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Chapter 2

Mathematics

+2 college entrance (after SEE) past exam questions

Past questions and answers

223 questions set from this chapter, 143 of them more than once; 62 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 6 of 11 exams
  • Asked 2 times
  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

If the surface area of a spherical ball is 616 cm2616\ \text{cm}^2, then its diameter is ………… (a) 14 cm (b) 7 cm (c) 21 cm (d) 28 cm

Similar questions: The surface area of a ball is 16pi cm^2, then (2083 · Management Model) · The surface area of a spherical ball is 616 cm^2. (2079 · Management and Humanities Model)

Answer

(a) 14 cm

4πr2=616⇒r2=616×74×22=49⇒r=7 cm,4\pi r^2=616\Rightarrow r^2=\frac{616\times7}{4\times22}=49\Rightarrow r=7\ \text{cm}, so the diameter is 1414 cm.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 5 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

The greatest number of 3 digits, which is a perfect square is ……… (a) 981 (b) 999 (c) 951 (d) 961

Similar questions: The greatest number of 4 digits, which is a (2079 · Management and Humanities Model)

Answer

(d) 961

312=96131^2 = 961 and 322=102432^2 = 1024 has four digits, so the greatest 3-digit perfect square is 961961.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 5 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is ……… (a) 24 cm224\ \text{cm}^2 (b) 48 cm248\ \text{cm}^2 (c) 96 cm296\ \text{cm}^2 (d) 90 cm290\ \text{cm}^2

Similar questions: The side of a rhombus is 10 cm and one diagonal (2079 · Science Model)

Answer

(c) 96 cm296\ \text{cm}^2

The diagonals bisect each other at right angles. Half of the given diagonal is 88 cm, so half of the other is 102−82=6\sqrt{10^2 - 8^2} = 6 cm, giving a diagonal of 1212 cm. Area=12×16×12=96 cm2.\text{Area} = \tfrac12 \times 16 \times 12 = 96\ \text{cm}^2.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 5 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

The surface area of a ball is 16π cm216\pi\ \text{cm}^2, then what is its diameter? (a) 8 cm (b) 4 cm (c) 2 cm (d) 1 cm

Similar questions: If the surface area of a spherical ball is 616 (2081 · Science Model)

Answer

(b) 4 cm

Surface area of a sphere is 4πr24\pi r^2, so 4πr2=16π4\pi r^2 = 16\pi gives r2=4r^2 = 4 and r=2r = 2 cm.

Diameter =2r=4= 2r = 4 cm.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 5 of 11 exams
  • Asked 2 times
  • 2077 · Science Model · 1 mark
  • 2079 · Science Model · 1 mark

The side of a rhombus is 10 cm and one diagonal is 16 cm. The area of the rhombus is ………. (a) 24 cm224\ \text{cm}^2 (b) 48 cm248\ \text{cm}^2 (c) 96 cm296\ \text{cm}^2 (d) 90 cm290\ \text{cm}^2

Similar questions: If the side of a rhombus is 10 cm and one (2083 · Management Model)

Answer

(c) 96 cm296\ \text{cm}^2

The diagonals bisect each other at right angles. Half of the given diagonal is 88, so half of the other is 102−82=6\sqrt{10^2-8^2}=6, making that diagonal 1212 cm.

Area=12×16×12=96 cm2\text{Area}=\tfrac12\times16\times12=96\ \text{cm}^2

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 5 of 11 exams
  • Asked 2 times
  • 2079 · Management and Humanities Model
  • 2077 · Management Model

The greatest number of 4 digits, which is a perfect square is …….. (a) 9996 (b) 9801 (c) 9900 (d) 9604

Similar questions: The greatest number of 3 digits, which is a (2083 · Management Model)

Answer

(b) 9801

992=980199^2 = 9801 and 1002=10000100^2 = 10000 has 5 digits, so 9801 is the greatest 4-digit perfect square.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 4 times
  • 2080 · Science Model · 1 mark
  • 2079 · Management and Humanities Model
  • 2081 · Science Model · 1 mark
  • 2077 · Management Model

The quadratic equation whose roots are 12\frac{1}{2} and −12-\frac{1}{2} is …….. (a) x2−4=0x^2 - 4 = 0 (b) 4x2−1=04x^2 - 1 = 0 (c) 4x2+1=04x^2 + 1 = 0 (d) x2−12=0x^2 - \frac{1}{2} = 0

