Chapter 5
Genetics
MBBS and BDS entrance past exam questions
Past questions and answers
43 questions set from this chapter. Most repeated first.
- 2016 · NEET-UG (India) · 4 marks
A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the plants were selfed the resulting genotypes were in the ratio of:
(a) 1 : 2 : 1 :: Tall homozygous : Tall heterozygous : Dwarf
(b) 1 : 2 : 1 :: Tall heterozygous : Tall homozygous : Dwarf
(c) 3 : 1 :: Tall : Dwarf
(d) 3 : 1 :: Dwarf : Tall
Answer
(a) 1 : 2 : 1 :: Tall homozygous : Tall heterozygous : Dwarf
TT x tt gives all Tt in F1; selfing Tt gives 1 TT : 2 Tt : 1 tt in F2. The question asks for genotypes, so the ratio is 1 : 2 : 1. The 3 : 1 ratio (c) is the phenotypic ratio, and (b) mislabels the classes.
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- 2016 · NEET-UG (India) · 4 marks
Match the terms in Column I with their description in Column II and choose the correct option:
Column I Column II (a) Dominance (i) Many genes govern a single character (b) Codominance (ii) In a heterozygous organism only one allele expresses itself (c) Pleiotropy (iii) In a heterozygous organism both alleles express themselves fully (d) Polygenic inheritance (iv) A single gene influences many characters
Code (a), (b), (c), (d):
(a) (ii), (i), (iv), (iii)
(b) (ii), (iii), (iv), (i)
(c) (iv), (i), (ii), (iii)
(d) (iv), (iii), (i), (ii)
Answer
(b) (ii), (iii), (iv), (i)
Dominance: only one allele expresses in a heterozygote (ii). Codominance: both alleles express fully (iii). Pleiotropy: one gene affects many characters (iv). Polygenic inheritance: many genes govern one character (i).
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- 2016 · NEET-UG (India) · 4 marks
In a testcross involving dihybrid flies, more parental-type offspring were produced than the recombinant-type offspring. This indicates:
(a) The two genes are located on two different chromosomes.
(b) Chromosomes failed to separate during meiosis.
(c) The two genes are linked and present on the same chromosome.
(d) Both of the characters are controlled by more than one gene.
Answer
(c) The two genes are linked and present on the same chromosome.
In a testcross of a dihybrid, independent assortment (genes on different chromosomes) gives parental and recombinant types in equal numbers (1:1:1:1). More parental than recombinant offspring means the genes are linked and tend to be inherited together, with crossing over separating them only occasionally. Failure of chromosomes to separate would give abnormal chromosome numbers, not this ratio.
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- 2016 · NEET-UG (India) · 4 marks
A cell at telophase stage is observed by a student in a plant brought from the field. He tells his teacher that this cell is not like other cells at telophase stage. There is no formation of cell plate and thus the cell is containing more number of chromosomes as compared to other dividing cells. This would result in:
(a) Aneuploidy
(b) Polyploidy
(c) Somaclonal variation
(d) Polyteny
Answer
(b) Polyploidy
If the cell plate does not form at telophase, cytokinesis fails even though the chromosomes have been duplicated and separated. The cell ends up with a doubled chromosome set, i.e. more than two complete sets, which is polyploidy. Aneuploidy is a gain or loss of single chromosomes, and polyteny is the repeated replication of chromatids without separation, as in salivary gland chromosomes.
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- 2015 · NEET-UG (India) · 4 marks
A colour blind man marries a woman with normal sight who has no history of colour blindness in her family. What is the probability of their grandson being colour blind?
(a) 0.25
(b) 0.5
(c) 1
(d) Nil
Answer
(a) 0.25
The man is XY and the woman is XX. All daughters are carriers (XX) and all sons are normal. Grandsons through a daughter are colour blind with probability , while grandsons through a son get the father's Y and are normal, so the overall probability is .
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- 2015 · NEET-UG (India) · 4 marks
The term "linkage" was coined by:
(a) W. Sutton
(b) T.H. Morgan
(c) T. Boveri
(d) G. Mendel
Answer
(b) T.H. Morgan
T.H. Morgan coined the term linkage for genes inherited together on the same chromosome, based on his Drosophila work. Sutton and Boveri proposed the chromosomal theory of inheritance and Mendel formulated the laws of inheritance.
