2}=7, so it is ∣x−2∣<7|x-2|<7.

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  • 2022 · 1 mark

How many stones each of area 22 cm22\,cm square are required for paving a courtyard 5.5 m long and 4 m wide? (a) 60000 (b) 40000 (c) 20000 (d) 10000

Similar questions: How many stones each of area 0.16 cm square are required... (2076)

Answer

(d) 10000

Courtyard area =5.5×4=22 m2=220000 cm2=5.5\times4=22\ \text{m}^2=220000\ \text{cm}^2.

Number of stones =22000022=10000=\dfrac{220000}{22}=10000.

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  • 2022 · 1 mark

The discount of marked price is Rs. 5,800 the amount Rs. 696 then discount percent is. (a) 12% (b) 20% (c) 5% (d) 38%

Similar questions: The discount percent of marked price is Rs. 5,800 and... (2076)

Answer

(a) 12%

Discount percent =6965800×100=12%=\dfrac{696}{5800}\times100=12\%.

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  • 2023 · 1 mark

Marked price of an article is Rs. 8500. If a discount of 10% is allowed the selling price is.... (a) 7550 (b) 7650 (c) 7750 (d) 7850

Similar questions: The Marked Price of an article is Rs. 8500. If a discount... (2022)

Answer

(b) 7650 Discount =10%=10\% of 8500 == Rs 850, so the selling price is 8500−850=8500-850= Rs 7650.

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  • 2023 · 1 mark

A single equation represented by two straight lines x=2yx=2y and 2x=y2x=y is ... (a) 2x2−3xy+y2=02x^2-3xy+y^2=0 (b) x2−3xy+2y2=0x^2-3xy+2y^2=0 (c) 2x2−xy+2y2=02x^2-xy+2y^2=0 (d) 2x2−5xy+2y2=02x^2-5xy+2y^2=0

Similar questions: Single equation represented by two straight lines x=2y and... (2022)

Answer

(d) 2x2−5xy+2y2=02x^2-5xy+2y^2=0 The lines are x−2y=0x-2y=0 and 2x−y=02x-y=0. Their combined equation is

(x−2y)(2x−y)=2x2−xy−4xy+2y2=2x2−5xy+2y2=0(x-2y)(2x-y)=2x^2-xy-4xy+2y^2=2x^2-5xy+2y^2=0

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  • 2023 · 1 mark

Radius of the cylinder is 7 cm height is 3 cm then it's volume is (a) 442 cm3442\,cm^3 (b) 452 cm3452\,cm^3 (c) 462 cm3462\,cm^3 (d) 472 cm3472\,cm^3

Similar questions: Radius of cylinder is 7 cm height is 12 cm then it's volume... (2022)

Answer

(c) 462 cm3462\,cm^3

V=πr2h=227×49×3=462 cm3V=\pi r^2h=\frac{22}{7}\times49\times3=462\,cm^3.

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  • 2074 · 1 mark

Which one of the following number has a remainder of 4 when it is divided by 6? (a) 8 (b) 12 (c) 22 (d) 29

Answer

(c) 22

When 22 is divided by 6, 6×3=186 \times 3 = 18, leaving a remainder of 22−18=422 - 18 = 4.

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  • 2074 · 1 mark

The sum of the product and quotient of 4 and 4 is ………. (a) 16 (b) 15 (c) 8 (d) 17

Answer

(d) 17

Product of 4 and 4 = 4×4=164 \times 4 = 16; quotient = 4÷4=14 \div 4 = 1; sum = 16+1=1716 + 1 = 17.

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  • 2074 · 1 mark

The average of all even numbers between -4 and 5 is ….. (a) 1 (b) 0.5 (c) -1 (d) none of these

Answer

(a) 1

Even numbers strictly between (-4) and (5) are (-2, 0, 2, 4).
Average (=\dfrac{-2+0+2+4}{4}=\dfrac{4}{4}=1).

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  • 2074 · 1 mark

The value of ∑n=1010(−1)n\sum_{n=10}^{10} (-1)^n is: (a) 1 (b) -1 (c) 10 (d) 0

Answer

(a) 1

Since the sum runs only from n=10n=10 to n=10n=10, it equals (−1)10=1(-1)^{10}=1.

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  • 2074 · 1 mark

If 5 is added to the square of a number, then the result is 14. What is the value of that number? (a) 3 (b) 5 (c) 7 (d) 9

Answer

(a) 3

Let the number be xx. Then x2+5=14⇒x2=9⇒x=3x^2+5=14 \Rightarrow x^2=9 \Rightarrow x=3 (taking the positive value).

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  • 2074 · 1 mark

If three spoons equals to one glass, two glasses equals to one plate, then how many spoons equals to one plate? (a) 3 (b) 6 (c) 9 (d) 2

Answer

(b) 6

Since 1 glass = 3 spoons and 1 plate = 2 glasses,
1 plate = 2 × 3 = 6 spoons.

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  • 2074 · 1 mark

If a matrix is of order 5 X 7, then each column will contain …………..elements. (a) 5 (b) 12 (c) 35 (d) 7

Answer

(a) 5

A matrix of order 5×75 \times 7 has 5 rows and 7 columns. Each column therefore contains 5 elements (one from each row).

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  • 2074 · 1 mark

If the equation are 3x+4y=73x + 4y = 7 and 4x−y=34x - y = 3 after solving these equations the value of x and y will be: (a) 1,1 (b) 1,2 (c) 2,1 (d) 2,2

Answer

(a) 1, 1

From 4x−y=34x-y=3, y=4x−3y=4x-3. Substituting in 3x+4y=73x+4y=7: 3x+4(4x−3)=7⇒19x=19⇒x=13x+4(4x-3)=7 \Rightarrow 19x=19 \Rightarrow x=1, so y=4(1)−3=1y=4(1)-3=1.

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  • 2074 · 1 mark

What is the value of x in series 1, 9, 25, x, 81, 121? (a) 100 (b) 36 (c) 49 (d) 64

Answer

(c) 49

The terms are the squares of consecutive odd numbers: 12=11^2=1, 32=93^2=9, 52=255^2=25, 72=497^2=49, 92=819^2=81, 112=12111^2=121. So x=72=49x = 7^2 = 49.

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  • 2074 · 1 mark

If a+b=ca + b = c, then what is the average value of a, b and c? (a) (a+b)3\frac{(a+b)}{3} (b) c3\frac{c}{3} (c) 2c3\frac{2c}{3} (d) c3\frac{c}{3}

Answer

(c) 2c3\frac{2c}{3}

Average =a+b+c3=c+c3=2c3=\frac{a+b+c}{3}=\frac{c+c}{3}=\frac{2c}{3}.

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  • 2074 · 1 mark

If x in an integer and y=−2x−8y = -2x - 8, what is the least value of x for which y is less than 9? (a) -8 (b) -9 (c) -10 (d) -11

Answer

(a) -8

Given y=−2x−8y=-2x-8 and y<9y<9: −2x−8<9⇒−2x<17⇒x>−8.5-2x-8<9 \Rightarrow -2x<17 \Rightarrow x>-8.5 The least integer greater than −8.5-8.5 is −8-8.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2074 · 1 mark

The slope of line which equation is 2x−4y=92x - 4y = 9 is: (a) 2 (b) 1/2 (c) -1/2 (d) 3

Answer

(b) 1/2

Rearranging 2x−4y=92x - 4y = 9 gives 4y=2x−94y = 2x - 9, so y=12x−94y = \frac{1}{2}x - \frac{9}{4}. Comparing with y=mx+cy = mx + c, the slope is m=12m = \frac{1}{2}.

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  • 2074 · 1 mark

What is the slope of horizontal line? (a) >1 (b) < 0 (c) 0 (d) 1

Answer

(c) 0

A horizontal line has no vertical rise, so its slope m=ΔyΔx=0Δx=0m = \frac{\Delta y}{\Delta x} = \frac{0}{\Delta x} = 0.

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  • 2074 · 1 mark

The difference between 3/5 of 80 and 30% of 80 is: (a) 20 (b) 14 (c) 15 (d) 24

Answer

(d) 24

35\frac{3}{5} of 80 = 48 and 30% of 80 = 24, so the difference is 48−24=2448 - 24 = 24.

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  • 2074 · 1 mark

Gautam spent Rs. 40/-, which is 5% of his daily wage, then his total daily wage is: (a) Rs.400/- (b) Rs.600/- (c) Rs.800/- (d) Rs. 1000/-

Answer

(c) Rs.800/-

Since 5% of his daily wage is Rs. 40, his total daily wage is 400.05=Rs. 800\frac{40}{0.05} = \text{Rs. } 800.

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  • 2074 · 1 mark

If 1254376 represents the CENTURY, then what represents 735? (a) NUT (b) RUT (c) RUN (d) YET

Answer

(c) RUN

From the code: C=1, E=2, N=5, T=4, U=3, R=7, Y=6C=1,\ E=2,\ N=5,\ T=4,\ U=3,\ R=7,\ Y=6.
So 735=R U N735 = R\ U\ N = RUN.

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  • 2074 · 1 mark

Find the missing value in (27695143?)\begin{pmatrix} 2 & 7 & 6 \\ 9 & 5 & 1 \\ 4 & 3 & ? \end{pmatrix}. (a) 5 (b) 8 (c) 7 (d) 9

Answer

(b) 8

Each row and each column sums to 15.
So, 4+3+?=15⇒?=84 + 3 + ? = 15 \Rightarrow ? = 8.

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  • 2074 · 1 mark

There are 48 students in a computer class. If number of boys are twice than girls, then how many girls are there? (a) 16 (b) 18 (c) 32 (d) 28

Answer

(a) 16

Let the number of girls be xx. Then boys =2x=2x. So x+2x=48⇒3x=48⇒x=16x+2x=48 \Rightarrow 3x=48 \Rightarrow x=16.

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  • 2074 · 1 mark

Find the number x, which is equal to (80% of x) plus 5. (a) 20 (b) 30 (c) 40 (d) 25

Answer

(d) 25

Let the number be xx. Then x=80%x = 80\% of x+5=0.8x+5x + 5 = 0.8x + 5.
So 0.2x=50.2x = 5, giving x=25x = 25.

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  • 2074 · 1 mark

If the age of five girls are 15, 16, 17, 18, 19 respectively then what is the average age of girls? (a) 15 (b) 17 (c) 18 (d) 19

Answer

(b) 17

Average age =15+16+17+18+195=855=17=\dfrac{15+16+17+18+19}{5}=\dfrac{85}{5}=17 years.

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  • 2074 · 1 mark

How many triangles in this figure? (a) 6 (b) 7 (c) 8 (d) 9

Answer

(c) 8

The figure is a square with both diagonals drawn. The two diagonals cut it into 4 small triangles (the four corner regions). Joining each pair of adjacent small triangles across a side of the square gives 4 more triangles (the four half-square triangles). So the total is 4+4=84 + 4 = 8.

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  • 2074 · 1 mark

What is the value of cos 60° ? (a) 1 (b) 12\frac{1}{2} (c) 0 (d) 32\frac{\sqrt{3}}{2}

Answer

(b) 12\frac{1}{2}

From the standard trigonometric values, cos⁡60∘=12\cos 60^\circ = \frac{1}{2}.

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  • 2074 · 1 mark

Find the value of x in series 1, 1, 2, 3, 5, 8, 13, x. (a) 21 (b) 22 (c) 19 (d) 23

Answer

(a) 21

This is the Fibonacci series, where each term is the sum of the two terms before it: 8+13=218 + 13 = 21. So x=21x = 21.

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  • 2074 · 1 mark

If 'n' is an integer, which of the following must be even? (a) n + 1 (b) n + 2 (c) 2n + 1 (d) 2n

Answer

(d) 2n

For any integer nn, multiplying by 2 gives an even number, so 2n2n is always even. The other expressions can be odd or even depending on whether nn is odd or even.

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  • 2074 · 1 mark

The largest prime factor of 255 is: (a) 45 (b) 25 (c) 17 (d) 5

Answer

(c) 17

255=3×5×17255 = 3 \times 5 \times 17, so its prime factors are 3, 5 and 17. The largest prime factor is 17.

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  • 2074 · 1 mark

The sum of first n natural number is: (a) n(n+1)2\frac{n(n+1)}{2} (b) n(n+1)(2n+1)2\frac{n(n+1)(2n+1)}{2} (c) (n+1)22\frac{(n+1)^2}{2} (d) none of these

Answer

(a) n(n+1)2\frac{n(n+1)}{2}

The sum of the first nn natural numbers is 1+2+⋯+n=n(n+1)21+2+\cdots+n=\frac{n(n+1)}{2}.

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  • 2074 · 1 mark

The root of the equation 3x2−8x+16=03x^2 - 8x + 16 = 0 are (a) real & equal (b) real & unequal (c) imaginary & unequal (d) none of these

Answer

(c) imaginary & unequal

Discriminant D=b2−4ac=(−8)2−4(3)(16)=64−192=−128<0D = b^2 - 4ac = (-8)^2 - 4(3)(16) = 64 - 192 = -128 < 0, so the roots are imaginary (complex conjugates) and unequal.

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  • 2074 · 1 mark

If x + y = 12 and x - y = 6 then, the value of x2−y2x^2 - y^2 is: (a) 18 (b) 36 (c) 60 (d) 72

Answer

(d) 72

Using the identity x2−y2=(x+y)(x−y)x^2-y^2=(x+y)(x-y): x2−y2=12×6=72x^2-y^2=12\times 6=72

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  • 2074 · 1 mark

If x - 5 = 2, then the value of x + 12 is: (a) 15 (b) 17 (c) 19 (d) 18

Answer

(c) 19

Since x−5=2x - 5 = 2, we get x=7x = 7, so x+12=7+12=19x + 12 = 7 + 12 = 19.

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  • 2074 · 1 mark

The value when simplified 64−635\frac{6^4 - 6^3}{5} is: (a) 1/5 (b) 63 (c) 6/5 (d) 64

Answer

(b) 636^3 (the printed "63" is 636^3 with its superscript lost), which equals 216216.

64−635=63(6−1)5=63⋅55=63=216\frac{6^4-6^3}{5}=\frac{6^3(6-1)}{5}=\frac{6^3\cdot 5}{5}=6^3=216

Read literally, 6363 is not the value, so option (b) is the intended choice only as 636^3.

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  • 2074 · 1 mark

If 4/a + 4/a + 4/a + 4/a = 16 then, 4a is: (a) 4 (b) 8 (c) 12 (d) 16

Answer

(a) 4

Since (\frac{4}{a}+\frac{4}{a}+\frac{4}{a}+\frac{4}{a}=\frac{16}{a}=16), we get (a=1). Hence (4a=4).

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  • 2074 · 1 mark

The slope of line xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 is: (a) −(ab)-\left(\frac{a}{b}\right) (b) −(ba)-\left(\frac{b}{a}\right) (c) ab (d) −(1ab)-\left(\frac{1}{ab}\right)

Answer

(b) −(ba)-\left(\frac{b}{a}\right)

Rearranging xa+yb=1\frac{x}{a}+\frac{y}{b}=1 gives y=b−baxy=b-\frac{b}{a}x, so the coefficient of xx is the slope: −ba-\frac{b}{a}.

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  • 2074 · 1 mark

If x = 4y, what percent of 2x is 2y? (a) 20% (b) 40% (c) 30% (d) 25%

Answer

(d) 25%

Since x=4yx=4y, we have 2y2x×100=yx×100=y4y×100=25%\dfrac{2y}{2x}\times 100=\dfrac{y}{x}\times 100=\dfrac{y}{4y}\times 100=25\%.

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  • 2074 · 1 mark

If 3 bananas cost 50 cents, how many bananas can be bought for 20 dollars? (a) 120 (b) 115 (c) 110 (d) 130

Answer

(a) 120

20 dollars = 2000 cents. Since 50 cents buys 3 bananas, 2000 cents buys (2000÷50)×3=40×3=120(2000 \div 50) \times 3 = 40 \times 3 = 120 bananas.

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  • 2074 · 1 mark

If 5:7 = 15:x, then the value of x is: (a) 35 (b) 21 (c) 27 (d) 18

Answer

(b) 21

Since 5:7=15:x5:7 = 15:x, we have 57=15x\frac{5}{7}=\frac{15}{x}, so 5x=1055x=105 and x=21x=21.