Answer

(b) 4x2−1=04x^2 - 1 = 0

Sum of roots =0=0, product =−14=-\frac14, so the equation is x2−0⋅x−14=0x^2-0\cdot x-\frac14=0, i.e. 4x2−1=04x^2-1=0.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

Let A={a,b,c}A = \{a, b, c\}, the possible number of subsets for the set AA is …… (a) 3 (b) 5 (c) 6 (d) 8

Similar questions: Let A = 1, 2, 3, the possible number of subsets (2079 · Management and Humanities Model)

Answer

(d) 8

A set with nn elements has 2n2^n subsets. Here n=3n=3, so the number of subsets is

23=8.2^3 = 8.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

The simple interest on Rs. 2500 for 3 years at 1212%12\frac{1}{2}\% per annum is …….. (a) Rs. 900 (b) Rs. 937.50 (c) Rs. 1000 (d) Rs. 1050

Similar questions: The simple interest on Rs. 20,000 for 3 years at (2079 · Management and Humanities Model)

Answer

(b) Rs 937.50

I=PTR100=2500×3×12.5100=Rs 937.50.I = \frac{PTR}{100} = \frac{2500 \times 3 \times 12.5}{100} = \text{Rs } 937.50.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

Rama bears a loss of 12% while selling apples at Rs. 1,320. What is her cost price? (a) Rs. 1500 (b) Rs. 1450 (c) Rs. 1400 (d) Rs. 1350

Similar questions: Rama bears a loss of 12% while selling a mobile (2077 · Management Model)

Answer

(a) Rs. 1500

A loss of 12% means SP=88%SP = 88\% of CPCP.

CP=1320×10088=Rs 1500CP = \frac{1320 \times 100}{88} = \text{Rs } 1500

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2077 · Science Model · 1 mark
  • 2079 · Science Model · 1 mark

A couple plans to have three children. What is the probability that at least two will be boys? (a) 38\frac{3}{8} (b) 12\frac{1}{2} (c) 28\frac{2}{8} (d) 18\frac{1}{8}

Similar questions: A couple plans to have three children. What is (2081 · Science Model)

Answer

(b) 12\frac12

Of the 88 equally likely outcomes, those with at least two boys are exactly 22 boys (33 ways) and 33 boys (11 way).

P=3+18=12.P=\frac{3+1}{8}=\frac12.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2077 · Science Model · 1 mark
  • 2079 · Science Model · 1 mark

How many cubes with 4 cm can be made from a cube with 16 cm in length? (a) 128 (b) 64 (c) 32 (d) 16

Similar questions: How many cubes with 4 cm can be made from a cube (2081 · Science Model)

Answer

(b) 64

Each edge holds 164=4\frac{16}{4}=4 small cubes, so the number is 43=644^3=64 (equivalently 16343\frac{16^3}{4^3}).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

A couple plans to have three children. What is the probability that exactly two will be boys? (a) 23\frac{2}{3} (b) 38\frac{3}{8} (c) 28\frac{2}{8} (d) 18\frac{1}{8}

Similar questions: A couple plans to have three children. What is (2079 · Science Model)

Answer

(b) 38\dfrac38

There are 23=82^3=8 equally likely outcomes. Exactly two boys: BBG, BGB, GBB, which is (32)=3\binom32=3 outcomes. So the probability is 38\dfrac38.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

What is the probability that a leap year has 53 Sundays? (a) 14\frac{1}{4} (b) 13\frac{1}{3} (c) 17\frac{1}{7} (d) 27\frac{2}{7}

Similar questions: What is the probability for 53 Sundays in a leap (2080 · Law Model)

Answer

(d) 27\dfrac27

A leap year has 366=52×7+2366=52\times7+2 days, so 52 full weeks plus 2 extra days. The pairs of extra days are (Sun,Mon), (Mon,Tue), (Tue,Wed), (Wed,Thu), (Thu,Fri), (Fri,Sat), (Sat,Sun). Two of these 7 contain Sunday, so the probability is 27\dfrac27.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

How many cubes with 4 cm can be made from a cube with 16 cm in length? (a) 4 (b) 16 (c) 64 (d) 404

