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Chapter 7

Plant Physiology and Developmental Botany

MBBS and BDS entrance past exam questions

Past questions and answers

45 questions set from this chapter. Most repeated first.

  • 2016 · NEET-UG (India) · 4 marks

Emerson's enhancement effect and Red drop have been instrumental in the discovery of:
(a) Photophosphorylation and non-cyclic electron transport
(b) Two photosystems operating simultaneously
(c) Photophosphorylation and cyclic electron transport
(d) Oxidative phosphorylation

Answer

(b) Two photosystems operating simultaneously

The red drop (quantum yield falls beyond about 680 nm) is removed by adding shorter-wavelength light, which is Emerson's enhancement effect. This showed that two light reactions, PS I and PS II, work together in photosynthesis.

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  • 2016 · NEET-UG (India) · 4 marks

In a chloroplast the highest number of protons are found in:
(a) Stroma
(b) Lumen of thylakoids
(c) Inter membrane space
(d) Antennae complex

Answer

(b) Lumen of thylakoids

Water splitting and plastoquinone proton pumping release protons into the thylakoid lumen, creating the proton gradient. ATP synthase uses this gradient to make ATP on the stroma side, so the lumen has the highest proton concentration.

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  • 2016 · NEET-UG (India) · 4 marks

The Avena curvature is used for bioassay of:
(a) ABA
(b) GA3\mathrm{GA_3}
(c) IAA
(d) Ethylene

Answer

(c) IAA

The Avena (oat) coleoptile curvature test, by Went, measures auxin: agar blocks containing IAA placed asymmetrically cause bending in decapitated coleoptiles. The bending angle is proportional to IAA concentration. GA3 is assayed by dwarf pea or maize tests, ABA and ethylene by other tests.

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  • 2016 · NEET-UG (India) · 4 marks

A plant in your garden avoids photorespiratory losses, has improved water use efficiency, shows high rates of photosynthesis at high temperatures and has improved efficiency of nitrogen utilisation. In which of the following physiological groups would you assign this plant?
(a) C3\mathrm{C_3}
(b) C4\mathrm{C_4}
(c) CAM
(d) Nitrogen fixer

Answer

(b) C4\mathrm{C_4}

The listed features are the hallmarks of C4_4 plants: Kranz anatomy and PEP carboxylase concentrate CO2_2 around RuBisCO, so photorespiration is avoided. They also have better water use efficiency and keep high photosynthetic rates at high temperature. C3_3 plants lose carbon through photorespiration, and CAM plants are adapted to arid conditions with slow growth.

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  • 2016 · NEET-UG (India) · 4 marks

Water vapour comes out from the plant leaf through the stomatal opening. Through the same stomatal opening carbon dioxide diffuses into the plant during photosynthesis. Reason out the above statements using one of following options.
(a) Both processes can not happen simultaneously.
(b) Both processes can happen together because the diffusion coefficient of water and CO2\mathrm{CO_2} is different.
(c) The above processes happen only during nighttime.
(d) One process occurs during day time, and the other at night.

Answer

(b) Both processes can happen together because the diffusion coefficient of water and CO2\mathrm{CO_2} is different.

Water vapour moves out and CO2_2 moves in along their own concentration gradients through the same open stomata, and the two gases diffuse independently. They differ in diffusion coefficient and gradient, so both go on simultaneously during the day. Stomata are open mainly in the day, so it is wrong to say they happen only at night or at separate times.

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  • 2015 · NEET-UG (India) · 4 marks

Root pressure develops due to:
(a) Increase in transpiration
(b) Active absorption
(c) Low osmotic potential in soil
(d) Passive absorption

Answer

(b) Active absorption

Root pressure develops from active uptake of ions by root cells into the xylem, which lowers its water potential so water enters by osmosis and pushes up. Increased transpiration causes suction (negative pressure), not root pressure, and passive absorption is driven by transpiration pull.

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  • 2015 · NEET-UG (India) · 4 marks

The oxygen evolved during photosynthesis comes from water molecules. Which one of the following pairs of elements is involved in this reaction?
(a) Magnesium and Chlorine
(b) Manganese and Chlorine
(c) Manganese and Potassium
(d) Magnesium and Molybdenum

Answer

(b) Manganese and Chlorine

Photolysis of water at photosystem II needs Mn (in the oxygen-evolving complex) and Cl−^- as cofactors to release O2_2, protons and electrons. Mg is in chlorophyll, and K and Mo are not directly involved in water splitting.