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  • 2074 · 1 mark

By selling 150 apples, the seller gains the selling price of 30 apples, then gain percentage is: (a) 25% (b) 30% (c) 12% (d) 20%

Answer

(a) 25%

Let the selling price of one apple be Rs 1.
Total SP of 150 apples = Rs 150.
Gain = SP of 30 apples = Rs 30.
So total CP = 150 − 30 = Rs 120.
Gain % = (30/120) × 100 = 25%.

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  • 2074 · 1 mark

A vendor purchases lemons at Rs. 5/- per lemon, at what price vendor will sell lemon to gain 20% profit? (a) Rs. 4/- (b) Rs. 5/- (c) Rs. 6/- (d) Rs. 7/-

Answer

(c) Rs. 6/-

Cost price = Rs. 5, profit = 20%, so selling price = 5×120100=Rs. 65 \times \frac{120}{100} = \text{Rs. } 6.

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  • 2074 · 1 mark

What is the population doubling time if population growth rate is 2% per annum? (a) 50yrs (b) 30yrs (c) 40yrs (d) none of these

Answer

(d) none of these

Using the rule of 70, doubling time =70growth rate=702=35= \dfrac{70}{\text{growth rate}} = \dfrac{70}{2} = 35 years. (The exact value is ln⁡20.02≈34.7\dfrac{\ln 2}{0.02} \approx 34.7 years.) Since 35 years is not among the given options, the answer is "none of these".

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  • 2074 · 1 mark

If log⁡a81=4\log_a 81 = 4, then the value of 'a' is: (a) 4 (b) 3 (c) 5 (d) none of these

Answer

(b) 3

Since log⁡a81=4\log_a 81 = 4, we have a4=81=34a^4 = 81 = 3^4, so a=3a = 3.

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  • 2074 · 1 mark

The value of 1872\frac{\sqrt{18}}{\sqrt{72}} is: (a) a rational number (b) an irrational number (c) an imaginary number (d) none of these

Answer

(a) a rational number

1872=1872=14=12\frac{\sqrt{18}}{\sqrt{72}}=\sqrt{\frac{18}{72}}=\sqrt{\frac14}=\frac12

Since 12\frac12 is a rational number, the value is rational.

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  • 2074 · 1 mark

If 5/7 of a number is 1025, then 3/7 of number is: (a) 735 (b) 430 (c) 615 (d) 560

Answer

(c) 615

Let the number be xx. Then 57x=1025\frac{5}{7}x=1025, so x=1025×75=1435x=1025\times\frac{7}{5}=1435. Hence 37x=1435×37=615\frac{3}{7}x=1435\times\frac{3}{7}=615.

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  • 2074 · 1 mark

The number of seconds in 1131\frac{1}{3} hours is: (a) 4800 (b) 4700 (c) 4900 (d) 5000

Answer

(a) 4800

1131\frac{1}{3} hours =43×3600=4800=\frac{4}{3}\times 3600 = 4800 seconds.

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  • 2074 · 1 mark

The 4m wide carpet is used for carpeting a room of 8m long and 3m wide, then what is the length of carpet? (a) 5m (b) 6m (c) 2m (d) 3m

Answer

(b) 6m

Room area =8×3=24 m2= 8 \times 3 = 24\text{ m}^2.
Carpet length =Areawidth=244=6 m= \dfrac{\text{Area}}{\text{width}} = \dfrac{24}{4} = 6\text{ m}.

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  • 2074 · 1 mark

Hari ranks seventh from the top and twenty sixth from the bottom in a class. Then the total number of students in a class are: (a) 36 (b) 35 (c) 31 (d) 32

Answer

(d) 32

Total students = rank from top + rank from bottom − 1 = 7 + 26 − 1 = 32.

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  • 2074 · 1 mark

If three girls write 3 pages in 3 minutes, in how many minutes can one girl write one page? (a) 4 min (b) 5 min (c) 3 min (d) 6 min

Answer

(c) 3 min

Three girls write 3 pages in 3 minutes, so each girl writes 1 page in those same 3 minutes. Hence one girl writes one page in 3 minutes.

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  • 2019

The total surface area of a closed right circular cylinder of radius 3.5 m and height 7 m is (a) 77 m² (b) 154 m² (c) 231 m² (d) 308 m²

Answer

(c) 231 m²

Total surface area of a closed cylinder is
A=2πr(r+h)=2×227×3.5×(3.5+7)=231 m2A = 2\pi r(r+h) = 2 \times \frac{22}{7} \times 3.5 \times (3.5+7) = 231\ \text{m}^2

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  • 2019

If volume of a cube is 1728 m³ then its surface area is (a) 864 m² (b) 846 m² (c) 1444 m² (d) 72 m²

Answer

(a) 864 m²

Volume of cube =a3=1728= a^3 = 1728, so a=17283=12a = \sqrt[3]{1728} = 12 m.

Surface area =6a2=6×122=6×144=864= 6a^2 = 6 \times 12^2 = 6 \times 144 = 864 m².

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  • 2019

If f(x) = 4x - 2, then f(x - 1) equals (a) 4x² - 6x + 2 (b) 4x² + 2x + 2 (c) 4x - 6 (d) 4x - 2

Answer

(c) 4x - 6

Substitute x−1x-1 for xx:
f(x−1)=4(x−1)−2=4x−4−2=4x−6f(x-1)=4(x-1)-2=4x-4-2=4x-6.

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  • 2019

If 3x−1=1273^{x-1} = \frac{1}{27} then value of x is (a) -10 (b) -8 (c) -6 (d) -2

Answer

(d) -2

Since 127=3−3\frac{1}{27} = 3^{-3}, we get
3x−1=3−33^{x-1} = 3^{-3} So x−1=−3⇒x=−2x - 1 = -3 \Rightarrow x = -2.

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  • 2019

If cos⁡60∘=12\cos 60^\circ = \frac{1}{2}, then the value of cos⁡300∘\cos 300^\circ is (a) 32\frac{\sqrt{3}}{2} (b) −12-\frac{1}{2} (c) −32-\frac{\sqrt{3}}{2} (d) 12\frac{1}{2}

Answer

(d) 12\frac{1}{2}

Since 300∘=360∘−60∘300^\circ = 360^\circ - 60^\circ, we have
cos⁡300∘=cos⁡(360∘−60∘)=cos⁡60∘=12.\cos 300^\circ = \cos(360^\circ - 60^\circ) = \cos 60^\circ = \frac{1}{2}.

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  • 2019

The zeroes of quadratic polynomial x2+7x+12x^2 + 7x + 12 are (a) -2, -5 (b) -3, -4 (c) 2, 5 (d) 3, 4

Answer

(b) -3, -4

Since x2+7x+12=(x+3)(x+4)x^2+7x+12=(x+3)(x+4), the zeroes are x=−3x=-3 and x=−4x=-4.

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  • 2019

The lines pair 2x + 3y = 3 and x + 2y = 1 are (a) coincide (b) perpendicular (c) parallel (d) intersect at a point

Answer

(d) intersect at a point

The slopes are −23-\frac{2}{3} and −12-\frac{1}{2}, which are neither equal nor negative reciprocals. Solving gives x=3, y=−1x=3,\ y=-1, so the lines intersect at the single point (3,−1)(3,-1).

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  • 2019

Slope of a line perpendicular to the line 20x - 2y = 6 is (a) -10 (b) −110-\frac{1}{10} (c) 10 (d) 110\frac{1}{10}

Answer

(b) −110-\frac{1}{10}

The given line is 20x−2y=620x-2y=6, i.e. y=10x−3y=10x-3, so its slope is 1010. A line perpendicular to it has slope −110-\frac{1}{10}.

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  • 2019

In given triangle ABC if side BC is extended to point D with ∠A=x\angle A = x, ∠B=2x+15\angle B = 2x + 15 and ∠ACD=5x+5\angle ACD = 5x + 5, then ∠B\angle B is (a) 5 (b) 20 (c) 25 (d) 55

Answer

(c) 25

Since (BC) is extended to (D), (\angle ACD) is the exterior angle at (C).

[ \angle ACD = \angle A + \angle B ]

[ 5x+5 = x + (2x+15) ]

[ 5x+5 = 3x+15 ]

[ 2x=10 \Rightarrow x=5 ]

So,

[ \angle B = 2x+15 = 2(5)+15 = 25^\circ ]

Hence, (\angle B = 25^\circ).

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  • 2019

If height and diameter of a cylinder are 15cm and 12 cm respectively then its volume is (a) 180 π cm³ (b) 540 π cm³ (c) 675 π cm³ (d) 2,160 π cm³

Answer

(b) 540 π cm³

Diameter = 12 cm, so radius r=6r = 6 cm. Volume of a cylinder =πr2h=π×62×15=540π= \pi r^2 h = \pi \times 6^2 \times 15 = 540\pi cm³.

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  • 2019

What is the perimeter of a square whose diagonal is 323\sqrt{2}. (a) 18 (b) 12 (c) 9 (d) 6

Answer

(b) 12

For a square, diagonal =s2= s\sqrt{2}. Given s2=32s\sqrt{2}=3\sqrt{2}, so side s=3s=3. Perimeter =4s=4×3=12=4s=4\times3=12.

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  • 2019

The 5th term of the sequence an=2n+1a_n = 2n + 1 is (a) 9 (b) 11 (c) 13 (d) 15

Answer

(b) 11

For the 5th term, put n=5n=5 in an=2n+1a_n=2n+1:

a5=2(5)+1=10+1=11a_5 = 2(5)+1 = 10+1 = 11

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  • 2019

2n+12n−1\frac{2^{n+1}}{2^{n-1}} is equal to (a) n+1n−1\frac{n+1}{n-1} (b) 18\frac{1}{8} (c) −12-\frac{1}{2} (d) 8

Answer

None of the given options —
[ \frac{2^{n+1}}{2^{n-1}}=2^{(n+1)-(n-1)}=2^2=4. ] So the correct value is 4; if option (d) was misprinted as 8, it should be 4.

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  • 2019

The derivative of x3x^3 w.r.t x2x^2 is (a) 2x3\frac{2x}{3} (b) xx (c) 3x2\frac{3x}{2} (d) 32x\frac{3}{2x}

Answer

(c) 3x2\dfrac{3x}{2}

Let y=x3y=x^3 and u=x2u=x^2. Then dydu=dy/dxdu/dx=3x22x=3x2.\frac{dy}{du}=\frac{dy/dx}{du/dx}=\frac{3x^2}{2x}=\frac{3x}{2}.

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  • 2019

The value of −8×−2\sqrt{-8} \times \sqrt{-2} is (a) -4 (b) 4 (c) 4i (d) -4i

Answer

(a) -4

Using principal square roots, −8=i8=22 i\sqrt{-8}=i\sqrt{8}=2\sqrt2\,i and −2=i2\sqrt{-2}=i\sqrt2, so their product is (22 i)(2 i)=2⋅2 i2=4(−1)=−4(2\sqrt2\,i)(\sqrt2\,i)=2\cdot2\,i^2=4(-1)=-4.

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  • 2019

If U={1,2,3,4,5,6}U = \{1, 2, 3, 4, 5, 6\} and A={2,3,5}A = \{2, 3, 5\} the Aˉ\bar{A} is (a) {1,4,6}\{1, 4, 6\} (b) {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\} (c) {2,3,5}\{2, 3, 5\} (d) {1,3,5,6}\{1, 3, 5, 6\}

Answer

(a) {1,4,6}\{1, 4, 6\}

The complement Aˉ\bar{A} (or A′A') is the set of all elements of the universal set UU that are not in AA.

U={1,2,3,4,5,6},A={2,3,5}U = \{1, 2, 3, 4, 5, 6\}, \quad A = \{2, 3, 5\}

Removing the elements of AA from UU:

Aˉ=U−A={1,4,6}\bar{A} = U - A = \{1, 4, 6\}

So the correct option is (a).

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  • 2019

The opposite angles of any quadrilateral inscribed in circle are (a) tangent (b) supplementary (c) complementary (d) reflective

Answer

(b) supplementary

In a cyclic quadrilateral, each pair of opposite angles adds up to 180∘180^\circ, i.e. they are supplementary. This follows from the inscribed angle theorem: opposite angles subtend the two complementary arcs of the circle, so their sum is 12(360∘)=180∘\tfrac{1}{2}(360^\circ) = 180^\circ.

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  • 2019

If a set has 5 elements, then possible number of subsets are (a) 30 (b) 120 (c) 32 (d) 25

Answer

(c) 32

A set with (n) elements has (2^n) subsets. Here (n=5), so the number of subsets is (2^5 = 32).

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2019

2, 4, 6, 8, ............... is (a) Geometric Series (b) Harmonic Series (c) Geometric Progression (d) Arithmetic Progression

Answer

(d) Arithmetic Progression

The terms increase by a constant difference of 22 (4−2=6−4=8−6=24-2=6-4=8-6=2), which is the defining property of an arithmetic progression. A geometric progression would require a constant ratio, and a harmonic series would require the reciprocals to form an AP.

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2019

Which of the following is correct? (a) lim⁡x→axn−anx−a=nan−1\lim_{x \to a} \frac{x^n - a^n}{x - a} = na^{n-1} (b) lim⁡x→axn−anx−a=nan+1\lim_{x \to a} \frac{x^n - a^n}{x - a} = na^{n+1} (c) lim⁡x→axn−anx−a=nxn−1\lim_{x \to a} \frac{x^n - a^n}{x - a} = nx^{n-1} (d) lim⁡x→axn−anx−a=nan−1\lim_{x \to a} \frac{x^n - a^n}{x - a} = na^{n-1}

Answer

(a) lim⁡x→axn−anx−a=nan−1\lim_{x \to a} \dfrac{x^n - a^n}{x - a} = na^{n-1}

Why: Factor the numerator:

xn−an=(x−a)(xn−1+xn−2a+xn−3a2+⋯+an−1)x^n - a^n = (x-a)\left(x^{n-1} + x^{n-2}a + x^{n-3}a^2 + \cdots + a^{n-1}\right)

So

lim⁡x→axn−anx−a=lim⁡x→a(xn−1+xn−2a+⋯+an−1)\lim_{x \to a} \frac{x^n - a^n}{x - a} = \lim_{x \to a}\left(x^{n-1} + x^{n-2}a + \cdots + a^{n-1}\right)

Putting x=ax = a, each of the nn terms equals an−1a^{n-1}, giving n an−1n\,a^{n-1}.

Note: options (a) and (d) are written identically in the question, so both state the correct result. The correct value is n an−1n\,a^{n-1} (option (b) is wrong because the power is n−1n-1, not n+1n+1; option (c) is wrong because the limit is evaluated at x=ax=a, so the answer must contain aa, not xx).

Answer checked by Claude Haiku · Oct 21, 2026

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  • 2075 · 1 mark

A number is divided by 10 gives a remainder 7. If the same number is divided by 5, then what will be the remainder? (a) 1 (b) 2 (c) 3 (d) 4

Answer

(b) 2

Write the number as = 10k + 7.Since0k. Since 0k is divisible by 5, the remainder on division by 5 is the remainder of 7 divided by 5, which is 2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Which one of the following value of 'n' gives the negative result on n2−15n^2-15? (a) 7 (b) 5 (c) 3 (d) 4

Answer

(c) 3

We need ^2 < 15.For=3. For =3, -15=-6,whichisnegative.For4,5and7theresultsare, which is negative. For 4, 5 and 7 the results are , 0and4 and 4, all positive.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If 'n' is an integer, then which one of the following expression must be even? (a) n(n+1)n(n+1) (b) n2+1n^2+1 (c) n(n+2)n(n+2) (d) n(n+4)n(n+4)

Answer

(a) (n+1)$

The product of two consecutive integers always contains one even factor, so it is always even. In the others, an odd $ makes both factors odd (or the sum odd), so they need not be even.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If you save 1 paisa today, 2 paisa next day, 4 paisa the succeeding day and so on, then what is the total saving on the week? (a) 127 paisa (b) 64 paisa (c) 256 paisa (d) 128 paisa

Answer

(a) 127 paisa

The savings 1, 2, 4, ... form a GP with =1,=2, =2, =7$.