Similar questions: How many cubes with 4 cm can be made from a cube (2079 · Science Model)

Answer

(c) 64

16343=(164)3=43=64\frac{16^3}{4^3}=\left(\frac{16}{4}\right)^3=4^3=64

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • Asked 2 times
  • 2079 · Law Model · 1 mark
  • 2080 · Law Model · 1 mark

What is the probability for 53 Sundays in a leap year? (a) 67\frac{6}{7} (b) 57\frac{5}{7} (c) 27\frac{2}{7} (d) 17\frac{1}{7}

Similar questions: What is the probability that a leap year has 53 (2081 · Science Model)

Answer

(c) 27\frac{2}{7}

A leap year has 366 days = 52 weeks + 2 extra days. The pair of extra days can be (Sun,Mon), (Mon,Tue), (Tue,Wed), (Wed,Thu), (Thu,Fri), (Fri,Sat), (Sat,Sun): 7 equally likely cases, of which 2 contain a Sunday.

P=27P = \frac{2}{7}

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  • Most repeated · 4 of 11 exams
  • 2079 · Management and Humanities Model

Let A={1,2,3}A = \{1, 2, 3\}, the possible number of subsets for the set AA is ………. (a) 8 (b) 7 (c) 6 (d) 3

Similar questions: Let A = a, b, c, the possible number of subsets (2083 · Management Model)

Answer

(a) 8

A set with nn elements has 2n2^n subsets, so 23=82^3 = 8 subsets (including ∅\emptyset and AA itself).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • 2079 · Management and Humanities Model

The simple interest on Rs. 20,000 for 3 years at 13% per annum is …… (a) Rs. 7500 (b) Rs. 7800 (c) Rs. 8100 (d) Rs. 8500

Similar questions: The simple interest on Rs. 2500 for 3 years at (2083 · Management Model)

Answer

(b) Rs 7800

I=PTR100=20000×3×13100=Rs 7800.I = \frac{PTR}{100} = \frac{20000 \times 3 \times 13}{100} = \text{Rs } 7800.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 4 of 11 exams
  • 2077 · Management Model

Rama bears a loss of 12% while selling a mobile at Rs. 1,320, then her cost price is ……… (a) Rs. 1,500 (b) Rs. 1,550 (c) Rs. 1,575 (d) Rs. 1,600

Similar questions: Rama bears a loss of 12% while selling apples at (2083 · Management Model)

Answer

(a) Rs. 1,500

Selling price is 100−12=88%100-12=88\% of the cost price.

CP=132088×100=Rs. 1,500CP=\frac{1320}{88}\times 100=\text{Rs. }1{,}500

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2077 · Science Model · 1 mark
  • 2079 · Science Model · 1 mark
  • 2080 · Law Model · 1 mark

If a+b+c=0a + b + c = 0, then a3+b3+c3a^3 + b^3 + c^3 is equal to …… (a) abcabc (b) 0 (c) 3abc3abc (d) 9abc9abc

Answer

(c) 3abc3abc

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)=0a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)=0, hence a3+b3+c3=3abca^3+b^3+c^3=3abc.

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2077 · Science Model · 1 mark
  • 2079 · Science Model · 1 mark
  • 2081 · Management Model · 1 mark

If x+1x=4x + \frac{1}{x} = 4, then the value of x2+1x2x^2 + \frac{1}{x^2} is …… (a) 18 (b) 14 (c) 16 (d) 20

Answer

(b) 14

x2+1x2=(x+1x)2−2=16−2=14x^2+\frac{1}{x^2}=\left(x+\frac1x\right)^2-2=16-2=14.

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  • Most repeated · 3 of 11 exams
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  • 2080 · Science Model · 1 mark
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If x+y−z=7x + y - z = 7, x−y+z=8x - y + z = 8 and −x+y+z=6-x + y + z = 6, then the average value of x,y,zx, y, z is ……….. (a) 21 (b) 15 (c) 9 (d) 7

Answer

(d) 7

Adding the three equations gives x+y+z=7+8+6=21x+y+z=7+8+6=21.