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- 2015 · NEET-UG (India) · 4 marks
A pleiotropic gene:
(a) controls multiple traits in an individual.
(b) is expressed only in primitive plants.
(c) is a gene evolved during Pliocene.
(d) controls a trait only in combination with another gene
Answer
(a) controls multiple traits in an individual.
A pleiotropic gene has multiple phenotypic effects, as in the single gene for phenylketonuria or sickle-cell anaemia. It is not restricted to primitive plants and has nothing to do with the Pliocene; needing another gene describes epistasis/complementation, not pleiotropy.
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- 2015 · NEET-UG (India) · 4 marks
In his classic experiments on pea plants, Mendel did not use:
(a) Flower position
(b) Seed colour
(c) Pod length
(d) Seed shape
Answer
(c) Pod length
Mendel's seven traits were stem height, flower colour, flower position, pod shape, pod colour, seed shape and seed colour. Pod length was not used (pod shape was), while flower position, seed colour and seed shape were.
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- 2015 · NEET-UG (India) · 4 marks
A gene showing codominance has:
(a) both alleles independently expressed in the heterozygote
(b) one allele dominant on the other
(c) alleles tightly linked on the same chromosome
(d) alleles that are recessive to each other
Answer
(a) both alleles independently expressed in the heterozygote
In codominance both alleles are fully expressed in the heterozygote, as with the AB blood group (IA and IB). One allele dominating the other describes complete dominance, and codominance is unrelated to linkage.
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- 2015 · NEET-UG (India) · 4 marks
Identify the correct order of organisation of genetic material from largest to smallest:
(a) Chromosome, genome, nucleotide, gene
(b) Chromosome, gene, genome, nucleotide
(c) Genome, chromosome, nucleotide, gene
(d) Genome, chromosome, gene, nucleotide
Answer
(d) Genome, chromosome, gene, nucleotide
The genome is the total genetic material, divided into chromosomes; each chromosome carries many genes, and each gene is a sequence of nucleotides. The other options misplace the gene or the genome in the hierarchy.
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- 2015 · NEET-UG (India) · 4 marks
Which one of the following is not applicable to RNA?
(a) Chargaff's rule
(b) Complementary base pairing
(c) 5' phosphoryl and 3' hydroxyl ends
(d) Heterocyclic nitrogenous bases
Answer
(a) Chargaff's rule
Chargaff's rule (A = T, G = C) applies to double-stranded DNA, but RNA is usually single-stranded and has uracil instead of thymine. RNA still shows complementary base pairing locally, has 5' phosphate and 3' hydroxyl ends, and contains heterocyclic bases.
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- 2014 · NEET-UG (India) · 4 marks
Fruit colour in squash is an example of:
(a) Dominant epistasis
(b) Complementary genes
(c) Inhibitory genes
(d) Recessive epistasis
Answer
(a) Dominant epistasis
In summer squash, a dominant allele for white colour masks the yellow () and green () alleles, giving a ratio (white : yellow : green) in the . This is dominant epistasis; recessive epistasis would give .
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- 2014 · NEET-UG (India) · 4 marks
A man whose father was colour blind marries a woman who had a colour blind mother and normal father. What percentage of male children of this couple will be colour blind?
(a) 0%
(b) 50%
(c) 75%
(d) 25%
Answer
(b) 50%
The man's father was colour blind, but the man got his Y from his father, so the man is normal (). The woman's mother was colour blind, so the woman is a carrier (). Sons get the mother's X, so half are colour blind: .
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- 2013 · NEET-UG (India) · 4 marks
Which of the following statements is not true of two genes that show 50% recombination frequency?
(a) The genes may be on different chromosomes
(b) The genes are tightly linked
(c) The genes show independent assortment
(d) If the genes are present on the same chromosome, they undergo more than one crossovers in every meiosis
Answer
(b) The genes are tightly linked
Tightly linked genes show very low recombination, not . A recombination frequency means independent assortment, as seen for genes on different chromosomes or far apart on the same chromosome (with multiple crossovers).
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- 2013 · NEET-UG (India) · 4 marks
If two persons with 'AB' blood group marry and have sufficiently large number of children, these children could be classified as 'A' blood group : 'AB' blood group : 'B' blood group in 1 : 2 : 1 ratio. Modern technique of protein electrophoresis reveals presence of both 'A' and 'B' type proteins in 'AB' blood group individuals. This is an example of:
(a) Codominance
(b) Incomplete dominance
(c) Partial dominance
(d) Complete dominance
Answer
(a) Codominance
Both and alleles express in the heterozygote, so both A and B proteins are present in AB blood group. That is codominance. In incomplete dominance a blended intermediate phenotype appears.