6250S_7=\frac{2^7-1}{2-1}=1276250

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the value of ∑n=1010(−1)n\sum_{n=10}^{10}(-1)^n? (a) 0 (b) -1 (c) 1 (d) 10

Answer

(c) 1

The sum has a single term, n=10n=10, so it equals (−1)10=1(-1)^{10}=1.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If 6 is subtracted from the cube of a number and the result is 21, then what is the value of that number? (a) 2 (b) 3 (c) 4 (d) 5

Answer

(b) 3

^3-6=21gives3=27 gives ^3=27, so =3$.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

The total of ages of A and B is 3:5, if B is 8 years elder to A, then what is the age of the A? (a) 12 yrs. (b) 15 yrs. (c) 18 yrs. (d) 21 yrs.

Answer

(a) 12 yrs.

The ratio of the ages is :B=3:5.Thedifferenceof2partsis8years,soonepartis4years,and=3×4=12. The difference of 2 parts is 8 years, so one part is 4 years, and =3\times4=12 years.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If the root of the equation x2−6x+c=0x^2-6x+c=0 is 3, then what is the value of c? (a) 3 (b) 6 (c) 8 (d) 9

Answer

(d) 9

Substitute =3:−18+c=0: -18+c=0, so =9$.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Which one of the following is true for the roots of the equation x2−8x+16=0x^2-8x+16=0? (a) Imaginary & unequal (b) Rational & unequal (c) real & equal (d) real & unequal

Answer

(c) real & equal

The discriminant is =(-8)^2-4(1)(16)=64-64=0,sotherootsarerealandequal.Indeed2−8x+16=(x−4)2, so the roots are real and equal. Indeed ^2-8x+16=(x-4)^2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If the matrix is of order 5×35\times3, then how many elements will be single column? (a) 5 (b) 3 (c) 4 (d) 15

Answer

(a) 5

A \times3$ matrix has 5 rows and 3 columns, so each column has 5 elements.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If x−5=1x-5=1, then what is the value of x+7x+7? (a) 5 (b) 7 (c) 8 (d) 13

Answer

(d) 13

-5=1gives=6 gives =6, so +7=13$.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If 5x+13=315x+13=31, what is the value of (5x+31)\sqrt{(5x+31)}? (a) 5 (b) 6 (c) 7 (d) 8

Answer

(c) 7

x+13=31givesx=18 gives x=18. Then x+31=49andand\sqrt{49}=7$.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the correct value of 54−534\frac{5^4-5^3}{4}? (a) 535^3 (b) 15\frac15 (c) 545^4 (d) 54\frac54

Answer

(a) ^3$

6250\frac{5^4-5^3}{4}=\frac{5^3(5-1)}{4}=\frac{5^3\cdot4}{4}=5^36250

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If ax=ba^x=b, by=cb^y=c and cz=ac^z=a, then what is the value of xyz? (a) c (b) a (c) b (d) 1

Answer

(d) 1

Substituting, =c^z=(b^y)^z=((a^x)^y)^z=a^{xyz}.Hence=1. Hence =1.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If 6p+6q=366p+6q=36, then what is the average value of a and b? (a) 2 (b) 3 (c) 4 (d) 5

Answer

(b) 3

Dividing p+6q=36by6gives+q=6 by 6 gives +q=6, so the average of the two quantities is 62=3\frac{6}{2}=3.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If p+q=rp+q=r, then what is the average value of p, q and r? (a) r3\frac r3 (b) p+q3\frac{p+q}{3} (c) 2r3\frac{2r}{3} (d) r2\frac r2

Answer

(c) 2r3\frac{2r}{3}

6250\text{Average}=\frac{p+q+r}{3}=\frac{r+r}{3}=\frac{2r}{3}6250

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the slope of the line whose equation is 2x−4y=92x-4y=9? (a) 1 (b) 12\frac12 (c) 2 (d) 3

Answer

(b) 12\frac12

Rewrite as =\frac{2x-9}{4}=\frac12x-\frac94.Theslopeis. The slope is \frac12(orhmtBcab=24 (or hmtBc\frac{a}{b}=\frac{2}{4}).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Which one of the following is correct for the acute angle of right angled triangle? (a) Complementary (b) supplementary (c) Adjacent (d) equal

Answer

(a) Complementary

The angles of a triangle sum to 80^\circandtherightangleis0∘ and the right angle is 0^\circ, so the two acute angles add up to 0^\circ$, which makes them complementary.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

There are 60 students in a class. If 60% of them are girls, then how many boys in the class? (a) 24 (b) 36 (c) 18 (d) 40

Answer

(a) 24

Boys are 00%-60%=40%oftheclass,and/bin/bash.4×60=24 of the class, and /bin/bash.4\times60=24.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Last year Hari was 4 feet tall, and this year he is 5 feet tall. What is the percent increase of his height? (a) 10% (b) 15% (c) 20% (d) 25%

Answer

(d) 25%

6250\frac{5-4}{4}\times100%=25%6250

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the difference between 35\frac35 of 80 and 30% of 80? (a) 12 (b) 18 (c) 24 (d) 20

Answer

(c) 24

35×80=48\frac35\times80=48 and 30%30\% of 80=2480=24, so the difference is 48−24=2448-24=24.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

The cost of 6 pens is equal to the cost of the 10 pencils. If the cost of 4 pencils is Rs. 120, then what is the cost of 4 pens? (a) 100 (b) 200 (c) 300 (d) 400

Answer

(b) 200

4 pencils cost Rs 120, so 1 pencil costs Rs 30 and 10 pencils cost Rs 300. This equals the cost of 6 pens, so 1 pen costs Rs 50 and 4 pens cost Rs 200.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Ganga can read 48 pages per hour. At this rate, how many pages she can read in 80 minutes? (a) 60 (b) 72 (c) 48 (d) 64

Answer

(d) 64

80 minutes =43=\frac43 hour, so pages read =48×43=64=48\times\frac43=64.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If 5:7=15:x5:7=15:x, then what is the value of x? (a) 18 (b) 21 (c) 24 (d) 35

Answer

(b) 21

57=15x\frac57=\frac{15}{x} gives x=7×155=21x=\frac{7\times15}{5}=21.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If cost price of 8 pens and selling price of 10 pens is equal, then what is loss percentage? (a) 20% (b) 15% (c) 10% (d) 25%

Answer

(a) 20%

Let each pen cost Rs 1 to buy. Then the cost of 10 pens is Rs 10, but they are sold for the cost price of 8 pens, Rs 8. Loss =2=2, so loss %=210×100=20%\%=\frac{2}{10}\times100=20\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

If the 20% discount is given on computer book costing Rs. 300, then what will be selling price? (a) Rs. 240 (b) Rs. 220 (c) Rs. 260 (d) Rs. 250

Answer

(a) Rs 240

Discount =20%=20\% of 300 == Rs 60, so selling price =300−60==300-60= Rs 240.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

A watch is bought at Rs. 250 and sold at Rs. 300, then what is the profit percentage? (a) 10% (b) 15% (c) 20% (d) 25%

Answer

(c) 20%

Profit =300−250==300-250= Rs 50, so profit %=50250×100=20%\%=\frac{50}{250}\times100=20\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the population doubling time if the population growth rate is 2% per anum? (a) 60 yrs. (b) 50 yrs. (c) 40 yrs. (d) 30 yrs.

Answer

(b) 50 yrs.

Using simple growth, the population doubles when growth equals 100% of the original, so t=1002=50t=\frac{100}{2}=50 years.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the minimum value of n(P∩Q)n(P\cap Q)? When n(U)=100n(U)=100, n(P)=70n(P)=70, and n(Q)=45n(Q)=45? (a) 15 (b) 55 (c) 30 (d) 45

Answer

(a) 15

n(P∪Q)≤100n(P\cup Q)\le100, so n(P∩Q)=n(P)+n(Q)−n(P∪Q)≥70+45−100=15n(P\cap Q)=n(P)+n(Q)-n(P\cup Q)\ge70+45-100=15. The minimum is 15.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Which one of the following is true for prime number? (a) no factors (b) only one factor (c) only two factors (d) more than two factors

Answer

(c) only two factors

A prime number has exactly two factors, 1 and itself.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

Which one of the following interval notation is correct for {x:5≤x≤15}\{x: 5\leq x\leq15\}? (a) [5,∞][5,\infty] (b) [∞,15][\infty,15] (c) [6,14][6,14] (d) [5,15][5,15]

Answer

(d) [5,15][5,15]

Both end points are included (≤\le), so the closed interval [5,15][5,15] is used.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the value of 'x' when it is multiplied by 6 and added to 3 times its own number gives 63? (a) 6 (b) 7 (c) 8 (d) 9

Answer

(b) 7

6x+3x=63⇒9x=63⇒x=76x+3x=63\Rightarrow 9x=63\Rightarrow x=7.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the value of (5+5)2\left(\sqrt5+\sqrt5\right)^2? (a) 20 (b) 25 (c) 10 (d) 60

Answer

(a) 20

(5+5)2=(25)2=4×5=20(\sqrt5+\sqrt5)^2=(2\sqrt5)^2=4\times5=20.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the number of seconds in 1131\frac13 hour? (a) 1200 sec (b) 2400 sec (c) 3600 sec (d) 4800 sec

Answer

(d) 4800 sec

1131\frac13 hour =80=80 minutes =80×60=4800=80\times60=4800 seconds.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

In a kilometer race A beats B by 100 meters and B beats C by 150 meters. In the same race, by how many meters does A beats C? (a) 150 m (b) 100 m (c) 250 m (d) 200 m

Answer

(c) 250 m

A beats B by 100 m and B beats C by 150 m, so in the intended (additive) reading A beats C by 100+150=250100+150=250 m.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the probability of death? (a) 1 (b) 12\frac12 (c) 0 (d) ∞\infty

Answer

(a) 1

Death is certain for every living being, so it is a sure event and its probability is 1.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the chance to give the birth by a pregnant lady on Tuesday? (a) 37\frac37 (b) 17\frac17 (c) 1 (d) 12\frac12

Answer

(b) 17\frac17

There are 7 equally likely days in a week and Tuesday is one of them, so the probability is 17\frac17.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 · 1 mark

What is the value of cos⁡0∘\cos0^\circ? (a) 12\frac12 (b) 12\frac{1}{\sqrt2} (c) 0 (d) 1

Answer

(d) 1

cos⁡0∘=1\cos0^\circ=1.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If the slope of line joining (1,2)(1,2) and (k,−5)(k,-5) is equally inclined with both the axes, then the value of kk is (a) 6 (b) -6 (c) 3 (d) -2

Answer

(b) −6-6

Equally inclined to both axes means the slope is ±1\pm1. The slope is −5−2k−1=−7k−1\frac{-5-2}{k-1}=\frac{-7}{k-1}.

For slope 11: k−1=−7k-1=-7, so k=−6k=-6 (this is the option given; slope −1-1 would give k=8k=8, which is not listed).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

What is the value of cot⁡90∘\cot90^\circ? (a) 3 (b) 12\frac12 (c) 0 (d) 1

Answer

(c) 0

cot⁡90∘=cos⁡90∘sin⁡90∘=01=0\cot 90^\circ=\frac{\cos90^\circ}{\sin90^\circ}=\frac{0}{1}=0.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

What is the probability of drawing a queen when one card is drawn randomly from a well shuffled pack of 52 cards? Find the probability of drawing a red queen? (a) 126\frac{1}{26} (b) 56\frac56 (c) 34\frac34 (d) 1536\frac{15}{36}

Answer

(a) 126\frac{1}{26}

There are 4 queens in 52 cards, so P(queen)=452=113P(\text{queen})=\frac{4}{52}=\frac1{13}. There are 2 red queens, so P(red queen)=252=126P(\text{red queen})=\frac{2}{52}=\frac{1}{26}.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If A, B, C are the subsets of a universal set U. Then A−(B∪C)A-(B\cup C) is equal to, (a) (A−B)∪(A−C)(A-B)\cup(A-C) (b) (A−B)∩(A−C)(A-B)\cap(A-C) (c) (A∩B)−(A∩C)(A\cap B)-(A\cap C) (d) (A∪B)−(A∪C)(A\cup B)-(A\cup C)

Answer

(b) (A−B)∩(A−C)(A-B)\cap(A-C)

By De Morgan's law, A−(B∪C)=A∩(B∪C)′=A∩B′∩C′=(A−B)∩(A−C)A-(B\cup C)=A\cap(B\cup C)'=A\cap B'\cap C'=(A-B)\cap(A-C).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The value of tan⁡180∘\tan180^\circ is equal to, (a) 1 (b) -1 (c) 0 (d) ∞\infty

Answer

(c) 0

tan⁡180∘=sin⁡180∘cos⁡180∘=0−1=0\tan180^\circ=\frac{\sin180^\circ}{\cos180^\circ}=\frac{0}{-1}=0.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

12+22+32+⋯+n21^2+2^2+3^2+\cdots+n^2 is equal to, (a) n(n+1)2\frac{n(n+1)}{2} (b) n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6} (c) (n(n+1)2)2\left(\frac{n(n+1)}{2}\right)^2 (d) None of the above

Answer

(b) n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}

This is the standard formula for the sum of the first nn squares.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If a matrix A=(05−6−5026−20)A=\begin{pmatrix}0&5&-6\\-5&0&2\\6&-2&0\end{pmatrix}, then matrix A is known as (a) Symmetric Matrix (b) Skew-Symmetric Matrix (c) Diagonal Matrix (d) Triangular Matrix

Answer

(b) Skew-Symmetric Matrix

Here AT=−AA^T=-A: the diagonal entries are 00 and aij=−ajia_{ij}=-a_{ji} (for example 55 and −5-5, −6-6 and 66, 22 and −2-2).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The radius of the circle x2+y2=9x^2+y^2=9 is equal to, (a) 4 (b) 3 (c) 5 (d) 9

Answer

(b) 3

x2+y2=r2x^2+y^2=r^2 with r2=9r^2=9, so r=3r=3.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If A=[1231]A=\begin{bmatrix}1&2\\3&1\end{bmatrix}, then the value of A2−2A−5IA^2-2A-5I is equal to, (a) 1 (b) -1 (c) 2 (d) 0

Answer

(d) 0

A2=[7467],2A=[2462],5I=[5005]A^2=\begin{bmatrix}7&4\\6&7\end{bmatrix},\quad 2A=\begin{bmatrix}2&4\\6&2\end{bmatrix},\quad 5I=\begin{bmatrix}5&0\\0&5\end{bmatrix}

A2−2A−5I=[0000]=0A^2-2A-5I=\begin{bmatrix}0&0\\0&0\end{bmatrix}=0

This is the null matrix, which is the option 00 (consistent with the Cayley-Hamilton theorem).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

What is the half of quarter of 400? (a) 200 (b) 100 (c) 50 (d) 90

Answer

(c) 50

A quarter of 400400 is 100100, and half of 100100 is 5050.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Half percent, written as a decimal is, (a) 0.2 (b) 0.02 (c) 0.005 (d) 0.05

Answer

(c) 0.005

Half percent is 0.5%=0.5100=0.0050.5\%=\frac{0.5}{100}=0.005.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The true discount on Rs. 2,562 due 4 months hence is Rs. 122. The rate percent is: (a) 12% (b) 13% (c) 14% (d) 15%

Answer

(d) 15%

Present worth =2562−122=Rs 2440=2562-122=\text{Rs }2440. Using TD=PW×r×t100TD=\frac{PW\times r\times t}{100} with t=13t=\frac13 year:

122=2440×r100×3⇒r=122×3002440=15%122=\frac{2440\times r}{100\times3}\Rightarrow r=\frac{122\times300}{2440}=15\%

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  • 2076 · 1 mark

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is: (a) 40% (b) 42% (c) 44% (d) 46%

Answer

(c) 44%

New area =1.2×1.2=1.44=1.2\times1.2=1.44 times the old area, so the increase is 44%44\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

AB and CD bisect each other at O. If AD = 6 cm, BC is: (a) 5.9 cm (b) 6 cm (c) 4.8 cm (d) 7 cm

Answer

(b) 6 cm

Since the diagonals bisect each other at OO, OA=OBOA=OB and OD=OCOD=OC, and the vertical angles are equal, so △AOD≅△BOC\triangle AOD\cong\triangle BOC (SAS). Hence BC=AD=6BC=AD=6 cm.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is: (a) 2 (b) 3 (c) 4 (d) 8

Answer

(a) 2

Amount =30000+4347=34347=30000+4347=34347.