Average=213=7\text{Average}=\frac{21}{3}=7

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The area of a square field is 144 m2144\ \text{m}^2, then its perimeter is ……… (a) 12 m (b) 48 m (c) 144 m (d) 150 m

Answer

(b) 48 m

Side =144=12=\sqrt{144}=12 m, so the perimeter is 4×12=484\times12=48 m.

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2080 · Science Model · 1 mark
  • 2079 · Management and Humanities Model
  • 2081 · Science Model · 1 mark

Ram does 35\frac{3}{5} of a work in 12 days. He finishes the remaining work in 4 days with the help of Sanu. In how many days will Sanu do the work alone? (a) 18 days (b) 20 days (c) 24 days (d) 30 days

Answer

(b) 20 days

Ram does 35\frac35 in 12 days, so he does 120\frac1{20} per day. The remaining 25\frac25 is done in 4 days by both, so together they do 110\frac1{10} per day. Sanu does 110−120=120\frac1{10}-\frac1{20}=\frac1{20} per day, so he needs 20 days alone.

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

Which of the following is a rational number? (a) 2\sqrt{2} (b) 14\sqrt{14} (c) 24\sqrt{24} (d) 36\sqrt{36}

Answer

(d) 36\sqrt{36}

36=6\sqrt{36}=6, which is rational. The numbers 2, 14 and 24 are not perfect squares, so 2\sqrt{2}, 14\sqrt{14} and 24\sqrt{24} are irrational.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

If A⊂BA \subset B then A∪BA \cup B is equal to ……. (a) AA (b) BB (c) both (a) and (b) (d) neither AA nor BB

Answer

(b) BB

Since every element of AA is already in BB, the union adds nothing new, so A∪B=BA \cup B = B.

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

If 2 American dollars (USD) = Rs. 156 and 2 Pounds (£) = Rs. 234, then 55 American dollars (USD) is equal to …….. (a) £ 36.67 (b) £ 63.67 (c) £ 67.36 (d) £ 67.60

Answer

(a) £ 36.67

USD1=Rs 78USD 1 = \text{Rs } 78, so USD55=Rs 55×78=Rs 4290USD 55 = \text{Rs } 55 \times 78 = \text{Rs } 4290. Also £1 = Rs 117, so 4290117=36.67\frac{4290}{117} = 36.67 pounds.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Most repeated · 3 of 11 exams
  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

There are 40% men and 30% women in a village. If there are 321000 children, then the total population of the village is ……… (a) 1050000 (b) 1060000 (c) 1070000 (d) 1080000

Answer

(c) 1070000

Children are 100−40−30=30%100 - 40 - 30 = 30\% of the population, so Population=321000×10030=1070000.\text{Population} = \frac{321000 \times 100}{30} = 1070000.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 3 times
  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark
  • 2081 · Management Model · 1 mark

One side of an equilateral triangle is 4 cm, its area is ….. (a) 83 cm28\sqrt{3}\ \text{cm}^2 (b) 163 cm216\sqrt{3}\ \text{cm}^2 (c) 43 cm24\sqrt{3}\ \text{cm}^2 (d) 123 cm212\sqrt{3}\ \text{cm}^2

Answer

(c) 43 cm24\sqrt{3}\ \text{cm}^2

Area=34a2=34×42=43 cm2.\text{Area} = \frac{\sqrt{3}}{4}a^2 = \frac{\sqrt{3}}{4}\times 4^2 = 4\sqrt{3}\ \text{cm}^2.

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3245\sqrt[5]{\sqrt[4]{3^2}} equals ……….. (a) 3103^{10} (b) 31103^{\frac{1}{10}} (c) 3403^{40} (d) 31403^{\frac{1}{40}}

Answer

(b) 31103^{\frac{1}{10}}

3245=(32⋅14)15=312⋅15=3110.\sqrt[5]{\sqrt[4]{3^2}} = \left(3^{2\cdot\frac14}\right)^{\frac15} = 3^{\frac12\cdot\frac15} = 3^{\frac{1}{10}}.

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The polynomial xx is ……… (a) a monomial (b) a binomial (c) a trinomial (d) none of these

Answer

(a) a monomial

xx has exactly one term, so it is a monomial.