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  • 2015 · NEET-UG (India) · 4 marks

During biological nitrogen fixation, inactivation of nitrogenase by oxygen poisoning is prevented by:
(a) Cytochrome
(b) Leghaemoglobin
(c) Xanthophyll
(d) Carotene

Answer

(b) Leghaemoglobin

Nitrogenase is highly oxygen-sensitive. Leghaemoglobin in root nodules is an oxygen scavenger that keeps the free oxygen level low. Cytochromes, xanthophyll and carotene are not oxygen scavengers in nodules.

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  • 2015 · NEET-UG (India) · 4 marks

Auxin can be bioassayed by:
(a) Lettuce hypocotyl elongation
(b) Avena coleoptile curvature
(c) Hydroponics
(d) Potometer

Answer

(b) Avena coleoptile curvature

The Avena coleoptile curvature test is the classic bioassay for auxin (IAA). Lettuce hypocotyl elongation is used for gibberellins, while hydroponics and the potometer are not bioassays.

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  • 2015 · NEET-UG (India) · 4 marks

Roots play insignificant role in absorption of water in:
(a) Wheat
(b) Sunflower
(c) Pistia
(d) Pea

Answer

(c) Pistia

Pistia is a floating aquatic plant that absorbs water through its whole surface, so roots play only an insignificant role in water absorption. Wheat, sunflower and pea are terrestrial plants that depend on roots for water.

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  • 2015 · NEET-UG (India) · 4 marks

A column of water within xylem vessels of tall trees does not break under its weight because of:
(a) Positive root pressure
(b) Dissolved sugars in water
(c) Tensile strength of water
(d) Lignification of xylem vessels

Answer

(c) Tensile strength of water

Water columns in xylem do not break because of cohesion and adhesion, which give water high tensile strength. Root pressure is too weak for tall trees, dissolved sugars do not hold the column together, and lignification gives wall strength but not column strength.

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  • 2015 · NEET-UG (India) · 4 marks

In photosynthesis, the light-independent reaction takes place at:
(a) Stromal matrix
(b) Thylakoid lumen
(c) Photosystem I
(d) Photosystem II

Answer

(a) Stromal matrix

The light-independent reactions (Calvin cycle) occur in the stroma of the chloroplast, using ATP and NADPH made in the light reactions. The thylakoid lumen and photosystems I and II are on the thylakoid membrane and are sites of the light reactions.

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  • 2014 · NEET-UG (India) · 4 marks

A few normal seedlings of tomato were kept in a dark room. After a few days they were found to have become white-coloured like albinos. Which of the following terms will you use to describe them?
(a) Embolised
(b) Etiolated
(c) Defoliated
(d) Mutated

Answer

(b) Etiolated

Seedlings grown in the dark become pale and spindly because there is no chlorophyll or light-regulated growth. This is etiolation. Embolism is an air bubble in xylem, defoliation is leaf loss, and mutation is a genetic change.

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  • 2014 · NEET-UG (India) · 4 marks

Which one of the following growth regulators is known as 'stress hormone'?
(a) Ethylene
(b) GA3\mathrm{GA_3}
(c) Indole acetic acid
(d) Abscissic acid

Answer

(d) Abscisic acid

ABA is called the stress hormone because its level rises under drought, salinity and cold, closing stomata and helping the plant tolerate stress. Ethylene is the fruit-ripening hormone, GA3_3 promotes stem elongation and IAA is the main auxin for growth.

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  • 2014 · NEET-UG (India) · 4 marks

Dr. F. Went noted that if coleoptile tips were removed and placed on agar for one hour, the agar would produce a bending when placed on one side of freshly-cut coleoptile stumps. Of what significance is this experiment?
(a) It is the basis for quantitative determination of small amounts of growth-promoting substances.
(b) It supports the hypothesis that IAA is auxin.
(c) It demonstrated polar movement of auxins.
(d) It made possible the isolation and exact identification of auxin.

Answer

(a) It is the basis for quantitative determination of small amounts of growth-promoting substances.

Went's agar block experiment (the Avena curvature test) showed that the degree of bending of the stump is proportional to the amount of auxin in the agar, giving a bioassay for tiny quantities of auxin. It did not identify IAA chemically or prove polar transport, so (b), (c) and (d) are not what the experiment is significant for.