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- 2017 · NEET-UG (India) · 4 marks
The final proof for DNA as the genetic material came from the experiments of
(a) Griffith
(b) Hershey and Chase
(c) Avery, Mcleod and McCarty
(d) Hargobind Khorana
Answer
(b) Hershey and Chase
Hershey and Chase labelled phage DNA with P and protein with S. Only the DNA entered the bacterium, which gave the final proof that DNA is the genetic material. Griffith showed transformation, and Avery, MacLeod and McCarty identified the transforming principle as DNA but did not convince everyone.
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- 2017 · NEET-UG (India) · 4 marks
During DNA replication, Okazaki fragments are used to elongate
(a) The leading strand towards replication fork
(b) The lagging strand towards replication fork
(c) The leading strand away from replication fork
(d) The lagging strand away from the replication fork
Answer
(d) The lagging strand away from the replication fork
DNA polymerase adds nucleotides only in the 5'→3' direction. The lagging strand is therefore made discontinuously as short Okazaki fragments, each synthesised away from the fork and later joined by DNA ligase. The leading strand is continuous and grows towards the fork.
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- 2017 · NEET-UG (India) · 4 marks
A disease caused by an autosomal primary non-disjunction is
(a) Down's syndrome
(b) Klinefelter's syndrome
(c) Turner's syndrome
(d) Sickle cell anemia
Answer
(a) Down's syndrome
Down's syndrome is trisomy 21, caused by non-disjunction of an autosome. Klinefelter's (XXY) and Turner's (XO) syndromes involve sex chromosomes. Sickle cell anaemia is a single-gene point mutation, not non-disjunction.
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- 2017 · NEET-UG (India) · 4 marks
The genotypes of a Husband and Wife are and . Among the blood types of their children, how many different genotypes and phenotypes are possible?
(a) 3 genotypes ; 3 phenotypes
(b) 3 genotypes ; 4 phenotypes
(c) 4 genotypes ; 3 phenotypes
(d) 4 genotypes ; 4 phenotypes
Answer
(c) 4 genotypes ; 3 phenotypes
The cross gives , , and . That is 4 genotypes. The phenotypes are blood group A (, ), AB and B, which is 3 phenotypes.
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- 2017 · NEET-UG (India) · 4 marks
Among the following characters, which one was not considered by Mendel in his experiments on pea?
(a) Stem – Tall or Dwarf
(b) Trichomes – Glandular or non-glandular
(c) Seed – Green or Yellow
(d) Pod – Inflated or Constricted
Answer
(b) Trichomes – Glandular or non-glandular
Mendel studied seven pea characters: stem height, flower colour, flower position, pod shape, pod colour, seed shape and seed colour. Trichome type was not among them. Tall/dwarf, green/yellow seed and inflated/constricted pod were all studied.
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- 2017 · NEET-UG (India) · 4 marks
Which one from those given below is the period for Mendel's hybridization experiments?
(a) 1856 - 1863
(b) 1840 - 1850
(c) 1857 - 1869
(d) 1870 - 1877
Answer
(a) 1856 - 1863
Mendel conducted his hybridisation experiments on garden pea for about seven years, from 1856 to 1863. He presented his work in 1865 and published it in 1866.
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- 2017 · NEET-UG (India) · 4 marks
Thalassemia and sickle cell anemia are caused due to a problem in globin molecule synthesis. Select the correct statement.
(a) Both are due to a qualitative defect in globin chain synthesis
(b) Both are due to a quantitative defect in globin chain synthesis
(c) Thalassemia is due to less synthesis of globin molecules
(d) Sickle cell anemia is due to a quantitative problem of globin molecules
Answer
(c) Thalassemia is due to less synthesis of globin molecules
Thalassemia is a quantitative defect: too little of an alpha or beta globin chain is made. Sickle cell anaemia is a qualitative defect, since a point mutation (Glu to Val) produces an abnormal beta globin. So only (c) is correct.