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In △ABC\triangle ABC, if ∠C>∠B\angle C > \angle B, then ………. (a) BC>ACBC > AC (b) AB>ACAB > AC (c) AB<ACAB < AC (d) BC<ACBC < AC

Answer

(b) AB>ACAB > AC

The larger angle has the longer opposite side. ∠C>∠B\angle C > \angle B, and the side opposite ∠C\angle C is ABAB while the side opposite ∠B\angle B is ACAC, so AB>ACAB > AC.

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Signs of the abscissa and ordinate of a point in the third quadrant are respectively ………. (a) +,0+, 0 (b) −,−-, - (c) −,+-, + (d) +,++, +

Answer

(b) −,−-, -

In the third quadrant both x<0x < 0 and y<0y < 0, so the abscissa and ordinate are both negative.

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The perpendicular distance of the point P(7,5)P(7, 5) from the y-axis is …… (a) 5 (b) 12 (c) 7 (d) 2

Answer

(c) 7

The perpendicular distance of (x,y)(x, y) from the y-axis is ∣x∣|x|, so for P(7,5)P(7, 5) it is 77.

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Which of the lines represents a line parallel to the x-axis? (a) 5x+3=45x + 3 = 4 (b) 3y−5=y+23y - 5 = y + 2 (c) x+y=7x + y = 7 (d) x+3=0x + 3 = 0

Answer

(b) 3y−5=y+23y - 5 = y + 2

A line parallel to the x-axis has the form y=ky = k. Here 3y−y=2+53y - y = 2 + 5 gives 2y=72y = 7, so y=72y = \tfrac72.

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If the diagonals of a quadrilateral bisect each other at right angles, then the quadrilateral is a …… (a) rhombus (b) rectangle (c) square (d) trapezium

Answer

(a) rhombus

A quadrilateral whose diagonals bisect each other is a parallelogram; if they also meet at right angles it is a rhombus. (A square also has this property, but it additionally needs equal diagonals, which is not given.)

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Two adjacent angles of a parallelogram are in the ratio of 4 : 5. The angles are …….. (a) 72∘,108∘72^\circ, 108^\circ (b) 84∘,96∘84^\circ, 96^\circ (c) 70∘,110∘70^\circ, 110^\circ (d) 80∘,100∘80^\circ, 100^\circ

Answer

(d) 80∘,100∘80^\circ, 100^\circ

Adjacent angles of a parallelogram are supplementary. Let them be 4x4x and 5x5x: 4x+5x=180∘⇒x=20∘,4x + 5x = 180^\circ \Rightarrow x = 20^\circ, so the angles are 80∘80^\circ and 100∘100^\circ.

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In figure, PQ is a diameter of circle. ∠SQP is equal to ………. (a) 40° (b) 60° (c) 50° (d) 30°

Answer

(c) 50∘50^\circ

The angle in a semicircle is a right angle, so ∠PSQ=90∘\angle PSQ = 90^\circ. In △PSQ\triangle PSQ, with ∠SPQ=40∘\angle SPQ = 40^\circ, ∠SQP=180∘−90∘−40∘=50∘.\angle SQP = 180^\circ - 90^\circ - 40^\circ = 50^\circ.

Answer checked by Claude Sonnet · Oct 21, 2026

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The mean of ten numbers is 55. If one number is excluded, their mean becomes 50. The excluded number is ……. (a) 100 (b) 80 (c) 70 (d) 60

Answer

(a) 100

Sum of ten numbers =10×55=550= 10 \times 55 = 550. Sum of the remaining nine =9×50=450= 9 \times 50 = 450. Excluded number=550−450=100.\text{Excluded number} = 550 - 450 = 100.

Answer checked by Claude Sonnet · Oct 21, 2026

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The median of the data 32, 35, 39, 31, 35, 36, 33 is ……… (a) 33 (b) 35 (c) 39 (d) 36

Answer

(b) 35

Arranged in order: 31, 32, 33, 35, 35, 36, 39. There are 7 values, so the median is the 4th value, 3535.

Answer checked by Claude Sonnet · Oct 21, 2026

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From a normal pack of 52 cards, a card is drawn at random. The probability of getting a king is ……… (a) 14\frac{1}{4} (b) 126\frac{1}{26} (c) 113\frac{1}{13} (d) 12\frac{1}{2}

Answer

(c) 113\frac{1}{13}

There are 4 kings among 52 cards, so P=452=113P = \dfrac{4}{52} = \dfrac{1}{13}.