(1.07)n=3434730000=1.1449=(1.07)2⇒n=2 years\left(1.07\right)^n=\frac{34347}{30000}=1.1449=(1.07)^2\Rightarrow n=2\text{ years}

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If a man were to sell his chair for Rs. 720, he would lose 25%. To gain 25%, he would sell it for: (a) Rs. 1,200 (b) Rs. 1,000 (c) Rs. 960 (d) Rs. 900

Answer

(a) Rs. 1,200

Cost price =7200.75=Rs 960=\frac{720}{0.75}=\text{Rs }960. To gain 25%25\%: 960×1.25=Rs 1200960\times1.25=\text{Rs }1200.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Find the percentage gain or loss when the dot pens bought for Rs. 96 per dozen were sold at the rate of 10 for Rs. 90? (a) 13% (b) 20% (c) 4% (d) 12.5%

Answer

(d) 12.5%

Cost per pen =9612=Rs 8=\frac{96}{12}=\text{Rs }8. Selling price per pen =9010=Rs 9=\frac{90}{10}=\text{Rs }9.

Gain%=9−88×100=12.5%\text{Gain}\%=\frac{9-8}{8}\times100=12.5\%

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

What is the value of cos⁡230∘−sin⁡230∘\cos^230^\circ-\sin^230^\circ? (a) 12\frac12 (b) 32\frac{\sqrt3}{2} (c) 13\frac{1}{\sqrt3} (d) −12-\frac12

Answer

(a) 12\frac12

cos⁡2θ−sin⁡2θ=cos⁡2θ\cos^2\theta-\sin^2\theta=\cos2\theta, so the value is cos⁡60∘=12\cos60^\circ=\frac12.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Which one is the formula for area of equilateral triangle? (a) 34a2\frac{\sqrt3}{4}a^2 (b) 12×b×h\frac12\times b\times h (c) (s−a)(s−b)(s−c)\sqrt{(s-a)(s-b)(s-c)} (d) None of these

Answer

(a) 34a2\frac{\sqrt3}{4}a^2

This is the area of an equilateral triangle of side aa.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The commission of Rs. 5,600 at the rate of 3.5% is: (a) Rs. 196 (b) Rs. 440 (c) Rs. 360 (d) Rs. 1,000

Answer

(a) Rs. 196

5600×3.5100=Rs 1965600\times\frac{3.5}{100}=\text{Rs }196

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

What is the tax rate if original price is Rs. 2,000 and selling price is Rs. 2,400? (a) 20% (b) 17.39% (c) 35% (d) 10%

Answer

(a) 20%

Tax =2400−2000=Rs 400=2400-2000=\text{Rs }400, so the rate is 4002000×100=20%\frac{400}{2000}\times100=20\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The sum of the ages of father and his son is 52 years. Eight years ago the father was eight times as old as his son, the present age of son is, (a) 10 years (b) 20 years (c) 12 years (d) 15 years

Answer

(c) 12 years

Let the son be xx years old, so the father is 52−x52-x. Eight years ago: 52−x−8=8(x−8)52-x-8=8(x-8).

44−x=8x−64⇒9x=108⇒x=1244-x=8x-64\Rightarrow9x=108\Rightarrow x=12

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The radius of the circle x2+y2−12x−4y=9x^2+y^2-12x-4y=9 is equal to, (a) 18 (b) 7 (c) 10 (d) 2

Answer

(b) 7

Complete the squares:

(x−6)2+(y−2)2=9+36+4=49(x-6)^2+(y-2)^2=9+36+4=49

so r=7r=7.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The system of linear equation will be consistent and independent if they have, (a) exactly one solution (b) more than one solution (c) no solution (d) none of these

Answer

(a) exactly one solution

A consistent and independent system has exactly one (unique) solution; the lines intersect at a single point.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Let a and b are two numbers on the real line. If (a,b]={x:a<x≤b}(a,b]=\{x: a<x\leq b\} is known as, (a) left open interval (b) right open interval (c) closed interval (d) open interval

Answer

(a) left open interval

(a,b](a,b] excludes the left endpoint aa and includes the right endpoint bb, so it is open on the left.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Let f:R→Rf:R\to R and g:R→Rg:R\to R be defined by f(x)=2x2−3f(x)=2x^2-3, g(x)=3x+2g(x)=3x+2. Then the composite functions g∘f(x)g\circ f(x) is, (a) 9x+89x+8 (b) 2x+22x+2 (c) 2x+12x+1 (d) 6x2−76x^2-7

Answer

(d) 6x2−76x^2-7

g∘f(x)=g(f(x))=3(2x2−3)+2=6x2−9+2=6x2−7g\circ f(x)=g(f(x))=3(2x^2-3)+2=6x^2-9+2=6x^2-7

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

A square matrix A is said to be singular if its determinant is equal to, (a) 1 (b) 0 (c) -1 (d) none of these

Answer

(b) 0

A square matrix is singular when ∣A∣=0|A|=0, because it then has no inverse.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

The system of equations 4x−3y=−64x-3y=-6, −4x+2y=16-4x+2y=16 is, (a) consistent and dependent (b) inconsistent and independent (c) inconsistent and dependent (d) consistent and independent

Answer

(d) consistent and independent

Adding the equations gives −y=10-y=10, so y=−10y=-10 and x=−6+3y4=−9x=\frac{-6+3y}{4}=-9. A unique solution exists, so the system is consistent and independent.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Ratio of 2 km to 600 m should be, (a) 2:7 (b) 2:8 (c) 2:3 (d) 10:3

Answer

(d) 10:3

2 km=2000 m2\text{ km}=2000\text{ m}, so the ratio is 2000:600=10:32000:600=10:3.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

In a:b=c:da:b=c:d, then b and c are called, (a) antecedent (b) extreme (c) consequent (d) mean

Answer

(d) mean

In a:b=c:da:b=c:d, aa and dd are the extremes, and bb and cc are the means.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If b2−4ac<0b^2-4ac<0 then the roots of ax2+bx+c=0ax^2+bx+c=0 are: (a) equal (b) rational (c) irrational (d) imaginary

Answer

(d) imaginary

When the discriminant b2−4ac<0b^2-4ac<0, the square root is of a negative number, so the roots are complex (imaginary) and unequal.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

A polygon having 10 sides is called, (a) decagon (b) heptagon (c) quadrilateral (d) hexagon

Answer

(a) decagon

A polygon with 10 sides is a decagon.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Linear equation is also known as, (a) simultaneous equation (b) second degree equation (c) first degree equation (d) zero degree equation

Answer

(c) first degree equation

A linear equation has the highest power of the variable equal to 1.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Two straight lines in same plane which never meet are called, (a) angles (b) transversal lines (c) vertex (d) parallel line

Answer

(d) parallel line

Coplanar lines that never meet, however far extended, are parallel.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Degree of polynomial f(x)=ax2+2 (a≠0)f(x)=ax^2+2\ (a\neq0) (a) 2 (b) -2 (c) 1 (d) -3

Answer

(a) 2

The degree is the highest power of xx, which is 2 (since a≠0a\neq0).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If A, G, H are arithmetic, geometric and harmonic means between a and b, then A, G, H are (a) in G.P (b) in A.P (c) real numbers (d) in H.P

Answer

(a) in G.P

A=a+b2A=\frac{a+b}{2}, H=2aba+bH=\frac{2ab}{a+b}, so AH=ab=G2AH=ab=G^2. Thus AG=GH\frac{A}{G}=\frac{G}{H} and A, G, H are in G.P.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

In selling an article for Rs. 76, a shopkeeper gain 52%. The gain by selling that for Rs. 74 is (a) 45% (b) 48% (c) 49% (d) 50%

Answer

(b) 48%

CP =761.52==\frac{76}{1.52}= Rs 50. Gain at Rs 74 =74−5050×100=48%=\frac{74-50}{50}\times100=48\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Ram bought oranges at 6 for Rs. 10 and sold them at 4 for Rs. 6, find his loss percent (a) 12% (b) 8% (c) 6% (d) 10%

Answer

(d) 10%

Take 12 oranges. CP =2×10==2\times10= Rs 20, SP =3×6==3\times6= Rs 18. Loss =220×100=10%=\frac{2}{20}\times100=10\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

By giving a discount of 10% on the marked price of Rs. 1,100 of a mobile phone a dealer gains 10%, then the cost price is (a) Rs. 950 (b) Rs. 900 (c) Rs. 1,000 (d) Rs. 1,050

Answer

(b) Rs. 900

SP =1100×0.9==1100\times0.9= Rs 990. CP =9901.10==\frac{990}{1.10}= Rs 900.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

Rama purchased a table in Rs. 1,260 and due to some damage on its top, she had to sell it for Rs. 1,197, her loss percent is (a) 20% (b) 15% (c) 10% (d) 5%

Answer

(d) 5%

Loss =1260−1197==1260-1197= Rs 63. Loss percent =631260×100=5%=\frac{63}{1260}\times100=5\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

A shopkeeper purchases 11 pens for Rs. 10 and sells them at of 10 for Rs. 11, then the profit is, (a) 18% (b) 19% (c) 20% (d) 21%

Answer

(d) 21%

For 110 pens: CP =10×10==10\times10= Rs 100, SP =11×11==11\times11= Rs 121. Profit =21%=21\%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 · 1 mark

If A=(100010001)A=\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}, then A is (a) unit matrix (b) singular matrix (c) symmetric (d) all of them are true

Answer

(a) unit matrix

A is the 3×33\times3 identity (unit) matrix. It is also symmetric but is non-singular (∣A∣=1|A|=1), so "all of them are true" is false.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The slope of the line passing through (a,b)(a,b) and (1a,b)\left(\frac1a,b\right) is : (a) 0 (b) 4 (c) 3 (d) 2

Answer

(a) 0

m=b−b1a−a=0m=\frac{b-b}{\frac1a-a}=0

The two points have the same yy-coordinate, so the line is horizontal.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

If P(A∪B)=1P(A\cup B)=1, two events A and B are (a) mutually exclusive (b) equally likely events (c) exhaustive (d) dependent events

Answer

(c) exhaustive

P(A∪B)=1P(A\cup B)=1 means that at least one of AA or BB must occur, which is the definition of exhaustive events.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The set {X:X2+X+1=0,X∈R}\{X: X^2+X+1=0, X\in R\} is : (a) {1,3}\{1,\sqrt3\} (b) {−1,3}\{-1,\sqrt3\} (c) {}\{\} (d) (−1,0)(-1,0)

Answer

(c) {}\{\}

For x2+x+1=0x^2+x+1=0 the discriminant is 1−4=−3<01-4=-3<0, so there is no real root. The set is empty.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

Every rational number is also (a) natural number (b) a whole number (c) an integer number (d) a real number

Answer

(d) a real number

Every rational number is a real number. Rationals like 12\frac12 need not be natural, whole or integer.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

If f(u)=uu−1f(u)=\frac{u}{u-1}, then f(a)/f(a+1)f(a)/f(a+1) is: (a) f(−a)f(-a) (b) f(1a)f\left(\frac1a\right) (c) f(a2)f(a^2) (d) f(−aa+1)f\left(\frac{-a}{a+1}\right)

Answer

(c) f(a2)f(a^2)

f(a)=aa−1,f(a+1)=a+1af(a)=\frac{a}{a-1},\quad f(a+1)=\frac{a+1}{a}

f(a)f(a+1)=a2(a−1)(a+1)=a2a2−1=f(a2)\frac{f(a)}{f(a+1)}=\frac{a^2}{(a-1)(a+1)}=\frac{a^2}{a^2-1}=f(a^2)

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

Average of even number between 20 to 100 (a) 60 (b) 40 (c) 50 (d) 70

Answer

(c) 60

The even numbers between 20 and 100 are 22,24,…,9822,24,\dots,98, an arithmetic progression. The average is 22+982=60\frac{22+98}{2}=60.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The value of cot⁡30∘\cot30^\circ is : (a) 12\frac12 (b) 2/32/\sqrt3 (c) 3\sqrt3 (d) 1

Answer

(c) 3\sqrt3

cot⁡30∘=1tan⁡30∘=11/3=3\cot30^\circ=\frac{1}{\tan30^\circ}=\frac{1}{1/\sqrt3}=\sqrt3

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

If AB=CAB=C exists, which of the following order of matrices is possible? (a) A2×3,B3×2,C2×3A_{2\times3}, B_{3\times2}, C_{2\times3} (b) A3×2,B2×3,C2×2A_{3\times2}, B_{2\times3}, C_{2\times2} (c) A3×2,B2×3,C3×3A_{3\times2}, B_{2\times3}, C_{3\times3} (d) A2×3,B3×2,C3×3A_{2\times3}, B_{3\times2}, C_{3\times3}

Answer

(c) A3×2,B2×3,C3×3A_{3\times2}, B_{2\times3}, C_{3\times3}

The product ABAB needs columns of AA equal to rows of BB, and the result has rows of AA and columns of BB. Here (3×2)(2×3)=3×3(3\times2)(2\times3)=3\times3.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The value of ∣481632541632∣\begin{vmatrix}48&1&6\\32&5&4\\16&3&2\end{vmatrix} is: (a) 1 (b) 2 (c) 0 (d) 4

Answer

(c) 0

Expanding along the first row:

48(10−12)−1(64−64)+6(96−80)=−96−0+96=048(10-12)-1(64-64)+6(96-80)=-96-0+96=0

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

Raman salary was decreased by 50% and subsequently increased by 50%. He has a loss of : (a) 0% (b) 25% (c) 0.25% (d) 2.5%

Answer

(b) 25%

Let the salary be 100100. After a 50% decrease it is 5050, and after a 50% increase it is 7575. The loss is 2525, i.e. 25%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

If a=4ba=4b, what percent of 2a2a is 2b2b? (a) 10% (b) 20% (c) 25% (d) 26%

Answer

(c) 25%

2b2a×100=b4b×100=25%\frac{2b}{2a}\times100=\frac{b}{4b}\times100=25\%

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

What 3 percent is 250 out of 1 kg? (a) 25% (b) 35% (c) 24% (d) 30%

Answer

(a) 25%

1 kg=1000 g1\ \text{kg}=1000\ \text{g}, so

2501000×100=25%\frac{250}{1000}\times100=25\%

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The equation of the straight line passing through (2,4)(2,4) and having slope -2 is : (a) 2x+y=82x+y=8 (b) 2x−y=42x-y=4 (c) x+2y=8x+2y=8 (d) x−2y=4x-2y=4

Answer

(a) 2x+y=82x+y=8

y−4=−2(x−2)⇒y=−2x+8⇒2x+y=8y-4=-2(x-2)\Rightarrow y=-2x+8\Rightarrow 2x+y=8

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

A sum reckoned at 12% SI amounts to Rs. 2409 in 4 years, the sum is : (a) 1625 (b) 1635 (c) 1640 (d) 1652

Answer

(a) 1625

A=P(1+12×4100)=1.48PA=P\left(1+\frac{12\times4}{100}\right)=1.48P

P=24091.48≈1627.7P=\frac{2409}{1.48}\approx1627.7

The nearest option is 1625 (it gives an amount of 2405).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

Ram gains the cost price of 10 books by selling 50 books. His profit percentage is : (a) Rs 30% (b) 25% (c) 20% (d) 16%

Answer

(c) 20%

Let the cost of one book be 11. Then SP50=CP50+CP10=50+10=60SP_{50}=CP_{50}+CP_{10}=50+10=60.

Profit%=1050×100=20%\text{Profit}\%=\frac{10}{50}\times100=20\%

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

cos⁡45∘=\cos45^\circ= (a) 1 (b) 0 (c) 2\sqrt2 (d) 12\frac12

Answer

(c) 2\sqrt2 (read as 22\frac{\sqrt2}{2})

The true value is cos⁡45∘=12=22≈0.707\cos45^\circ=\frac{1}{\sqrt2}=\frac{\sqrt2}{2}\approx0.707. Among the options, this is the only one involving 2\sqrt2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The area of a triangular field whose three sides are 300, 400 and 500m (in m2m^2) is : (a) 6000 (b) 5000 (c) 400 (d) 200

Answer

(a) 6000

3002+4002=5002300^2+400^2=500^2, so it is a right triangle.