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  • 2013 · NEET-UG (India) · 4 marks

During seed germination its stored food is mobilized by:
(a) Ethylene
(b) Cytokinin
(c) ABA
(d) Gibberellin

Answer

(d) Gibberellin

During germination gibberellins from the embryo induce alpha-amylase and other hydrolases in the aleurone layer, which mobilise stored food in the endosperm. ABA and ethylene do not do this, and ABA inhibits germination.

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  • 2013 · NEET-UG (India) · 4 marks

Which of the following criteria does not pertain to facilitated transport?
(a) Requirement of special membrane proteins
(b) High selectivity
(c) Transport saturation
(d) Uphill transport

Answer

(d) Uphill transport

Facilitated diffusion needs membrane proteins, is selective and saturates, but it moves molecules down their concentration gradient without energy. Uphill transport needs ATP, so it is active transport.

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  • 2013 · NEET-UG (India) · 4 marks

The first stable product of fixation of atmospheric nitrogen in leguminous plants is:
(a) NO2−\mathrm{NO_2^-}
(b) Ammonia
(c) NO3−\mathrm{NO_3^-}
(d) Glutamate

Answer

(b) Ammonia

Nitrogenase reduces N2N_2 to NH3NH_3, which is the first stable product in root nodules (N2+8e−+8H++16ATP→2NH3+H2+16ADP+16PiN_2 + 8e^- + 8H^+ + 16ATP \to 2NH_3 + H_2 + 16ADP + 16P_i). Glutamate forms later by reductive amination of ammonia with alpha-ketoglutarate.

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  • 2017 · NEET-UG (India) · 4 marks

Which of the following facilitates opening of stomatal aperture? (a) Contraction of outer wall of guard cells (b) Decrease in turgidity of guard cells (c) Radial orientation of cellulose microfibrils in the cell wall of guard cells (d) Longitudinal orientation of cellulose microfibrils in the cell wall of guard cells

Answer

(c) Radial orientation of cellulose microfibrils in the cell wall of guard cells

Cellulose microfibrils in guard cell walls are arranged radially, so the cells cannot widen. When they become turgid they lengthen and bend outward, pulling the stomatal pore open. Decreased turgidity closes the stoma. Longitudinal microfibrils would not give this response.

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  • 2017 · NEET-UG (India) · 4 marks

With reference to factors affecting the rate of photosynthesis, which of the following statements is not correct? (a) Light saturation for CO2\mathrm{CO_2} fixation occurs at 10% of full sunlight (b) Increasing atmospheric CO2\mathrm{CO_2} concentration upto 0.05% can enhance CO2\mathrm{CO_2} fixation rate (c) C3\mathrm{C_3} plants responds to higher temperatures with enhanced photosynthesis while C4\mathrm{C_4} plants have much lower temperature optimum (d) Tomato is a greenhouse crop which can be grown in CO2\mathrm{CO_2} - enriched atmosphere for higher yield

Answer

(c) C3_3 plants respond to higher temperatures with enhanced photosynthesis while C4_4 plants have much lower temperature optimum

This statement is not correct because it is reversed. C4_4 plants respond to higher temperatures (optimum about 30-45 °C), while C3_3 plants have a lower optimum (about 20-25 °C). The other statements are correct: light saturates at about 10% of full sunlight, CO2_2 up to 0.05% increases fixation, and tomato is grown in CO2_2-enriched greenhouses.

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  • 2017 · NEET-UG (India) · 4 marks

Fruit and leaf drop at early stages can be prevented by the application of (a) Cytokinins (b) Ethylene (c) Auxins (d) Gibberellic acid

Answer

(c) Auxins

Auxins delay abscission of young leaves and fruits and so prevent early drop. Ethylene promotes abscission. Cytokinins delay senescence and gibberellins promote elongation, but neither is the standard answer for preventing fruit and leaf drop.

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  • 2017 · NEET-UG (India) · 4 marks

Phosphoenol pyruvate (PEP) is the primary CO2\mathrm{CO_2} acceptor in : (a) C3\mathrm{C_3} plants (b) C4\mathrm{C_4} plants (c) C2\mathrm{C_2} plants (d) C3\mathrm{C_3} and C4\mathrm{C_4} plants

Answer

(b) C4_4 plants

In C4_4 plants the primary CO2_2 acceptor is phosphoenolpyruvate (PEP) in the mesophyll cells, with PEP carboxylase fixing CO2_2 into oxaloacetate. In C3_3 plants the acceptor is RuBP, fixed by RuBisCO.