Answer checked by Claude Sonnet · Oct 21, 2026

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What is the probability of getting a 2 or a 6 in a roll of a die? (a) 12\frac{1}{2} (b) 13\frac{1}{3} (c) 14\frac{1}{4} (d) 16\frac{1}{6}

Answer

(b) 13\frac{1}{3}

Favourable outcomes are 2 and 6 (2 outcomes) out of 6, so P=26=13P = \dfrac{2}{6} = \dfrac{1}{3}.

Answer checked by Claude Sonnet · Oct 21, 2026

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The value of x2x−2\sqrt{x^2\sqrt{x^{-2}}} is …….. (a) 1 (b) xx (c) x\sqrt{x} (d) x−4x^{-4}

Answer

(c) x\sqrt{x}

x2x−2=x2⋅x−1=x(x>0).\sqrt{x^2\sqrt{x^{-2}}} = \sqrt{x^2 \cdot x^{-1}} = \sqrt{x} \quad (x > 0).

Answer checked by Claude Sonnet · Oct 21, 2026

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The value of xy−11−xy\frac{\frac{x}{y} - 1}{1 - \frac{x}{y}} is ………. (a) 0 (b) 1 (c) −1-1 (d) xy\frac{x}{y}

Answer

(c) −1-1

The numerator xy−1\frac{x}{y} - 1 is the negative of the denominator 1−xy1 - \frac{x}{y}, so the fraction equals −1-1 (for x≠yx \ne y).

Answer checked by Claude Sonnet · Oct 21, 2026

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The fourth proportional to 4, 6, 8 is …….. (a) 12 (b) 32 (c) 48 (d) 50

Answer

(a) 12

If 4:6=8:x4 : 6 = 8 : x, then x=6×84=12.x = \frac{6 \times 8}{4} = 12.

Answer checked by Claude Sonnet · Oct 21, 2026

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If a:b=3:4a : b = 3 : 4 and b:c=1:3b : c = 1 : 3, then a:c=a : c = ? (a) 1 : 4 (b) 3 : 4 (c) 4 : 1 (d) 1 : 1

Answer

(a) 1 : 4

Make bb equal in both: a:b=3:4a : b = 3 : 4 and b:c=4:12b : c = 4 : 12, so a:b:c=3:4:12a : b : c = 3 : 4 : 12 and a:c=3:12=1:4a : c = 3 : 12 = 1 : 4.

Answer checked by Claude Sonnet · Oct 21, 2026

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A mobile of cost Rs. 25,000 is depreciated at 12% p.a., then what will be its value after 2 years? (a) Rs. 22,000 (b) Rs. 20,336 (c) Rs. 19,360 (d) Rs. 19,250

Answer

(c) Rs. 19,360

Value after nn years under reducing-balance depreciation: V=P(1−r100)nV = P\left(1-\frac{r}{100}\right)^n.

V=25000(1−12100)2=25000×(0.88)2=25000×0.7744=Rs 19,360V = 25000\left(1-\frac{12}{100}\right)^2 = 25000 \times (0.88)^2 = 25000 \times 0.7744 = \text{Rs } 19{,}360

Answer checked by Claude Sonnet · Oct 21, 2026

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A can do a piece of work in 6 days and B does the same work in 3 days. How long will A and B take working together? (a) 4 days (b) 2 days (c) 1 day (d) 1121\frac{1}{2} day

Answer

(b) 2 days

Work per day together: 16+13=1+26=12\frac{1}{6}+\frac{1}{3}=\frac{1+2}{6}=\frac{1}{2}.

So the whole work takes 11/2=2\frac{1}{1/2}=2 days.

Answer checked by Claude Sonnet · Oct 21, 2026

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H.C.F. of a3−1a^3 - 1 and a4+a2+1a^4 + a^2 + 1 is …….. (a) a−1a - 1 (b) a2−a+1a^2 - a + 1 (c) a2+a+1a^2 + a + 1 (d) a2−a−1a^2 - a - 1

Answer

(c) a2+a+1a^2 + a + 1

a3−1=(a−1)(a2+a+1)a^3 - 1 = (a-1)(a^2+a+1)

a4+a2+1=(a2+1)2−a2=(a2+a+1)(a2−a+1)a^4 + a^2 + 1 = (a^2+1)^2 - a^2 = (a^2+a+1)(a^2-a+1)

The common factor is a2+a+1a^2 + a + 1.