Area=12×300×400=60000 m2\text{Area}=\tfrac12\times300\times400=60000\ m^2

The value 60000 is the intended one, and option (a) is it with a digit dropped.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The number of bricks, each 4cm x 3cm x 2cm are required to construct a wall having the dimension 11cm x 96cm x 64cm is : (a) 2815 (b) 281600 (c) 218500 (d) 2185

Answer

(a) 2815 (nearest option; exact count is 2816)

Number of bricks = volume of wall / volume of one brick.

11×96×644×3×2=6758424=2816\frac{11\times96\times64}{4\times3\times2}=\frac{67584}{24}=2816

The given option closest to this is 2815.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The value of sec⁡60∘\sec60^\circ is : (a) 12\frac12 (b) 32\frac{\sqrt3}{2} (c) 2 (d) 13\frac{1}{\sqrt3}

Answer

(c) 2

sec⁡60∘=1cos⁡60∘=11/2=2\sec60^\circ=\frac{1}{\cos60^\circ}=\frac{1}{1/2}=2

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

The ages of mother and her daughter are 30 years and 14 years respectively. The number of years ago that the product of their age was 192 is : (a) 5 (b) 6 (c) 7 (d) 9

Answer

(b) 6

Let the ages be reduced by xx years: (30−x)(14−x)=192(30-x)(14-x)=192.

x2−44x+228=0⇒(x−6)(x−38)=0x^2-44x+228=0\Rightarrow (x-6)(x-38)=0

So x=6x=6 (38 is impossible since the daughter was not yet born).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2077 · 1 mark

A rope is 40 ft. long is cut into two pieces, if one piece is 18 ft. longer than the other . What is the length , in feet, of the shorter piece ? (a) 11 (b) 12 (c) 13 (d) 14

Answer

(a) 11

Let the shorter piece be xx ft. Then x+(x+18)=40⇒2x=22⇒x=11x+(x+18)=40\Rightarrow 2x=22\Rightarrow x=11.

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  • 2077 · 1 mark

If M=(1223)M=\begin{pmatrix}1&2\\2&3\end{pmatrix}, M2−rM−I=0M^2-rM-I=0, the value of r is : (a) -2 (b) -4 (c) 4 (d) 2

Answer

(c) 4

M2=(58813),M2−rM−I=(5−r−18−2r8−2r13−3r−1)=0M^2=\begin{pmatrix}5&8\\8&13\end{pmatrix},\quad M^2-rM-I=\begin{pmatrix}5-r-1&8-2r\\8-2r&13-3r-1\end{pmatrix}=0

Each entry gives r=4r=4.

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  • 2077 · 1 mark

If f(x)=3x+5f(x)=3x+5, then value of f(x+h)−f(x)h\frac{f(x+h)-f(x)}{h} is : (a) 2 (b) 3 (c) 4 (d) 5

Answer

(b) 3

f(x+h)−f(x)h=3(x+h)+5−3x−5h=3hh=3\frac{f(x+h)-f(x)}{h}=\frac{3(x+h)+5-3x-5}{h}=\frac{3h}{h}=3

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  • 2077 · 1 mark

The difference of two irrational number is : (a) always an irrational number (b) always a rational number (c) always a real number (d) All of above

Answer

(c) always a real number

The difference of two irrational numbers may be rational (e.g. 2−2=0\sqrt2-\sqrt2=0) or irrational (e.g. 3−2\sqrt3-\sqrt2), so (a) and (b) are false. It is always a real number.

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If p−q+r=4p-q+r=4 and p+q+r=8p+q+r=8, the value of p+q=p+q= (a) 2 (b) 4 (c) 6 (d) 8

Answer

(c) 6

Subtracting the equations gives 2q=42q=4, so q=2q=2. Adding gives 2(p+r)=122(p+r)=12, so p+r=6p+r=6. The intended value of the sum in the options is 6.

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  • 2077 · 1 mark

If a4=b5=c9\frac a4=\frac b5=\frac c9 then a+b+cc\frac{a+b+c}{c} is : (a) 4 (b) 2 (c) 7 (d) none

Answer

(b) 2

Let a=4k, b=5k, c=9ka=4k,\ b=5k,\ c=9k. Then

a+b+cc=18k9k=2\frac{a+b+c}{c}=\frac{18k}{9k}=2

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If 60% of 450=15x, the value of x is : (a) 6 (b) 18 (c) 36 (d) 72

Answer

(b) 18

60%60\% of 450=270450=270, so 15x=270⇒x=1815x=270\Rightarrow x=18.

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  • 2077 · 1 mark

The system of equation −4x+6y+2z=8-4x+6y+2z=8 and 2x−3y−z=−142x-3y-z=-14 have : (a) unique solution (b) no solution (c) infinity many solutions (d) none of these

Answer

(b) no solution

Multiplying the second equation by −2-2 gives −4x+6y+2z=28-4x+6y+2z=28, while the first says −4x+6y+2z=8-4x+6y+2z=8. The two are contradictory, so the system is inconsistent.

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  • 2077 · 1 mark

The area of rectangle field is 493 m2493\,m^2 and its perimeter is 92 meter. The length and breadth (in m) are : (a) 7,4 (b) 9,7 (c) 29,17 (d) 19,13

Answer

(c) 29, 17

l+b=46l+b=46 and lb=493lb=493. Since 29+17=4629+17=46 and 29×17=49329\times17=493, the length is 29 m and the breadth is 17 m.

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  • 2077 · 1 mark

While solving the value of x is X3−3x2+3x−1=0X^3-3x^2+3x-1=0. (a) 2 (b) 1 (c) both (d) none

Answer

(b) 1

x3−3x2+3x−1=(x−1)3=0⇒x=1x^3-3x^2+3x-1=(x-1)^3=0\Rightarrow x=1

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  • 2077 · 1 mark

The side of triangle are 3cm, 4cm and 5cm. it is : (a) a right angle triangle (b) an isosceles triangle (c) an equilateral triangle (d) none of these

Answer

(a) a right angle triangle

32+42=9+16=25=523^2+4^2=9+16=25=5^2, so the Pythagorean relation holds.

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  • 2077 · 1 mark

Which of the following represents all solutions of the inequality x2<2xx^2<2x? (a) −1<x<1-1<x<1 (b) 1<x<31<x<3 (c) 0<x<20<x<2 (d) 4<x<64<x<6

Answer

(c) 0<x<20<x<2

x2−2x<0⇒x(x−2)<0⇒0<x<2x^2-2x<0\Rightarrow x(x-2)<0\Rightarrow 0<x<2

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  • 2077 · 1 mark

If the term 2x2x, x+10x+10 and 3x+23x+2 be in AP , the value of x is (a) 7 (b) 10 (c) 6 (d) 5

Answer

(c) 6

For an AP, 2(x+10)=2x+(3x+2)2(x+10)=2x+(3x+2).

2x+20=5x+2⇒3x=18⇒x=62x+20=5x+2\Rightarrow 3x=18\Rightarrow x=6

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If tn=3n−2t_n=3n-2, the value of S5S_5 is : (a) 35 (b) 40 (c) 45 (d) 50

Answer

(a) 35

The terms are 1, 4, 7, 10, 13, so S5=52(1+13)=35S_5=\frac52(1+13)=35.

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  • 2077 · 1 mark

If Sn=1+2+3+…+n=20S_n=1+2+3+\ldots+n=20 the sum of the series Sn=13+23+33+⋯+n3S_n=1^3+2^3+3^3+\cdots+n^3 is : (a) 400 (b) 500 (c) 450 (d) 1000

Answer

(a) 400

13+23+⋯+n3=(n(n+1)2)2=(1+2+⋯+n)2=202=4001^3+2^3+\cdots+n^3=\left(\frac{n(n+1)}{2}\right)^2=(1+2+\cdots+n)^2=20^2=400

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  • 2077 · 1 mark

While selling a pen for Rs. 50, there is a loss of 5%, for what price should it be sold to gain 5%? (a) 55.26 (b) 52.63 (c) 55 (d) 56.32

Answer

(a) 55.26

Cost price =500.95=52.63=\frac{50}{0.95}=52.63.

Selling price for 5% gain =1.05×52.63=55.26=1.05\times52.63=55.26.

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  • 2077 · 1 mark

A man sold 250 chairs and had gain equal to the selling price of 50 chairs. His profit percent is: (a) 5% (b) 10% (c) 25% (d) 50%

Answer

(c) 25%

Let the selling price of one chair be ss. Total SP =250s=250s, gain =50s=50s, so cost =200s=200s.

Profit %=50s200s×100=25%\text{Profit}\,\%=\frac{50s}{200s}\times100=25\%

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A watch is bought at Rs.250 and sold at Rs. 300, the gain percent is : (a) 25% (b) 20% (c) 50% (d) none

Answer

(b) 20%

Gain %=300−250250×100=20%\text{Gain}\,\%=\frac{300-250}{250}\times100=20\%

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  • 2077 · 1 mark

The list of price of an article is 25% above the selling price and cost price is 40% below the list price, then rate of discount is : (a) 15 % (b) 20% (c) 25% (d) 40%

Answer

(b) 20%

Let the selling price be 100. List price =125=125 and cost price =0.6×125=75=0.6\times125=75.

The article is sold at 100 from a list price of 125, so

Discount %=125−100125×100=20%\text{Discount}\,\%=\frac{125-100}{125}\times100=20\%

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  • 2077 · 1 mark

If A=(n001)A=\begin{pmatrix}n&0\\0&1\end{pmatrix} and A2A^2 is identity matrix, the value of n is : (a) 1 (b) 2 (c) 0 (d) 3

Answer

(a) 1

A2=(n2001)=I⇒n2=1⇒n=±1A^2=\begin{pmatrix}n^2&0\\0&1\end{pmatrix}=I\Rightarrow n^2=1\Rightarrow n=\pm1

Of the options, n=1n=1 is listed.

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  • 2077 · 1 mark

If A=(123−4)A=\begin{pmatrix}1&2\\3&-4\end{pmatrix}, Q=(x32−1)Q=\begin{pmatrix}x&3\\2&-1\end{pmatrix}, determinant of 2p−3q2p-3q is -5, the value of x is equal to : (a) −12\frac{-1}{2} (b) 12\frac12 (c) −13\frac{-1}{3} (d) −14\frac{-1}{4}

Answer

(c) −13\frac{-1}{3} (nearest option; computed value is 13\frac13)

Taking P=AP=A:

2P−3Q=(2−3x−50−5),det⁡=−5(2−3x)=−5⇒2−3x=1⇒x=132P-3Q=\begin{pmatrix}2-3x&-5\\0&-5\end{pmatrix},\quad \det=-5(2-3x)=-5\Rightarrow 2-3x=1\Rightarrow x=\tfrac13

The nearest listed option is −13-\frac13.

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  • 2077 · 1 mark

The simple interest on Rs. 1250 for 5 years at 8% p.a is : (a) 480 (b) 1000 (c) 500 (d) 625

Answer

(c) 500

SI=PTR100=1250×5×8100=500SI=\frac{PTR}{100}=\frac{1250\times5\times8}{100}=500

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If a sum of money doubles itself in 8 years at simple interest, the rate percent per annum is : (a) 10. 5% (b) 11. 5% (c) 12. 5% (d) 13. 5%

Answer

(c) 12.5%

Interest after 8 years equals the principal: P=P×8×R100⇒R=12.5%P=\frac{P\times8\times R}{100}\Rightarrow R=12.5\%.

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  • 2077 · 1 mark

If two numbers are in the ratio 5:7 and their least common multiple is 315, their product is : (a) 2385 (b) 2538 (c) 2358 (d) 2835

Answer

(d) 2835

Let the numbers be 5k5k and 7k7k. LCM =35k=315⇒k=9=35k=315\Rightarrow k=9. The numbers are 45 and 63, and the product is 45×63=283545\times63=2835.

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If 0.75:x::5:8, then x is equal to... (a) 1.12 (b) 1.2 (c) 1.25 (d) 1.30

Answer

(b) 1.2

0.75:x::5:8⇒0.75x=58⇒x=0.75×85=1.20.75:x::5:8\Rightarrow \frac{0.75}{x}=\frac58\Rightarrow x=\frac{0.75\times8}{5}=1.2

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  • 2077 · 1 mark

A container contains 40l of milk from this container 4l of milk taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? (a) 26.34l (b) 27.36l (c) 28l (d) 29.16l

Answer

(d) 29.16l

Milk left after nn replacements: 40(1−440)3=40×(0.9)3=40×0.729=29.1640\left(1-\frac{4}{40}\right)^3 = 40\times(0.9)^3 = 40\times0.729 = 29.16 l.

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  • 2078 · 1 mark

If A and B are two subset of a universal set U. State the condition for n(A∪B)=n(A)+n(B)n(A\cup B)=n(A)+n(B) (a) If A and B are disjoint (b) If A and B are intersecting (c) A⊂BA\subset B (d) A⊃BA\supset B

Answer

(a) If A and B are disjoint

n(A∪B)=n(A)+n(B)−n(A∩B)n(A\cup B)=n(A)+n(B)-n(A\cap B), so the formula reduces to n(A)+n(B)n(A)+n(B) only when n(A∩B)=0n(A\cap B)=0, that is, when A and B are disjoint.

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  • 2078 · 1 mark

The cost of an electric item is Rs. 4,250. How much should a customer pay for it with 13% VAT? (a) 5520.50 (b) 525.5 (c) 4802.5 (d) 3697.5

Answer

(c) 4802.5

Price with VAT =4250×1.13=Rs 4802.50=4250\times1.13 = \text{Rs } 4802.50.

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  • 2078 · 1 mark

If US USD 1=NPR 115 convert NPR. 67275 dollar (a) 585 (b) 580 (c) 590 (d) 600

Answer

(a) 585

67275÷115=58567275 \div 115 = 585 dollars.

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If f(x)=2xf(x)=2x & g(x)=x+1g(x)=x+1 then fog(2)fog(2) (a) 4 (b) 6 (c) 8 (d) 10

Answer

(b) 6

fog(2)=f(g(2))=f(3)=2×3=6fog(2)=f(g(2))=f(3)=2\times3=6.

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  • 2078 · 1 mark

A man earn Rs.720 a month. If he spends 80% of it in each month, how much he will save in a year (a) Rs. 1528 (b) Rs. 1628 (c) Rs. 1728 (d) Rs. 1828

Answer

(c) Rs. 1728

Monthly saving is 20%20\% of Rs 720, which is Rs 144. Yearly saving is 144×12=Rs 1728144\times12=\text{Rs } 1728.

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  • 2078 · 1 mark

If a selling price of 12 cycle is equal to cost price of 15 cycles. find gain % (a) 20% (b) 25% (c) 30% (d) 15%

Answer

(b) 25%

Let the cost of one cycle be Rs 1. Then 12 SP=15 CP12\,SP = 15\,CP, so SP=15/12=1.25SP = 15/12 = 1.25.

Gain%=1.25−11×100=25%\text{Gain}\% = \frac{1.25-1}{1}\times100 = 25\%

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  • 2078 · 1 mark

Circumference of a circle whose area is equal to half that of rectangle 44cm by 28 cm is, (a) 84 cm (b) 86 cm (c) 88 cm (d) 90 cm

Answer

(c) 88 cm

Rectangle area =44×28=1232=44\times28=1232 cm². Circle area =616=616 cm².

πr2=616⇒r2=616×722=196⇒r=14\pi r^2=616 \Rightarrow r^2=616\times\frac{7}{22}=196 \Rightarrow r=14

Circumference =2πr=2×227×14=88=2\pi r = 2\times\frac{22}{7}\times14 = 88 cm.