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  • 2017 · NEET-UG (India) · 4 marks

The water potential of pure water is (a) Zero (b) Less than zero (c) More than zero but less than one (d) More than one

Answer

(a) Zero

Water potential of pure water at standard temperature and atmospheric pressure is taken as zero. Adding solute lowers it, so the water potential of solutions is negative.

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  • 2018 · NEET-UG (India) · 4 marks

Stomatal movement is not affected by (a) Temperature (b) Light (c) O2\mathrm{O_2} concentration (d) CO2\mathrm{CO_2} concentration

Answer

(c) O2\mathrm{O_2} concentration

Guard cells respond to light, temperature and CO2\mathrm{CO_2} level inside the leaf (low CO2\mathrm{CO_2} opens stomata, high CO2\mathrm{CO_2} closes them), as well as water status and ABA. Ambient O2\mathrm{O_2} concentration has no significant role in stomatal movement.

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  • 2018 · NEET-UG (India) · 4 marks

Which of the following is not a product of light reaction of photosynthesis? (a) ATP (b) NADH (c) NADPH (d) Oxygen

Answer

(b) NADH

The light reaction produces ATP (photophosphorylation), NADPH (reduction of NADP+\mathrm{NADP^+} at PS I) and O2\mathrm{O_2} (photolysis of water at PS II). NADH is a product of respiration, not photosynthesis; the light reaction makes NADPH.

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  • 2018 · NEET-UG (India) · 4 marks

Oxygen is not produced during photosynthesis by (a) Green sulphur bacteria (b) Nostoc (c) Cycas (d) Chara

Answer

(a) Green sulphur bacteria

Green sulphur bacteria carry out anoxygenic photosynthesis, using H2S\mathrm{H_2S} rather than water as the electron donor, so no O2\mathrm{O_2} is released. Nostoc (cyanobacterium), Cycas and Chara (green alga) all use water and release oxygen.

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  • 2019 · NEET-UG (India) · 4 marks

It takes very long time for pineapple plants to produce flowers. Which combination of hormones can be applied to artificially induce flowering in pineapple plants throughout the year to increase yield? (a) Gibberellin and Abscisic acid (b) Cytokinin and Abscisic acid (c) Auxin and Ethylene (d) Gibberellin and Cytokinin

Answer

(c) Auxin and Ethylene

Auxins (e.g. NAA) and ethylene promote flowering in pineapple and make flowering synchronous, so it can be induced throughout the year. Gibberellin promotes bolting and cytokinin promotes cell division, while ABA is inhibitory.

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  • 2019 · NEET-UG (India) · 4 marks

What is the site of perception of photoperiod necessary for induction of flowering in plants? (a) Shoot apex (b) Leaves (c) Lateral buds (d) Pulvinus

Answer

(b) Leaves

Photoperiod is perceived by the leaves, which then send a floral stimulus (florigen) through the phloem to the shoot apex. The shoot apex is where flowering takes place, not where the light signal is sensed. Experiments in which only a leaf is exposed to the right photoperiod still induce flowering.

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  • 2019 · NEET-UG (India) · 4 marks

Xylem translocates (a) Water, mineral salts and some organic nitrogen only (b) Water, mineral salts, some organic nitrogen and hormones (c) Water only (d) Water and mineral salts only

Answer

(b) Water, mineral salts, some organic nitrogen and hormones

Xylem mainly carries water and mineral salts. It also carries some organic nitrogen (amino acids, amides) and hormones such as cytokinins made in the roots. Options (c) and (d) leave these out. Option (a) leaves out the hormones.

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  • 2019 · NEET-UG (India) · 4 marks

What is the direction of movement of sugars in phloem? (a) Downward (b) Bi-directional (c) Non-multidirectional (d) Upward

Answer

(b) Bi-directional

Sugars move in phloem from source to sink, and the direction depends on where the source and sink are. Leaves can send sugar down to roots, or up to growing buds and fruits, and a sink can be above or below the source. Movement in phloem is therefore bi-directional, unlike the one-way upward flow in xylem.

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  • 2020 · NEET-UG (India) · 4 marks

In light reaction, plastoquinone facilitates the transfer of electrons from (a) PS-I to NADP+\mathrm{NADP^+} (b) PS-I to ATP synthase (c) PS-II to Cytb6f complex (d) Cytb6f complex to PS-I

Answer

(c) PS-II to Cytb6f complex

Plastoquinone carries electrons from PS-II to the Cytb6f complex, and it also carries protons into the lumen. Plastocyanin then carries electrons from Cytb6f to PS-I. Ferredoxin and NADP reductase take them from PS-I to NADP+\mathrm{NADP^+}, so options (a), (b) and (d) are wrong.