Answer checked by Claude Sonnet · Oct 21, 2026

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The value of 127×286217×166\frac{12^7 \times 28^6}{21^7 \times 16^6} is ………. (a) 47\frac{4}{7} (b) 74\frac{7}{4} (c) 34\frac{3}{4} (d) 43\frac{4}{3}

Answer

(a) 47\frac{4}{7}

Write in prime factors: 127=2143712^7 = 2^{14}3^7, 286=2127628^6 = 2^{12}7^6, 217=377721^7 = 3^7 7^7, 166=22416^6 = 2^{24}.

214⋅37⋅212⋅7637⋅77⋅224=226224⋅7=47\frac{2^{14}\cdot 3^7\cdot 2^{12}\cdot 7^6}{3^7\cdot 7^7\cdot 2^{24}} = \frac{2^{26}}{2^{24}\cdot 7} = \frac{4}{7}

Answer checked by Claude Sonnet · Oct 21, 2026

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If N=50N = 50 and Xˉ=15\bar{X} = 15 then ∑fx\sum fx is ……. (a) 600 (b) 750 (c) 500 (d) 450

Answer

(b) 750

Mean Xˉ=∑fxN\bar{X} = \frac{\sum fx}{N}, so ∑fx=NXˉ=50×15=750\sum fx = N\bar{X} = 50 \times 15 = 750.

Answer checked by Claude Sonnet · Oct 21, 2026

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The sum of the digits of a two digit number is 7 and their product is 12. Then the numbers are ………. (a) 52 and 25 (b) 34 and 43 (c) 61 and 16 (d) 62 and 26

Answer

(b) 34 and 43

Let the digits be xx and yy with x+y=7x+y=7 and xy=12xy=12. They are the roots of t2−7t+12=0t^2 - 7t + 12 = 0, i.e. (t−3)(t−4)=0(t-3)(t-4)=0, so the digits are 3 and 4.

The numbers are 34 and 43. Check: 3+4=73+4=7, 3×4=123\times4=12. The other options fail (52: product 10; 61: product 6; 62: sum 8).

Answer checked by Claude Sonnet · Oct 21, 2026

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Ananda spends 70% of his income and saves Rs. 540. What is his income? (a) Rs. 1500 (b) Rs. 1650 (c) Rs. 1750 (d) Rs. 1800

Answer

(d) Rs. 1800

Savings are 100%−70%=30%100\% - 70\% = 30\% of income, so 30%30\% of income =540=540.

Income=540×10030=Rs 1800\text{Income} = \frac{540 \times 100}{30} = \text{Rs } 1800

Answer checked by Claude Sonnet · Oct 21, 2026

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If the circumference of a great circle of a metallic sphere is 44 cm, then the surface area of the sphere is ……. (a) 308 cm2308\ \text{cm}^2 (b) 416 cm2416\ \text{cm}^2 (c) 616 cm2616\ \text{cm}^2 (d) 710 cm2710\ \text{cm}^2

Answer

(c) 616 cm2616\ \text{cm}^2

For a great circle, 2πr=442\pi r = 44, so with π=227\pi=\frac{22}{7}: r=44×72×22=7r = \frac{44\times 7}{2\times 22} = 7 cm.

Surface area=4πr2=4×227×49=616 cm2\text{Surface area} = 4\pi r^2 = 4 \times \frac{22}{7} \times 49 = 616\ \text{cm}^2

Answer checked by Claude Sonnet · Oct 21, 2026

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Three years ago, the sum of the ages of a father and his son was 48 years and three years hence the father's age will be three times that of his son. Then the present ages of the father and his son will be respectively ……… (a) 42 years and 12 years (b) 40 years and 8 years (c) 39 years and 9 years (d) 30 years and 18 years

Answer

(a) 42 years and 12 years

Let the present ages of father and son be FF and SS.

Three years ago: (F−3)+(S−3)=48(F-3)+(S-3)=48, so F+S=54F+S=54.

Three years hence: F+3=3(S+3)F+3 = 3(S+3), so F=3S+6F = 3S+6.