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  • 2078 · 1 mark

If a tank with capacity 96m396m^3 have base are 24m224m^2 then its height is equal to the (a) 1m (b) 2m (c) 3m (d) 4m

Answer

(d) 4m

h=VA=9624=4 mh=\frac{V}{A}=\frac{96}{24}=4\text{ m}

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  • 2078 · 1 mark

If 154000cm3154000cm^3 of water is taken out from a cylindrical well of diameter 3.5m, then decrease in height in cm is equal to , (a) 8/3cm (b) 8/5cm (c) 8/7 cm (d) 1cm

Answer

(b) 8/5 cm

Radius =1.75=1.75 m =175=175 cm. Volume removed =πr2h=\pi r^2 h.

h=154000227×1752=15400096250=1.6=85 cmh=\frac{154000}{\frac{22}{7}\times175^2}=\frac{154000}{96250}=1.6=\frac{8}{5}\text{ cm}

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  • 2078 · 1 mark

If a surface area of a hemisphere is 32m3 then its radius is equal to (a) 3m (b) 4m (c) 5m (d) 6m

Answer

(b) 4m Taking the curved surface area 2πr2=32π2\pi r^2 = 32\pi gives r2=16r^2=16, so r=4r=4 m.

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  • 2078 · 1 mark

Two number are in the ratio 2:5 and their sum is 35 then the smaller number is (a) 10 (b) 12 (c) 14 (d) 16

Answer

(a) 10 Parts: 2+5=72+5=7, so the smaller number is 27×35=10\frac{2}{7}\times 35 = 10.

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The numerical value of (343)−23(343)^{-\frac23} is equal to (a) 1/49 (b) 1/7 (c) 1/25 (d) 1/29

Answer

(a) 1/49 (343)−2/3=(73)−2/3=7−2=149(343)^{-2/3}=(7^3)^{-2/3}=7^{-2}=\frac{1}{49}.

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  • 2078 · 1 mark

If 32x+1=92x−13^{2x+1}=9^{2x-1} then the value of x is equal to (a) 1/2 (b) 3/2 (c) 5/2 (d) 1

Answer

(b) 3/2 32x+1=32(2x−1)3^{2x+1}=3^{2(2x-1)}, so 2x+1=4x−22x+1=4x-2, giving 2x=32x=3 and x=32x=\frac32.

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In a single throw of a dice, find the probability of getting a number divisible by 3 is (a) 1/2 (b) 1/3 (c) 1/4 (d) 2/3

Answer

(b) 1/3 Numbers divisible by 3 on a die are 3 and 6, so P=26=13P=\frac{2}{6}=\frac13.

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  • 2078 · 1 mark

In a three -dimensional space the three axes divide the space into (a) 4 parts (b) 6 parts (c) 8 parts (d) 3 parts

Answer

(c) 8 parts The three coordinate planes (formed by the axes) divide space into 8 octants.

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  • 2078 · 1 mark

Half of the product of diagonals indicates the area of (a) parallelogram (b) rectangular (c) square (d) rhombus

Answer

(d) rhombus Area of a rhombus =12d1d2=\frac12 d_1 d_2.

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  • 2078 · 1 mark

A parallelogram having it's area 24cm224cm^2 and base 6cm then it's height is equal to , (a) 2cm (b) 3cm (c) 4 cm (d) 6 cm

Answer

(c) 4 cm Area = base × height, so h=246=4h=\frac{24}{6}=4 cm.

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  • 2078 · 1 mark

If the area of triangle 56sq.cm and the altitude 8cm then the base is , (a) 7cm (b) 8cm (c) 14 cm (d) 28cm

Answer

(c) 14 cm Area =12×b×h=\frac12 \times b \times h, so b=2×568=14b=\frac{2\times 56}{8}=14 cm.

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  • 2078 · 1 mark

If A=[3243]A=\begin{bmatrix}3&2\\4&3\end{bmatrix}, then the inverse of A is equal to (a) [3−2−43]\begin{bmatrix}3&-2\\-4&3\end{bmatrix} (b) [−324−3]\begin{bmatrix}-3&2\\4&-3\end{bmatrix} (c) [−32−43]\begin{bmatrix}-3&2\\-4&3\end{bmatrix} (d) [1001]\begin{bmatrix}1&0\\0&1\end{bmatrix}

Answer

(a) [3−2−43]\begin{bmatrix}3&-2\\-4&3\end{bmatrix} ∣A∣=9−8=1|A|=9-8=1, so A−1=11[3−2−43]A^{-1}=\frac{1}{1}\begin{bmatrix}3&-2\\-4&3\end{bmatrix}.

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  • 2078 · 1 mark

If ∣A∣=0|A|=0, then A is called (a) singular matrix (b) zero matrix (c) non-singular matrix (d) identify matrix

Answer

(a) singular matrix A square matrix with zero determinant is called singular.

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  • 2078 · 1 mark

The famous mathematicians associated with finding the sum of the natural number is, (a) Pythagoras (b) newton (c) Gauss (d) Euclid

Answer

(c) Gauss Carl Friedrich Gauss is famed for the quick method of summing the natural numbers, n(n+1)2\frac{n(n+1)}{2}.

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  • 2078 · 1 mark

Sum of the series 1+12+122+123+…1+\frac12+\frac1{2^2}+\frac1{2^3}+\ldots (a) 1 (b) 2 (c) 1.555 (d) 1.7555

Answer

(b) 2 Infinite G.P. with a=1a=1, r=12r=\frac12: S∞=a1−r=11/2=2S_\infty=\frac{a}{1-r}=\frac{1}{1/2}=2.

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  • 2078 · 1 mark

The A.M. between x−3x-3 & x+5x+5 is , (a) 2x+22x+2 (b) x−1x-1 (c) x+1x+1 (d) 2x+12x+1

Answer

(c) x+1 A.M.=(x−3)+(x+5)2=2x+22=x+1A.M.=\frac{(x-3)+(x+5)}{2}=\frac{2x+2}{2}=x+1.

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  • 2078 · 1 mark

The value of sin⁡75∘\sin75^\circ is (a) 3+122\frac{\sqrt3+1}{2\sqrt2} (b) 3−122\frac{\sqrt3-1}{2\sqrt2} (c) 3+222\frac{\sqrt3+2}{2\sqrt2} (d) 3+12\frac{\sqrt3+1}{\sqrt2}

Answer

(a) 3+122\frac{\sqrt3+1}{2\sqrt2} sin⁡75∘=sin⁡(45∘+30∘)=12⋅32+12⋅12=3+122\sin75^\circ=\sin(45^\circ+30^\circ)=\frac{1}{\sqrt2}\cdot\frac{\sqrt3}{2}+\frac{1}{\sqrt2}\cdot\frac12=\frac{\sqrt3+1}{2\sqrt2}.

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  • 2078 · 1 mark

The mean of the data 4,6,8,10,12,14 is (a) 7 (b) 8 (c) 9 (d) 10

Answer

(c) 9 Sum =54=54, number of terms =6=6, mean =546=9=\frac{54}{6}=9.

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  • 2078 · 1 mark

The angle between two straight line 2x−3y+1=02x-3y+1=0 & 3x+2y−2=03x+2y-2=0 is (a) 45∘45^\circ (b) 60∘60^\circ (c) 75∘75^\circ (d) 90∘90^\circ

Answer

(d) 90∘90^\circ Slopes are m1=23m_1=\frac23 and m2=−32m_2=-\frac32. Since m1m2=−1m_1m_2=-1, the lines are perpendicular.

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  • 2078 · 1 mark

The value of lim⁡x→asin⁡(x−a)x−a\lim_{x\to a}\frac{\sin(x-a)}{x-a} is (a) 0 (b) 1 (c) -1 (d) 1/2

Answer

(b) 1 This is the standard limit lim⁡θ→0sin⁡θθ=1\lim_{\theta\to0}\frac{\sin\theta}{\theta}=1 with θ=x−a\theta=x-a.

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  • 2078 · 1 mark

The derivatives of tan⁡x\tan x is (a) sec⁡2x\sec^2x (b) sec⁡x\sec x (c) sec⁡xtan⁡x\sec x\tan x (d) cot⁡\cot

Answer

(a) sec⁡2x\sec^2x ddxtan⁡x=sec⁡2x\frac{d}{dx}\tan x=\sec^2x.

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  • 2078 · 1 mark

The limit value of lim⁡x→3x2−9x−3\lim_{x\to3}\frac{x^2-9}{x-3} is (a) 9 (b) 0 (c) 6 (d) 1

Answer

(c) 6 x2−9x−3=x+3\frac{x^2-9}{x-3}=x+3 for x≠3x\ne3, which tends to 66 as x→3x\to3.

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Reflection of a point (−1,2)(-1,2) about the line y=xy=x is (a) (1,2)(1,2) (b) (2,1)(2,1) (c) (−2,1)(-2,1) (d) (2,−1)(2,-1)

Answer

(d) (2,−1)(2,-1) Reflection about y=xy=x swaps the coordinates: (x,y)→(y,x)(x,y)\to(y,x), so (−1,2)→(2,−1)(-1,2)\to(2,-1).

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The value of (i)101(i)^{101} is (a) ii (b) -1 (c) 1 (d) −i-i

Answer

(a) ii i101=i4×25+1=i1=ii^{101}=i^{4\times25+1}=i^1=i.

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The number of subset of a set containing n element is (a) 22n2^{2n} (b) 2n2n (c) 2n2^n (d) n2n^2

Answer

(c) 2n2^n Each of the nn elements is either in or out of a subset, giving 2n2^n subsets.

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If A=60∘A=60^\circ value of sin⁡3A\sin3A is (a) 1/2 (b) 0 (c) -1/2 (d) 3/2

Answer

(b) 0 sin⁡3A=sin⁡180∘=0\sin3A=\sin180^\circ=0.

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If equation of circle is x2+y2−4x+2y−11=0x^2+y^2-4x+2y-11=0, then it's center is (a) (−4,2)(-4,2) (b) (−2,1)(-2,1) (c) (2,−1)(2,-1) (d) (2,1)(2,1)

Answer

(c) (2,−1)(2,-1) For x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0 the centre is (−g,−f)(-g,-f). Here 2g=−42g=-4, 2f=22f=2, so g=−2g=-2, f=1f=1 and the centre is (2,−1)(2,-1).

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If an equilateral triangle has side length a then it's area is (a) 32a2\frac{\sqrt3}{2}a^2 (b) 34a2\frac{\sqrt3}{4}a^2 (c) 34a2\frac34a^2 (d) 14a2\frac14a^2

Answer

(b) 34a2\frac{\sqrt3}{4}a^2 Height is 32a\frac{\sqrt3}{2}a, so area =12⋅a⋅32a=34a2=\frac12\cdot a\cdot\frac{\sqrt3}{2}a=\frac{\sqrt3}{4}a^2.

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Exterior angle of a regular hexagon is (a) 45∘45^\circ (b) 60∘60^\circ (c) 75∘75^\circ (d) 30∘30^\circ

Answer

(b) 60∘60^\circ Exterior angle of a regular nn-gon is 360∘n=360∘6=60∘\frac{360^\circ}{n}=\frac{360^\circ}{6}=60^\circ.

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If an angle is 270∘270^\circ then it's value in grade system is (a) 100g (b) 200g (c) 300g (d) 400g

Answer

(c) 300g 100g=90∘100^g=90^\circ, so 270∘=270×109=300g270^\circ=\frac{270\times10}{9}=300^g.

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A man looks at the top of the tree which is at a distance of 1000m and makes angle of 45∘45^\circ then height of the tree is (a) 100m (b) 75m (c) 50m (d) 40m

Answer

(a) 100m tan⁡45∘=1\tan45^\circ=1, so height equals the horizontal distance to the tree. Of the options, 100 m is the intended value (distance 100 m).

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If sin⁡θ−cos⁡θ=0\sin\theta-\cos\theta=0 then the value of θ\theta is, (a) 0∘0^\circ (b) 90∘90^\circ (c) 60∘60^\circ (d) 45∘45^\circ

Answer

(d) 45∘45^\circ sin⁡θ=cos⁡θ\sin\theta=\cos\theta gives tan⁡θ=1\tan\theta=1, so θ=45∘\theta=45^\circ.

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If x>0x>0 then ∣x∣|x| is equal to (a) -x (b) x (c) 0 (d) 1

Answer

(b) x For x>0x>0, ∣x∣=x|x|=x by definition.

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The range of the function f(x)=x∣x∣f(x)=\frac{x}{|x|} is (a) {1}\{1\} (b) {1,−1}\{1,-1\} (c) {0}\{0\} (d) {−∞,∞}\{-\infty,\infty\}

Answer

(b) {1,−1}\{1,-1\} For x>0x>0, f(x)=xx=1f(x)=\frac{x}{x}=1; for x<0x<0, f(x)=x−x=−1f(x)=\frac{x}{-x}=-1. The function is undefined at 0, so the range is {1,−1}\{1,-1\}.

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For set A, (A′)′(A')' is (a) U−AU-A (b) A′A' (c) AA (d) U′U'

Answer

(c) AA The complement of the complement of a set is the set itself (double complement law).

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Geometric mean between two number 4 and 6 is (a) 6 (b) 8 (c) 10 (d) 12

Answer

(a) 6 G.M. =ab=\sqrt{ab}. The intended numbers are 4 and 9, giving 36=6\sqrt{36}=6; for exactly 4 and 6 the value would be 24≈4.9\sqrt{24}\approx4.9, which is not listed, so 6 is the nearest listed choice.

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The 6th term of the series 3,9,27,... is (a) 81 (b) 243 (c) 729 (d) 2187

Answer

(c) 729 G.P. with a=3a=3, r=3r=3: t6=3⋅35=36=729t_6=3\cdot3^5=3^6=729.

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For some integers n which of the following is odd integer (a) n (b) n+1 (c) 2n (d) 2n+1

Answer

(d) 2n+12n+1 2n2n is always even, so 2n+12n+1 is always odd for any integer nn.

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The centroid of a triangle is a point where (a) the perpendicular from vertex to opposite sides meets (b) medians meet (c) bisectors of each angle meet (d) perpendicular bisectors of each sides meet

Answer

(b) medians meet The centroid is the point of concurrence of the three medians, dividing each in the ratio 2:1.

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The set A={x:x∈N & x2+3x+2=0}A=\{x: x\in N\ \&\ x^2+3x+2=0\} is (a) Null set (b) Finite set (c) Infinite set (d) set with two elements

Answer

(a) Null set x2+3x+2=(x+1)(x+2)=0x^2+3x+2=(x+1)(x+2)=0 gives x=−1,−2x=-1,-2, neither of which is a natural number, so A=∅A=\varnothing.

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The H.C.F of the algebraic expressions a2−b2a^2-b^2 & a2+2ab+b2a^2+2ab+b^2 is (a) a+b (b) (a+b)2(a−b)(a+b)^2(a-b) (c) a-b (d) a2−b2a^2-b^2

Answer

(a) a+b a2−b2=(a+b)(a−b)a^2-b^2=(a+b)(a-b) and a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2, so the H.C.F. is a+ba+b.

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Set of natural number is (a) Finite set (b) Infinite set (c) Null set (d) Singleton set

Answer

(b) Infinite set

The natural numbers {1,2,3,…}\{1,2,3,\ldots\} never end, so the set is infinite.

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If n(A)=26n(A)=26, n(B)=32n(B)=32, then maximum value of n(A∪B)n(A\cup B) is (a) 26 (b) 58 (c) 32 (d) 6

Answer

(b) 58

n(A∪B)=n(A)+n(B)−n(A∩B)n(A\cup B)=n(A)+n(B)-n(A\cap B)

This is largest when n(A∩B)=0n(A\cap B)=0 (disjoint sets), giving 26+32=5826+32=58.

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Area of an equilateral triangle with each side 'a' is (a) 32a3\frac{\sqrt3}{2}a^3 (b) 32a2\frac{\sqrt3}{2}a^2 (c) 34a\frac{\sqrt3}{4}a (d) 34a2\frac{\sqrt3}{4}a^2

Answer

(d) 34a2\frac{\sqrt3}{4}a^2

Height of the triangle is 32a\frac{\sqrt3}{2}a, so area =12⋅a⋅32a=34a2=\frac12\cdot a\cdot\frac{\sqrt3}{2}a=\frac{\sqrt3}{4}a^2.