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- 2018 · NEET-UG (India) · 4 marks
The experimental proof for semiconservative replication of DNA was first shown in a
(a) Fungus
(b) Bacterium
(c) Plant
(d) Virus
Answer
(b) Bacterium
Meselson and Stahl showed semiconservative replication in 1958 using the bacterium E. coli grown in N medium and then in N medium, separated by CsCl density gradient centrifugation. Taylor later showed it in plants (Vicia faba), but the first proof was in a bacterium.
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- 2018 · NEET-UG (India) · 4 marks
Which of the following pairs is wrongly matched?
(a) Starch synthesis in pea : Multiple alleles
(b) ABO blood grouping : Co-dominance
(c) XO type sex determination : Grasshopper
(d) T.H. Morgan : Linkage
Answer
(a) Starch synthesis in pea : Multiple alleles
Starch synthesis in pea is the classic example of pleiotropy (one gene, the one controlling starch-branching enzyme, affecting several traits such as seed shape and starch grain structure), not multiple alleles. The other pairs are right: ABO grouping shows co-dominance ( and ), XO sex determination occurs in grasshopper, and Morgan worked on linkage.
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- 2018 · NEET-UG (India) · 4 marks
Select the correct match
(a) Ribozyme - Nucleic acid
(b) × Recessive parent - Dihybrid cross
(c) T.H. Morgan - Transduction
(d) G. Mendel - Transformation
Answer
(a) Ribozyme - Nucleic acid
Ribozymes are catalytic RNA molecules, so they are nucleic acids. A test cross uses the (not ) with the recessive parent, Morgan worked on linkage (not transduction), and transformation was shown by Griffith, not Mendel.
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- 2018 · NEET-UG (India) · 4 marks
Which of the following characteristics represent 'Inheritance of blood groups' in humans?
a. Dominance
b. Co-dominance
c. Multiple allele
d. Incomplete dominance
e. Polygenic inheritance
(a) b, c and e
(b) a, b and c
(c) b, d and e
(d) a, c and e
Answer
(b) a, b and c
ABO blood groups show dominance ( and over ), co-dominance ( and both expressed in AB) and multiple alleles (three alleles , , ). They do not show incomplete dominance or polygenic inheritance.
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- 2018 · NEET-UG (India) · 4 marks
A woman has an X-linked condition on one of her X chromosomes. This chromosome can be inherited by
(a) Only daughters
(b) Only sons
(c) Only grandchildren
(d) Both sons and daughters
Answer
(d) Both sons and daughters
A woman has two X chromosomes, and each of her children receives one of them, so the affected X can pass to a son or daughter with a probability of 1/2. It is not limited to one sex and is not limited to grandchildren.
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- 2019 · NEET-UG (India) · 4 marks
Under which of the following conditions will there be no change in the reading frame of following mRNA?
5′-AACAGCGGUGCUAUU-3′
(a) Insertion of A and G at 4th and 5th positions respectively
(b) Deletion of GGU from 7th, 8th and 9th positions
(c) Insertion of G at 5th position
(d) Deletion of G from 5th position
Answer
(b) Deletion of GGU from 7th, 8th and 9th positions
Read in codons the mRNA is AAC AGC GGU GCU AUU. Deleting GGU (positions 7-9) removes a whole codon, so the downstream codons stay in frame. Inserting or deleting one base (options c and d), or inserting two bases (option a), shifts the frame. Only changes of a multiple of three bases keep the frame.
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- 2019 · NEET-UG (India) · 4 marks
Purines found both in DNA and RNA are
(a) Guanine and cytosine
(b) Cytosine and thymine
(c) Adenine and thymine
(d) Adenine and guanine
Answer
(d) Adenine and guanine
Purines are adenine and guanine, and both occur in DNA and RNA. Cytosine, thymine and uracil are pyrimidines. Thymine is found only in DNA and uracil only in RNA, which rules out options (b) and (c). Option (a) pairs a purine with a pyrimidine.
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- 2019 · NEET-UG (India) · 4 marks
In Antirrhinum (Snapdragon), a red flower was crossed with a white flower and in generation pink flowers were obtained. When pink flowers were selfed, the generation showed white, red and pink flowers. Choose the incorrect statement from the following :
(a) Ratio of is (Red) : (Pink) : (White)
(b) Law of Segregation does not apply in this experiment
(c) This experiment does not follow the Principle of Dominance.
(d) Pink colour in is due to incomplete dominance.