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  • 2020 · NEET-UG (India) · 4 marks

Name the plant growth regulator which upon spraying on sugarcane crop increases the length of stem, thus increasing the yield of sugarcane crop (a) Ethylene (b) Abscisic acid (c) Cytokinin (d) Gibberellin

Answer

(d) Gibberellin

Gibberellins cause elongation of internodes. Spraying sugarcane with gibberellin increases stem length and so the yield of sugar. Ethylene promotes ripening, abscisic acid is a growth inhibitor, and cytokinin promotes cell division.

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  • 2020 · NEET-UG (India) · 4 marks

The process of growth is maximum during (a) Senescence (b) Dormancy (c) Log phase (d) Lag phase

Answer

(c) Log phase

The log (exponential) phase is the period of fastest growth, when the growth rate is greatest. The lag phase is slow growth, and in senescence growth ends. Dormancy is a resting state with no growth.

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  • 2020 · NEET-UG (India) · 4 marks

The oxygenation activity of RuBisCO enzyme in photorespiration leads to the formation of: (a) 1 molecule of 6-C compound (b) 1 molecule of 4-C compound and 1 molecule of 2-C compound (c) 2 molecules of 3-C compound (d) 1 molecule of 3-C compound

Answer

(d) 1 molecule of 3-C compound

When RuBisCO acts as an oxygenase, RuBP (5-C) is split into one 3-phosphoglycerate (3-C) and one phosphoglycolate (2-C). NCERT-style keys count the 3-C PGA, which enters the Calvin cycle, as the answer. Option (c), two 3-C molecules, is the carboxylation product, and no 6-C compound forms in oxygenation.

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  • 2020 · NEET-UG (India) · 4 marks

Which of the following is not an inhibitory substance governing seed dormancy? (a) Phenolic acid (b) Para-ascorbic acid (c) Gibberellic acid (d) Abscisic acid

Answer

(c) Gibberellic acid

Gibberellic acid promotes germination and breaks seed dormancy, so it is not an inhibitor. Abscisic acid, phenolic acids and para-ascorbic acid are inhibitory substances that maintain dormancy.

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  • 2020 · NEET-UG (India) · 4 marks

The process responsible for facilitating loss of water in liquid form from the tip of grass blades at night and in early morning is: (a) Imbibition (b) Plasmolysis (c) Transpiration (d) Root pressure

Answer

(d) Root pressure

Loss of water as liquid droplets from grass blade tips at night and early morning is guttation, caused by positive root pressure when transpiration is low and soil moisture is high. Transpiration is loss as vapour, while imbibition and plasmolysis do not move water out as droplets.

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  • 2023 · NEET-UG (India) · 4 marks

Which hormone promotes internode/petiole elongation in deep water rice? (a) Kinetin (b) Ethylene (c) 2, 4-D (d) GA3

Answer

(b) Ethylene

Deep water rice responds to submergence by accumulating ethylene, which promotes rapid elongation of internodes and petioles so the leaves reach the surface for air. Kinetin and 2,4-D do not drive this response, and GA3 acts downstream in the stem elongation but ethylene is the primary trigger.

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  • 2023 · NEET-UG (India) · 4 marks

Movement and accumulation of ions across a membrane against their concentration gradient can be explained by (a) Facilitated Diffusion (b) Passive Transport (c) Active Transport (d) Osmosis

Answer

(c) Active Transport

Moving ions against their concentration gradient needs energy (ATP) and carrier proteins, which is active transport. Facilitated diffusion, passive transport and osmosis all move substances down a gradient without energy expenditure.

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  • 2023 · NEET-UG (India) · 4 marks

In tissue culture experiments, leaf mesophyll cells are put in a culture medium to form callus. This phenomenon may be called as (a) Dedifferentiation (b) Development (c) Senescence (d) Differentiation

Answer

(a) Dedifferentiation

Mature, differentiated mesophyll cells regain the capacity to divide and form an undifferentiated mass of cells (callus). This reversal is dedifferentiation; later, callus cells mature again by redifferentiation.