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  • 2022 · 1 mark

Area of triangle with 4cm, 5cm, 7cm is (a) 7.8 cm27.8\,cm^2 (b) 8.8 cm28.8\,cm^2 (c) 9.8 cm29.8\,cm^2 (d) 10.8 cm210.8\,cm^2

Answer

(c) 9.8 cm29.8\,cm^2

By Heron's formula, s=4+5+72=8s=\frac{4+5+7}{2}=8.

A=8(8−4)(8−5)(8−7)=96≈9.8 cm2A=\sqrt{8(8-4)(8-5)(8-7)}=\sqrt{96}\approx 9.8\,cm^2

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  • 2022 · 1 mark

Total surface area of a hemisphere having radius 7 cm is (a) 450 cm2450\,cm^2 (b) 460 cm2460\,cm^2 (c) 462 cm2462\,cm^2 (d) 472 cm2472\,cm^2

Answer

(c) 462 cm2462\,cm^2

Total surface area of a hemisphere =3πr2=3×227×49=462 cm2=3\pi r^2=3\times\frac{22}{7}\times 49=462\,cm^2.

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  • 2022 · 1 mark

If the volume of a cone is 3696 cm23696\,cm^2 and radius of the base is 14 cm14\,cm then height of the cone is (a) 16 cm (b) 17 cm (c) 18 cm (d) 19 cm

Answer

(c) 18 cm

V=13πr2h⇒3696=13×227×196 h=6163hV=\frac13\pi r^2h\Rightarrow 3696=\frac13\times\frac{22}{7}\times196\,h=\frac{616}{3}h

h=3696×3616=18 cmh=\frac{3696\times3}{616}=18\text{ cm}

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If 32x−9=03^{2x}-9=0 then the value of x is equal to (a) 0 (b) 1 (c) 3 (d) 9

Answer

(b) 1

32x=9=32⇒2x=2⇒x=13^{2x}=9=3^2\Rightarrow 2x=2\Rightarrow x=1.

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The value of (278)13÷(94)12\left(\frac{27}{8}\right)^{\frac13}\div\left(\frac94\right)^{\frac12} is (a) 1 (b) -1 (c) 2 (d) -2

Answer

(a) 1

(278)1/3=32\left(\frac{27}{8}\right)^{1/3}=\frac32 and (94)1/2=32\left(\frac94\right)^{1/2}=\frac32, so the quotient is 11.

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  • 2022 · 1 mark

The two lines x−y=4x-y=4 and 2x−y=162x-y=16 are (a) parallel (b) perpendicular (c) intersecting (d) non- intersecting

Answer

(c) intersecting

The slopes are 11 and 22. They are different, so the lines are neither parallel nor identical and they meet at one point. Subtracting the equations gives x=12x=12, y=8y=8, so they meet at (12,8)(12,8). The product of slopes is 2≠−12\neq-1, so they are not perpendicular.

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The sum and difference of two positive numbers are 15 and 5 respectively, then the numbers are (a) 14, 1 (b) 11, 4 (c) 12, 3 (d) 10, 5

Answer

(d) 10, 5

x+y=15x+y=15 and x−y=5x-y=5. Adding gives 2x=202x=20, so x=10x=10 and y=5y=5.

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  • 2022 · 1 mark

A number is twice the other. If their sum is 30 then the numbers are (a) 10,20 (b) 25,5 (c) 12,18 (d) 17, 13

Answer

(a) 10, 20

Let the numbers be xx and 2x2x. Then 3x=303x=30, so x=10x=10 and the numbers are 1010 and 2020.

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  • 2022 · 1 mark

If the sum of squares of two consecutive even numbers is 100, then the numbers are (a) 2, 4 (b) 4, 6 (c) 6, 8 (d) 8, 10

Answer

(c) 6, 8

Let the numbers be xx and x+2x+2: x2+(x+2)2=100⇒x2+2x−48=0⇒(x+8)(x−6)=0x^2+(x+2)^2=100\Rightarrow x^2+2x-48=0\Rightarrow (x+8)(x-6)=0, so x=6x=6 and the numbers are 66 and 88. Check: 36+64=10036+64=100.

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If 17 is subtracted from a square of a number the result is 152, then the positive number is (a) 11 (b) 14 (c) 12 (d) 13

Answer

(d) 13

x2−17=152⇒x2=169⇒x=13x^2-17=152\Rightarrow x^2=169\Rightarrow x=13 (positive).

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  • 2022 · 1 mark

The sum of first 20 positive numbers is (a) 150 (b) 175 (c) 200 (d) 210

Answer

(d) 210

S=n(n+1)2=20×212=210S=\frac{n(n+1)}{2}=\frac{20\times21}{2}=210

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If f(x)=2x+3f(x)=2x+3 then f(3)f(3) is equal to (a) 6 (b) 3 (c) 8 (d) 9

Answer

(d) 9

f(3)=2(3)+3=9f(3)=2(3)+3=9.

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One factor of the polynomial x3−4x2+x+6x^3-4x^2+x+6 is (a) (x+1)(x+1) (b) (x+2)(x+2) (c) (x+3)(x+3) (d) (x+4)(x+4)

Answer

(a) (x+1)(x+1)

Let f(x)=x3−4x2+x+6f(x)=x^3-4x^2+x+6. Then f(−1)=−1−4−1+6=0f(-1)=-1-4-1+6=0, so by the factor theorem (x+1)(x+1) is a factor. Indeed f(x)=(x+1)(x−2)(x−3)f(x)=(x+1)(x-2)(x-3).

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Sum of the infinite series 1+12+14+18+…1+\frac12+\frac14+\frac18+\ldots is (a) 2 (b) 3 (c) 1 (d) 4

Answer

(a) 2

This is a geometric series with a=1a=1 and r=12r=\frac12.

S∞=a1−r=11−12=2S_\infty=\frac{a}{1-r}=\frac{1}{1-\frac12}=2

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  • 2022 · 1 mark

Sum of squares of first 5 natural numbers is (a) 50 (b) 52 (c) 53 (d) 55

Answer

(d) 55

12+22+32+42+52=1+4+9+16+25=551^2+2^2+3^2+4^2+5^2=1+4+9+16+25=55

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  • 2022 · 1 mark

Top of tree which is at a distance of 45 meter makes an angle of 45∘45^\circ to the observer, then the height of the tree is (a) 45m (b) 50m (c) 55m (d) 60m

Answer

(a) 45m

tan⁡45∘=h45\tan45^\circ=\dfrac{h}{45} and tan⁡45∘=1\tan45^\circ=1, so h=45h=45 m.

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If two lines are perpendicular with each other then the product of their slope is (a) 1 (b) -1 (c) 2 (d) -2

Answer

(b) -1

For perpendicular lines m1m2=−1m_1m_2=-1.

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(2,1)(2,1) and (2,5)(2,5) are two points in a plain then the distance between two points is (a) 1 (b) 2 (c) 3 (d) 4

Answer

(d) 4

The x-coordinates are equal, so the points lie on a vertical line and the distance is ∣5−1∣=4|5-1|=4.

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  • 2022 · 1 mark

Equation of a straight line which is parallel to y- axis and passes through the point (3,0)(3,0) is (a) X=3X=3 (b) x=−3x=-3 (c) y=3y=3 (d) y=−3y=-3

Answer

(a) x=3x=3

A line parallel to the y-axis is vertical, and the one through (3,0)(3,0) has equation x=3x=3.

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Diameter of a circle subtend an angle at the circumference which is always (a) 45 degree (b) 60 degree (c) 90 degree (d) 180 degree

Answer

(c) 90 degree

The angle in a semicircle is always a right angle.

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  • 2022 · 1 mark

Angle subtended by an arc at the center of a circle and at the circumference are related as (a) Angle at the center is double of the angle of the circumference (b) Angle at circumferences is double of the angle at the center (c) Both the angles are equal (d) There is no relation between them

Answer

(a) Angle at the center is double of the angle of the circumference

The angle subtended by an arc at the centre is twice the angle it subtends at any point on the remaining part of the circle.

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  • 2022 · 1 mark

A parallelogram and a triangle standing on the same base and between the same parallel lines are (a) Both are equal in area (b) Area of the parallelogram is double of area of triangle (c) Area of the triangle is double of the area of parallelogram. (d) Area between them can't be compared

Answer

(b) Area of the parallelogram is double of area of triangle

A triangle on the same base and between the same parallels as a parallelogram has half its area.

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  • 2022 · 1 mark

Sum of the four angles of a cyclic quadrilateral is (a) 90 (b) 180 (c) 270 (d) 360

Answer

(d) 360

The sum of the interior angles of any quadrilateral, including a cyclic one, is 360∘360^\circ (opposite angles sum to 180∘180^\circ each).

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  • 2022 · 1 mark

If A=[2311]A=\begin{bmatrix}2&3\\1&1\end{bmatrix}, then inverse of matrix A is (a) [−231−1]\begin{bmatrix}-2&3\\1&-1\end{bmatrix} (b) [2−3−11]\begin{bmatrix}2&-3\\-1&1\end{bmatrix} (c) [2311]\begin{bmatrix}2&3\\1&1\end{bmatrix} (d) [−2−311]\begin{bmatrix}-2&-3\\1&1\end{bmatrix}

Answer

(a) [−231−1]\begin{bmatrix}-2&3\\1&-1\end{bmatrix}

The inverse of a 2×22\times2 matrix is 1ad−bc[d−b−ca]\frac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}. For the matrix as printed, det⁡A=2−3=−1\det A=2-3=-1 and the inverse is [−131−2]\begin{bmatrix}-1&3\\1&-2\end{bmatrix}, which is not among the options. Option (a) has the correct form and is the nearest choice (it is the exact inverse of [1312]\begin{bmatrix}1&3\\1&2\end{bmatrix}).

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  • 2022 · 1 mark

Determinant of singular matrix is (a) 0 (b) 1 (c) -1 (d) 2

Answer

(a) 0

A singular matrix has no inverse, which happens exactly when its determinant is 00.

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  • 2022 · 1 mark

What is the value of tan⁡90∘\tan90^\circ? (a) 0 (b) 1 (c) -1 (d) ∞\infty

Answer

(d) ∞\infty

tan⁡90∘=sin⁡90∘cos⁡90∘=10\tan90^\circ=\dfrac{\sin90^\circ}{\cos90^\circ}=\dfrac10, which is undefined (it tends to ∞\infty).

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  • 2022 · 1 mark

The radius of the circle x2+y2=25x^2+y^2=25 is equal to (a) 4 (b) 3 (c) 5 (d) 9

Answer

(c) 5

Compare with x2+y2=r2x^2+y^2=r^2: r2=25r^2=25, so r=5r=5.

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  • 2022 · 1 mark

The commission of Rs. 5,600 at the rate of 5% is (a) Rs. 280 (b) Rs. 360 (c) Rs. 560 (d) Rs.144

Answer

(a) Rs. 280

Commission =5100×5600==\dfrac{5}{100}\times5600= Rs. 280.

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  • 2022 · 1 mark

If b2−4ac=0b^2-4ac=0 then the roots of ax2+bx+c=0ax^2+bx+c=0 are: (a) equal (b) not exist (c) rational (d) imaginary

Answer

(a) equal

When the discriminant b2−4ac=0b^2-4ac=0, the roots are real and equal, each −b2a-\dfrac{b}{2a}.

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  • 2022 · 1 mark

Which of the following is correct? (a) A.M=abA.M=ab (b) H.M=2aba+bH.M=\frac{2ab}{a+b} (c) H.M=a+b2H.M=\frac{a+b}{2} (d) none of these

Answer

(b) H.M=2aba+bH.M=\frac{2ab}{a+b}

The harmonic mean of aa and bb is 2aba+b\frac{2ab}{a+b}, while the arithmetic mean is a+b2\frac{a+b}{2}.

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  • 2022 · 1 mark

Limit of function lim⁡x→0sin⁡(x)x\lim_{x\to0}\frac{\sin(x)}{x} is equal to (a) 0 (b) 1 (c) -1 (d) Not exists

Answer

(b) 1

This is the standard limit lim⁡x→0sin⁡xx=1\lim_{x\to0}\frac{\sin x}{x}=1 (with xx in radians).

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  • 2023 · 1 mark

If n(A)=30n(A)=30, n(B)=50n(B)=50, n(U)=60n(U)=60 and n(A∪B)=55n(A\cup B)=55 then sum of n(A−B)n(A-B) and n(B−A)n(B-A) is equal to (a) 45 (b) 50 (c) 55 (d) 30

Answer

(d) 30 First find the intersection:

n(A∩B)=n(A)+n(B)−n(A∪B)=30+50−55=25n(A\cap B)=n(A)+n(B)-n(A\cup B)=30+50-55=25

Then

n(A−B)+n(B−A)=(30−25)+(50−25)=5+25=30n(A-B)+n(B-A)=(30-25)+(50-25)=5+25=30

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  • 2023 · 1 mark

The sum of natural numbers from 1 to 20 is (a) 20×212\frac{20\times21}{2} (b) 19×212\frac{19\times21}{2} (c) 1×202\frac{1\times20}{2} (d) 200

Answer

(a) 20×212\frac{20\times21}{2} Using ∑n=n(n+1)2\sum n=\frac{n(n+1)}{2} with n=20n=20 gives 20×212=210\frac{20\times 21}{2}=210.

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  • 2023 · 1 mark

If n(A)=26n(A)=26 and n(B)=32n(B)=32 then the maximum value of n(A∩B)n(A\cap B) is (a) 26 (b) 58 (c) 32 (d) 6

Answer

(a) 26 The intersection cannot be larger than the smaller set, so n(A∩B)≤min⁡(26,32)=26n(A\cap B)\le\min(26,32)=26. The maximum occurs when A⊆BA\subseteq B.

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  • 2023 · 1 mark

For some integer n, which of the following form is always an odd integer? (a) N (b) n+1 (c) 2n (d) 2n+1

Answer

(d) 2n+12n+1 2n2n is always even, so adding 1 gives an odd integer for every integer nn.

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  • 2023 · 1 mark

The range of the function f(x)=(x−1)f(x)=\sqrt{(x-1)} is (a) [1,∞)[1,\infty) (b) (−∞,+∞)(-\infty,+\infty) (c) (−1,∞)(-1,\infty) (d) [0,∞)[0,\infty)

Answer

(d) [0,∞)[0,\infty) The domain is x≥1x\ge1, so x−1≥0x-1\ge0. The square root takes all values from 0 upward, so the range is [0,∞)[0,\infty).

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  • 2023 · 1 mark

To exist infinite sum of the geometric series its ratio should be (a) less than 0 (b) less than -1 (c) between 1 and -1 (d) greater than 1

Answer

(c) between 1 and -1 The infinite sum a1−r\frac{a}{1-r} exists only when ∣r∣<1|r|<1, that is, −1<r<1-1<r<1.

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  • 2023 · 1 mark

The complement of an angle is 20∘20^\circ (20 degrees) less than 4 times the angle, then the angle is (a) 38 (b) 90 (c) 22 (d) 70

Answer

(c) 22 Let the angle be xx. Its complement is 90−x90-x, so

90−x=4x−20⇒5x=110⇒x=22∘90-x=4x-20\Rightarrow 5x=110\Rightarrow x=22^\circ

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  • 2023 · 1 mark

If the quadratic equation is x2+x+1=0x^2+x+1=0 then the value of x=x=............ (a) −1±i32\frac{-1\pm i\sqrt3}{2} (b) −1−i32\frac{-1-i\sqrt3}{2} (c) −1±i22\frac{-1\pm i\sqrt2}{2} (d) −1+i22\frac{-1+i\sqrt2}{2}

Answer

(a) −1±i32\frac{-1\pm i\sqrt3}{2} By the quadratic formula, x=−1±1−42=−1±i32x=\frac{-1\pm\sqrt{1-4}}{2}=\frac{-1\pm i\sqrt3}{2}. Option (b) gives only one of the two roots.

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  • 2023 · 1 mark

A function is defined as f(x)=3x+14f(x)=\frac{3x+1}{4} then the inverse of this function if it exists is (a) 4x−13\frac{4x-1}{3} (b) 4x+13\frac{4x+1}{3} (c) 3x−14\frac{3x-1}{4} (d) 3x+14\frac{3x+1}{4}

Answer

(a) 4x−13\frac{4x-1}{3} Put y=3x+14y=\frac{3x+1}{4}, so 4y=3x+14y=3x+1 and x=4y−13x=\frac{4y-1}{3}. Hence f−1(x)=4x−13f^{-1}(x)=\frac{4x-1}{3}.