Answer
(b) Law of Segregation does not apply in this experiment
The ratio is (red : pink : white), which shows that the alleles segregate in the gametes. The law of segregation therefore applies. Dominance does not apply because the heterozygote is intermediate, and the pink colour comes from incomplete dominance. Statement (b) is the false one.
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- 2019 · NEET-UG (India) · 4 marks
Select the incorrect statement.
(a) In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
(b) Human males have one of their sex-chromosome much shorter than the other
(c) Male fruit fly is heterogametic
(d) In male grasshoppers 50% of sperms have no sex-chromosome
Answer
(a) In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
Birds have the ZW-ZZ system, in which the female (ZW) is heterogametic. The sex of the progeny therefore depends on the egg (Z or W), not the sperm. The other statements are correct: the human Y is much shorter than X, the male fruit fly (XY) is heterogametic, and male grasshoppers are XO, so half the sperms lack a sex chromosome.
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- 2019 · NEET-UG (India) · 4 marks
What map unit (Centimorgan) is adopted in the construction of genetic maps?
(a) A unit of distance between genes on chromosomes, representing 1% cross over.
(b) A unit of distance between genes on chromosomes, representing 50% cross over.
(c) A unit of distance between two expressed genes representing 10% cross over.
(d) A unit of distance between two expressed genes representing 100% cross over.
Answer
(a) A unit of distance between genes on chromosomes, representing 1% cross over.
One map unit (centimorgan) equals 1% recombination frequency between two linked genes. A larger recombination percentage means the genes are further apart. The 10%, 50% and 100% figures in the other options are wrong.
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- 2019 · NEET-UG (India) · 4 marks
The frequency of recombination between gene pairs on the same chromosome as a measure of the distance between genes was explained by :
(a) Alfred Sturtevant
(b) Sutton Boveri
(c) T.H. Morgan
(d) Gregor J. Mendel
Answer
(a) Alfred Sturtevant
Sturtevant, a student of Morgan, used the frequency of recombination between linked genes as a measure of the distance between them. He used this to build the first genetic maps. Morgan found linkage, and Sutton and Boveri proposed the chromosomal theory. Mendel did not work on linkage.
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- 2020 · NEET-UG (India) · 4 marks
Experimental verification of the chromosomal theory of inheritance was done by
(a) Boveri
(b) Morgan
(c) Mendel
(d) Sutton
Answer
(b) Morgan
Sutton and Boveri proposed the chromosomal theory of inheritance. Morgan verified it experimentally through his work on sex linkage in Drosophila. Mendel worked before chromosomes were linked to inheritance.
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- 2020 · NEET-UG (India) · 4 marks
How many true breeding pea plant varieties did Mendel select as pairs, which were similar except in one character with contrasting traits?
(a) 14
(b) 8
(c) 4
(d) 2
Answer
(a) 14
Mendel chose 14 true-breeding pea varieties, forming 7 pairs, each differing in one character with contrasting traits. The pairs were tall/dwarf, round/wrinkled seed and so on. Option (b), 8, is not the number used.
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- 2020 · NEET-UG (India) · 4 marks
Which of the following statements is correct?
(a) Adenine pairs with thymine through three H-bonds
(b) Adenine does not pair with thymine
(c) Adenine pairs with thymine through two H-bonds
(d) Adenine pairs with thymine through one H-bond
Answer
(c) Adenine pairs with thymine through two H-bonds
In DNA, A pairs with T by two hydrogen bonds and G pairs with C by three. This is why GC-rich DNA is harder to denature. Option (a) wrongly swaps the numbers, and (b) is false because A–T pairing is the rule (Chargaff).
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- 2020 · NEET-UG (India) · 4 marks
Identify the wrong statement with reference to the gene 'I' that controls ABO blood groups.
(a) When and are present together, they express same type of sugar
(b) Allele 'i' does not produce any sugar
(c) The gene (I) has three alleles
(d) A person will have only two of the three alleles
Answer
(a) When and are present together, they express same type of sugar
This is the wrong statement. and are codominant and produce two different sugars (A and B), so the blood group has both. The gene has three alleles (, , ), allele makes no sugar, and a diploid person carries only two of them.
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- 2020 · NEET-UG (India) · 4 marks
Select the correct match.