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  • 2023 · NEET-UG (India) · 4 marks

How many ATP and NADPH2 are required for the synthesis of one molecule of Glucose during Calvin cycle? (a) 18 ATP and 12 NADPH2 (b) 12 ATP and 16 NADPH2 (c) 18 ATP and 16 NADPH2 (d) 12 ATP and 12 NADPH2

Answer

(a) 18 ATP and 12 NADPH2

One CO2 fixed needs 3 ATP and 2 NADPH. Glucose has 6 carbons, so 6 CO2 are fixed: 6×3=186\times3=18 ATP and 6×2=126\times2=12 NADPH.

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  • 2023 · NEET-UG (India) · 4 marks

Given below are two statements : Statement I: The forces generated by transpiration can lift a xylem-sized column of water over 130 meters height. Statement II: Transpiration cools leaf surfaces sometimes 10 to 15 degree evaporative cooling. In the light of the above statements, choose the most appropriate answer from the options given below : (a) Both Statement I and Statement II are incorrect (b) Statement I is correct but Statement II is incorrect (c) Statement I is incorrect but Statement II is correct (d) Both Statement I and Statement II are correct

Answer

(d) Both Statement I and Statement II are correct

Transpiration pull generates forces able to lift a xylem water column over 130 m, and evaporative cooling can lower leaf temperature by 10 to 15 degrees. Both statements are standard textbook facts.

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  • 2023 · NEET-UG (India) · 4 marks

Spraying of which of the following phytohormone on juvenile conifers helps in hastening the maturity period, that leads to early seed production? (a) Gibberellic Acid (b) Zeatin (c) Abscisic Acid (d) Indole-3-butyric Acid

Answer

(a) Gibberellic Acid

Spraying GA (gibberellins) on juvenile conifers hastens maturity and leads to early seed production. Zeatin promotes cell division, ABA is a stress hormone, and IBA is an auxin used for rooting.

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  • 2023 · NEET-UG (India) · 4 marks

The reaction centre PS II has an absorption maxima at (a) 700 nm (b) 660 nm (c) 780 nm (d) 680 nm

Answer

(d) 680 nm

The reaction centre of PS II (P680) absorbs at 680 nm, whereas PS I (P700) absorbs at 700 nm. The other values are not reaction centre maxima.

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  • 2023 · NEET-UG (India) · 4 marks

Which micronutrient is required for splitting of water molecule during photosynthesis? (a) Molybdenum (b) Magnesium (c) Copper (d) Manganese

Answer

(d) Manganese

Manganese is required for the water-splitting (oxygen-evolving) complex of PS II. Magnesium is part of chlorophyll but is a macronutrient, and molybdenum and copper act elsewhere (nitrogen metabolism, plastocyanin).

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  • 2023 · NEET-UG (India) · 4 marks

Match List I with List II:
List IList II
A.CohesionI.More attraction in liquid phase
B.AdhesionII.Mutual attraction among water molecules
C.Surface tensionIII.Water loss in liquid phase
D.GuttationIV.Attraction towards polar surfaces
Choose the correct answer from the options given below: (a) A-IV, B-III, C-II, D-I (b) A-III, B-I, C-IV, D-II (c) A-II, B-I, C-IV, D-III (d) A-II, B-IV, C-I, D-III

Answer

(d) A-II, B-IV, C-I, D-III

Cohesion is mutual attraction among water molecules, adhesion is attraction towards polar surfaces, surface tension arises from more attraction in the liquid phase, and guttation is water loss in liquid phase.

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Questions from NEET-UG 2013 (India), question paper (NTA NEET-UG 2013 question paper; only questions on topics in Nepal's MBBS entrance syllabus), AIPMT 2014 (NEET-UG, India), Code Q (NTA NEET-UG 2014 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2015 (India), Re-exam Code A (NTA NEET-UG 2015 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2016 (India), Phase 1 Code A (NTA NEET-UG 2016 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2017 (India), Code A (NTA NEET-UG 2017 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2018 (India), Code PP (NTA NEET-UG 2018 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2019 (India), Code S2 (NTA NEET-UG 2019 question paper; only questions on topics in Nepal's MBBS entrance syllabus), NEET-UG 2020 (India), Code F1 (September 2020) (NTA NEET-UG 2020 question paper; only questions on topics in Nepal's MBBS entrance syllabus) and NEET-UG 2023 (India), Code F1 Botany (NTA NEET-UG 2023 question paper; only questions on topics in Nepal's MBBS entrance syllabus). Answers are written for this site; check them against your class notes.