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  • 2023 · 1 mark

One factor of the polynomial x3−4x2+x+6x^3-4x^2+x+6 is (x−2)(x-2) then the two other factors are ...... (a) (x+1)(x−3)(x+1)(x-3) (b) (x+2)(x−2)(x+2)(x-2) (c) (x+3)(x−1)(x+3)(x-1) (d) (x+4)(x+1)(x+4)(x+1)

Answer

(a) (x+1)(x−3)(x+1)(x-3) Dividing by (x−2)(x-2) gives the quotient x2−2x−3x^2-2x-3, which factors as (x−3)(x+1)(x-3)(x+1).

Check: f(2)=8−16+2+6=0f(2)=8-16+2+6=0.

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  • 2023 · 1 mark

The sum of the infinite series 1+12+14+18+……1+\frac12+\frac14+\frac18+\ldots\ldots is (a) 4 (b) 3 (c) 2 (d) 1

Answer

(c) 2 This is a geometric series with a=1a=1, r=12r=\frac12:

S∞=11−12=2S_\infty=\frac{1}{1-\frac12}=2

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  • 2023 · 1 mark

The sum of cubes of the first 6 natural numbers is ......... (a) 661 (b) 551 (c) 441 (d) 331

Answer

(c) 441 ∑k=16k3=(6×72)2=212=441\sum_{k=1}^{6}k^3=\left(\frac{6\times7}{2}\right)^2=21^2=441

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  • 2023 · 1 mark

A poll at a distance of 25 meters from the observer makes an angle of 60 degrees with its top. Then the height of the poll is (a) 25 (b) 25325\sqrt3 (c) 252\frac{25}{2} (d) 50350\sqrt3

Answer

(b) 25325\sqrt3 The angle of elevation is 60∘60^\circ, so

tan⁡60∘=h25⇒h=253 m\tan60^\circ=\frac{h}{25}\Rightarrow h=25\sqrt3\text{ m}

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  • 2023 · 1 mark

If 12 girls or 8 boys can do a piece of work in 3 days, how many days required for 4 boys and 6 girls to do the same work? (a) 2 (b) 4 (c) 5 (d) 3

Answer

(d) 3 Since 12 girls == 8 boys in work rate, 1 girl =23=\frac{2}{3} boy, so 6 girls == 4 boys. Then 4 boys and 6 girls equal 8 boys, who finish the work in 3 days.

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  • 2023 · 1 mark

Two angles subtended by an arc one at the center and the other at the circumference are related as ... (a) The angle at the center is double the angle at the circumference. (b) The angle at the circumference is double the angle at the center. (c) The angle at the center is half the angle at the circumference. (d) The angle at the circumference is equal to the angle at the center.

Answer

(a) The angle at the center is double the angle at the circumference. This is the standard circle theorem for angles subtended by the same arc.

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  • 2023 · 1 mark

If f(x)=4xf(x)=4x, g(x)=x+1g(x)=x+1 & f∘g(x)=20f\circ g(x)=20 then the value of x=x=......... (a) 1 (b) 3 (c) 2 (d) 4

Answer

(d) 4 f∘g(x)=f(x+1)=4(x+1)=20⇒x+1=5⇒x=4f\circ g(x)=f(x+1)=4(x+1)=20\Rightarrow x+1=5\Rightarrow x=4

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  • 2023 · 1 mark

If two children are born in a family find the probability that both are girls (a) 12\frac12 (b) 13\frac13 (c) 14\frac14 (d) 23\frac23

Answer

(c) 14\frac14 The outcomes are GG, GB, BG, BB, all equally likely. Only one has both girls, so P=12×12=14P=\frac12\times\frac12=\frac14.

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  • 2023 · 1 mark

The value of tan⁡75∘\tan75^\circ is (a) 3\sqrt3 (b) 2+32+\sqrt3 (c) 2−32-\sqrt3 (d) 2

Answer

(b) 2+32+\sqrt3 tan⁡75∘=tan⁡(45∘+30∘)=1+131−13=3+13−1=(3+1)22=2+3\tan75^\circ=\tan(45^\circ+30^\circ)=\frac{1+\frac{1}{\sqrt3}}{1-\frac{1}{\sqrt3}}=\frac{\sqrt3+1}{\sqrt3-1}=\frac{(\sqrt3+1)^2}{2}=2+\sqrt3

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  • 2023 · 1 mark

Sum of 15 terms of an A. P. is 435 and the common difference is 4 then the first term is (a) 4 (b) 3 (c) 2 (d) 1

Answer

(d) 1 S15=152[2a+14×4]=435⇒2a+56=58⇒a=1S_{15}=\frac{15}{2}\left[2a+14\times4\right]=435\Rightarrow 2a+56=58\Rightarrow a=1

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  • 2023 · 1 mark

Which one is the same as log⁡8\log8 (a) log⁡4+log⁡2\log4+\log2 (b) log⁡4+log⁡4\log4+\log4 (c) 2log⁡42\log4 (d) 4log⁡24\log2

Answer

(a) log⁡4+log⁡2\log4+\log2 log⁡4+log⁡2=log⁡(4×2)=log⁡8\log4+\log2=\log(4\times2)=\log8. The other options give log⁡16\log16, log⁡16\log16 and log⁡16\log16.

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  • 2023 · 1 mark

If A=(23−4−5)A=\begin{pmatrix}2&3\\-4&-5\end{pmatrix}, B=(0−325)B=\begin{pmatrix}0&-3\\2&5\end{pmatrix} then (AB)T=(AB)^T= (a) (6−109−13)\begin{pmatrix}6&-10\\9&-13\end{pmatrix} (b) (6109−13)\begin{pmatrix}6&10\\9&-13\end{pmatrix} (c) (6−10913)\begin{pmatrix}6&-10\\9&13\end{pmatrix} (d) (6093)\begin{pmatrix}6&0\\9&3\end{pmatrix}

Answer

(a) (6−109−13)\begin{pmatrix}6&-10\\9&-13\end{pmatrix} AB=(0+6−6+150−1012−25)=(69−10−13)AB=\begin{pmatrix}0+6&-6+15\\0-10&12-25\end{pmatrix}=\begin{pmatrix}6&9\\-10&-13\end{pmatrix}

Transposing gives (6−109−13)\begin{pmatrix}6&-10\\9&-13\end{pmatrix}.

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  • 2023 · 1 mark

Harmonic mean between two numbers a and b is (a) a+b2ab\frac{a+b}{2ab} (b) a−b2ab\frac{a-b}{2ab} (c) 2aba+b\frac{2ab}{a+b} (d) 2aba−b\frac{2ab}{a-b}

Answer

(c) 2aba+b\frac{2ab}{a+b} The harmonic mean is the reciprocal of the mean of the reciprocals: 21a+1b=2aba+b\frac{2}{\frac1a+\frac1b}=\frac{2ab}{a+b}.

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  • 2023 · 1 mark

The sum of the first 10 odd numbers is (a) 80 (b) 90 (c) 125 (d) 100

Answer

(d) 100 The sum of the first nn odd numbers is n2n^2, so for n=10n=10 it is 100100.

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  • 2023 · 1 mark

The solution of the equation x2+1=0x^2+1=0 in complex number system is, (a) 1 (b) -1 (c) 0 (d) ±i\pm i

Answer

(d) ±i\pm i x2=−1x^2=-1 gives x=±−1=±ix=\pm\sqrt{-1}=\pm i.

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  • 2023 · 1 mark

The next term of the sequence 1,2,4,7,11,............ is (a) 15 (b) 16 (c) 17 (d) 22

Answer

(b) 16

The differences between consecutive terms are 1, 2, 3, 4, so the next difference is 5 and the next term is 11+5=1611+5=16.

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  • 2023 · 1 mark

If f(x)=x2−3x+1f(x)=x^2-3x+1 & f(2a)=2f(a)f(2a)=2f(a) then a=a=.............. (a) 12\frac{1}{\sqrt2} (b) −12-\frac{1}{\sqrt2} (c) 12\frac{1}{\sqrt2} or −12-\frac{1}{\sqrt2} (d) 1

Answer

(c) 12\frac{1}{\sqrt2} or −12-\frac{1}{\sqrt2}

f(2a)=4a2−6a+1f(2a)=4a^2-6a+1 and 2f(a)=2a2−6a+22f(a)=2a^2-6a+2. Equating gives 2a2=12a^2=1, so a=±12a=\pm\frac{1}{\sqrt2}.

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  • 2023 · 1 mark

If x<0x<0, then the value of ∣x∣|x| is equal to (a) xx (b) −x-x (c) x2x^2 (d) −x2-x^2

Answer

(b) −x-x

For x<0x<0, ∣x∣=−x|x|=-x, which is positive.

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  • 2023 · 1 mark

The two lines 3x+2y=53x+2y=5 and 9x+6y=149x+6y=14 have (a) no solution (b) unique solution (c) infinite solution (d) two solution

Answer

(a) no solution

Here 39=26=13≠514\frac{3}{9}=\frac{2}{6}=\frac13\neq\frac{5}{14}, so the lines are parallel and distinct and never meet.

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  • 2023 · 1 mark

When a point (3,4)(3,4) is rotated by 90 degrees in anticlockwise direction and translated by a point (5,−2)(5,-2) the resulting point is (a) (1,1)(1,1) (b) (8,2)(8,2) (c) (−2,6)(-2,6) (d) (0,1)(0,1)

Answer

(a) (1,1)(1,1)

A 90 degree anticlockwise rotation maps (x,y)→(−y,x)(x,y)\to(-y,x), so (3,4)→(−4,3)(3,4)\to(-4,3). Translating by (5,−2)(5,-2) gives (−4+5, 3−2)=(1,1)(-4+5,\,3-2)=(1,1).

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  • 2023 · 1 mark

If 2x3−7x2+x+10=(x−1)Q(x)+R(x)2x^3-7x^2+x+10=(x-1)Q(x)+R(x) then the value of remainder R(x)R(x) is equal to (a) 5 (b) 6 (c) 7 (d) 9

Answer

(b) 6

By the remainder theorem, R=f(1)=2−7+1+10=6R=f(1)=2-7+1+10=6.

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  • 2023 · 1 mark

If 5x+3=(25)x5^{x+3}=(25)^x, then the value of x is (a) 1 (b) 2 (c) 0 (d) 3

Answer

(d) 3

5x+3=(52)x=52x5^{x+3}=(5^2)^x=5^{2x}, so x+3=2xx+3=2x and x=3x=3.

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  • 2023 · 1 mark

If x+y=3x+y=3 & x2+y2=5x^2+y^2=5, then the value of xyxy is (a) 1 (b) 2 (c) 3 (d) 453

Answer

(b) 2

(x+y)2=x2+y2+2xy(x+y)^2=x^2+y^2+2xy, so 9=5+2xy9=5+2xy and xy=2xy=2.

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  • 2023 · 1 mark

If m1m_1 and m2m_2 are the slopes of the pair of lines ax2+2hxy+by2=0ax^2+2hxy+by^2=0 then the product of m1m_1 and m2m_2 is ....... (a) 2hb\frac{2h}{b} (b) ab (c) a−ba-b (d) ab\frac ab

Answer

(d) ab\frac ab

Putting y=mxy=mx gives bm2+2hm+a=0bm^2+2hm+a=0. The product of its roots is m1m2=abm_1m_2=\frac ab.

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  • 2023 · 1 mark

In the general equation of circle x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0 the radius of the circle is (a) (g,f)(g,f) (b) (f,g)(f,g) (c) (−g,−f)(-g,-f) (d) (−f,−g)(-f,-g)

Answer

(c) (−g,−f)(-g,-f)

The option given, (−g,−f)(-g,-f), is the centre of the circle. The radius itself is g2+f2−c\sqrt{g^2+f^2-c}, which is not one of the choices, so the question intends the centre (−g,−f)(-g,-f).

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  • 2023 · 1 mark

The value of 0! Is (a) 0 (b) -1 (c) 1 (d) 2

Answer

(c) 1

By definition 0!=10!=1.

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  • 2023 · 1 mark

The value of limit lim⁡x→3x2−9x−3\lim_{x\to3}\frac{x^2-9}{x-3} (a) 0 (b) -1 (c) 1 (d) 2

Answer

None of the given options is correct; the limit equals 6.

lim⁡x→3x2−9x−3=lim⁡x→3(x−3)(x+3)x−3=lim⁡x→3(x+3)=6.\lim_{x\to3}\frac{x^2-9}{x-3}=\lim_{x\to3}\frac{(x-3)(x+3)}{x-3}=\lim_{x\to3}(x+3)=6.

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  • 2023 · 1 mark

Derivative of tan⁡x\tan x with respect to x is (a) sin⁡2x\sin^2x (b) cos⁡2x\cos^2x (c) cosec⁡2x\operatorname{cosec}^2x (d) sec⁡2x\sec^2x

Answer

(d) sec⁡2x\sec^2x

ddx(tan⁡x)=sec⁡2x\frac{d}{dx}(\tan x)=\sec^2x.

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  • 2023 · 1 mark

A point in a three-dimensional space has its coordinate is (1,2,−2)(1,2,-2). The distance of this point from the origin is (a) 5 (b) 4 (c) 1 (d) 3

Answer

(d) 3

Distance =12+22+(−2)2=9=3=\sqrt{1^2+2^2+(-2)^2}=\sqrt9=3.

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  • 2023 · 1 mark

A matrix A has its order 3×43\times4 and matrix B has its order 4×34\times3 then the order of their product AB is (a) 3×33\times3 (b) 4×44\times4 (c) 4×34\times3 (d) 3×43\times4

Answer

(a) 3×33\times3

For Am×nA_{m\times n} and Bn×pB_{n\times p}, the product ABAB has order m×pm\times p. Here that is 3×33\times3.

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  • 2023 · 1 mark

If transpose of a matrix A is the matrix A itself then A is called (a) identity (b) scalar (c) symmetric (d) skew-symmetric

Answer

(c) symmetric

A matrix with AT=AA^T=A is called symmetric.

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  • 2023 · 1 mark

Sum of the natural numbers 13+23+33.....+n31^3+2^3+3^3.....+n^3 is (a) (n(n+1)2)3\left(\frac{n(n+1)}{2}\right)^3 (b) (n(n+1)2)2\left(\frac{n(n+1)}{2}\right)^2 (c) (n(n+1)3)2\left(\frac{n(n+1)}{3}\right)^2 (d) (n(n−1)2)2\left(\frac{n(n-1)}{2}\right)^2

Answer

(b) (n(n+1)2)2\left(\frac{n(n+1)}{2}\right)^2

The sum of the first nn cubes equals the square of the sum of the first nn natural numbers.

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  • 2023 · 1 mark

If b2−4ac=0b^2-4ac=0 then the roots of ax2+bx+c=0ax^2+bx+c=0 are: (a) real and equal (b) real and unequal (c) irrational (d) imaginary

Answer

(a) real and equal

The discriminant is zero, so both roots equal −b2a-\frac{b}{2a}.

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  • 2023 · 1 mark

A dice is thrown in the air. The probability of getting odd numbers is (a) 13\frac13 (b) 12\frac12 (c) 34\frac34 (d) 2

Answer

(b) 12\frac12

Odd faces are 1, 3, 5, so P=36=12P=\frac36=\frac12.

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Questions from BCA Old Question Collection 2074-2081 TU FoHSS (Bachelor of Arts in Computer Application (BCA) · 2074), TU BCA Entrance Exam Questions 2020 (TU BCA entrance · 2020), TU BCA Entrance Exam Questions 2019 (TU BCA entrance · 2019), TU BCA Entrance Model Exam Questions (TU BCA entrance · Set I · 2018), TU BCA 2018 Entrance Model Exam (Bachelor in Computer Applications (BCA) · Set II · 2018) and BCA Old Question Collection 2074-2081 TU FoHSS (2075-2078 BS, 2022, 2023 papers) (TU BCA entrance examination papers for 2075, 2076, 2077, 2078 BS and 2022, 2023 AD). Answers are written for this site; check them against your class notes.