(a) Sickle cell anaemia - Autosomal recessive trait, chromosome-11
(b) Thalassemia - X linked
(c) Haemophilia - Y linked
(d) Phenylketonuria - Autosomal dominant trait
Answer
(a) Sickle cell anaemia - Autosomal recessive trait, chromosome-11
Sickle cell anaemia results from a single base substitution (GAG to GUG) in the -globin gene on chromosome 11, and is autosomal recessive. Thalassemia is autosomal, haemophilia is X-linked recessive (not Y-linked), and phenylketonuria is autosomal recessive (not dominant).
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- 2020 · NEET-UG (India) · 4 marks
If the distance between two consecutive base pairs is 0.34 nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is bp, then the length of the DNA is approximately
(a) 2.2 meters
(b) 2.7 meters
(c) 2.0 meters
(d) 2.5 meters
Answer
(a) 2.2 meters
Length = number of base pairs spacing . The nearest wrong options come from rounding incorrectly.
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- 2023 · NEET-UG (India) · 4 marks
The phenomenon of pleiotropism refers to
(a) Presence of two alleles, each of the two genes controlling a single trait
(b) A single gene affecting multiple phenotypic expression
(c) More than two genes affecting a single character
(d) Presence of several alleles of a single gene controlling a single crossover
Answer
(b) A single gene affecting multiple phenotypic expression
Pleiotropy is when one gene influences several traits, for example the gene for phenylketonuria or sickle-cell anaemia producing multiple effects. Several genes controlling one character is polygenic inheritance, and several alleles of one gene is multiple allelism.
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- 2023 · NEET-UG (India) · 4 marks
Frequency of recombination between gene pairs on the same chromosome as a measure of the distance between genes to map their position on chromosome, was used for the first time by
(a) Sutton and Boveri
(b) Alfred Sturtevant
(c) Henking
(d) Thomas Hunt Morgan
Answer
(b) Alfred Sturtevant
Sturtevant, a student of Morgan, used recombination frequency between gene pairs as a measure of distance and mapped genes on the chromosome. Morgan discovered linkage, and Sutton and Boveri proposed the chromosomal theory of inheritance.
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- 2023 · NEET-UG (India) · 4 marks
Unequivocal proof that DNA is the genetic material was first proposed by
(a) Alfred Hershey and Martha Chase
(b) Avery, Macleoid and McCarthy
(c) Wilkins and Franklin
(d) Frederick Griffith
Answer
(a) Alfred Hershey and Martha Chase
Hershey and Chase used radioactive P (DNA) and S (protein) in bacteriophages and showed that only DNA enters the bacterium, giving unequivocal proof. Griffith showed transformation, and Avery, MacLeod and McCarty showed DNA was the transforming principle but with less decisive proof.
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- 2023 · NEET-UG (India) · 4 marks
Which of the following statements are correct about Klinefelter's Syndrome?
A. This disorder was first described by Langdon Down (1866).
B. Such an individual has overall masculine development. However, the feminine development is also expressed.
C. The affected individual is short statured.
D. Physical, psychomotor and mental development is retarded.
E. Such individuals are sterile.
Choose the correct answer from the options given below:
(a) C and D only
(b) B and E only
(c) A and E only
(d) A and B only
Answer
(b) B and E only
Klinefelter syndrome (XXY) gives overall masculine development with some feminine traits such as gynaecomastia, and the individuals are sterile. A describes Down syndrome (Langdon Down), and C and D do not describe Klinefelter syndrome (they relate to Turner and Down syndromes).
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Questions from NEET-UG 2013 (India), question paper (NTA NEET-UG 2013 question paper; only questions on topics in Nepal's MBBS entrance syllabus), AIPMT 2014 (NEET-UG, India), Code Q (NTA NEET-UG 2014 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2015 (India), Re-exam Code A (NTA NEET-UG 2015 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2016 (India), Phase 1 Code A (NTA NEET-UG 2016 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2017 (India), Code A (NTA NEET-UG 2017 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2018 (India), Code PP (NTA NEET-UG 2018 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2019 (India), Code S2 (NTA NEET-UG 2019 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2020 (India), Code F1 (September 2020) (NTA NEET-UG 2020 question paper; only questions on topics in Nepal's MBBS entrance syllabus) and NEET-UG 2023 (India), Code F1 Botany (NTA NEET-UG 2023 question paper; only questions on topics in Nepal's MBBS entrance syllabus). Answers are written for this site; check them against your class notes.