Substituting: 4S+6=544S + 6 = 54, so S=12S=12 and F=42F=42. Check: 39+9=4839+9=48 and 45=3×1545 = 3\times15.

Answer checked by Claude Sonnet · Oct 21, 2026

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One of the factors of r7+rs6r^7 + rs^6 is …….. (a) (r+s)(r + s) (b) r2+s2r^2 + s^2 (c) neither (a) nor (b) (d) both (a) and (b)

Answer

(b) r2+s2r^2 + s^2

r7+rs6=r(r6+s6)=r[(r2)3+(s2)3]=r(r2+s2)(r4−r2s2+s4)r^7 + rs^6 = r(r^6+s^6) = r\left[(r^2)^3+(s^2)^3\right] = r(r^2+s^2)(r^4 - r^2s^2 + s^4)

So r2+s2r^2+s^2 is a factor. (r+s)(r+s) is not, since putting r=−sr=-s gives −s7−s7≠0-s^7 - s^7 \ne 0.

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What is the area of a circle whose circumference is π\pi? (a) π4\frac{\pi}{4} (b) π2\frac{\pi}{2} (c) π\pi (d) 2π2\pi

Answer

(a) π4\frac{\pi}{4}

2πr=π2\pi r = \pi gives r=12r = \frac{1}{2}.

Area=πr2=π×14=π4\text{Area} = \pi r^2 = \pi \times \frac{1}{4} = \frac{\pi}{4}

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In a race of 1 km, if A beats B by 100 m and B beats C by 50 m, then by how much does A beat C? (a) 250 m (b) 150 m (c) 147.5 m (d) 145 m

Similar questions: In a race of 1 km, if A beats B by 50 m and B (2077 · Management Model)

Answer

(d) 145 m

When A runs 1000 m, B runs 900 m. When B runs 1000 m, C runs 950 m, so when B runs 900 m, C runs 900×9501000=855900\times\frac{950}{1000}=855 m.

A beats C by 1000−855=1451000-855=145 m.

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At what time does a sum of money double itself at the rate of 8% p.a.? (a) 8 year (b) 10 year (c) 12.5 year (d) 16 year

Similar questions: At what time does a sum of money double itself at (2080 · Science Model)

Answer

(c) 12.5 year

For the money to double, the simple interest must equal the principal: I=PI=P. P=P×8×T100⇒T=1008=12.5 yearsP=\frac{P\times 8\times T}{100}\Rightarrow T=\frac{100}{8}=12.5\text{ years}

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At what time does a sum of money double itself at the rate of 8% p.a.? (a) 8 years (b) 10 years (c) 12.5 years (d) 16 years

Similar questions: At what time does a sum of money double itself at (2081 · Science Model)

Answer

(c) 12.5 years

For the sum to double, the interest equals the principal: P=P×8×T100P=\dfrac{P\times8\times T}{100}, so

T=1008=12.5 yearsT=\frac{100}{8}=12.5\text{ years}

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The surface area of a spherical ball is 616 cm2616\ \text{cm}^2. What is its diameter? (a) 7 cm (b) 14 cm (c) 21 cm (d) 28 cm

Similar questions: If the surface area of a spherical ball is 616 (2081 · Science Model)

Answer

(b) 14 cm

4πr2=616⇒r2=616×74×22=49⇒r=7 cm4\pi r^2 = 616 \Rightarrow r^2 = \frac{616\times 7}{4\times 22}=49 \Rightarrow r = 7\text{ cm}

Diameter =2r=14= 2r = 14 cm.

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In a race of 1 km, if A beats B by 50 m and B beats C by 50 m, then by how much does A beat C? (a) 90 m (b) 100 m (c) 97.5 m (d) none of these

Similar questions: In a race of 1 km, if A beats B by 100 m and B (2081 · Science Model)

Answer

(c) 97.5 m

When A runs 1000 m, B runs 950 m. When B runs 1000 m, C runs 950 m. So when B runs 950 m, C runs 950×9501000=902.5950\times\frac{950}{1000}=902.5 m.

Hence A beats C by 1000−902.5=97.51000-902.5=97.5 m.

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The cotangents of π3,π4,π6\frac{\pi}{3}, \frac{\pi}{4}, \frac{\pi}{6} are in ……… (a) A. P. (b) G.P. (c) H.P. (d) None

Answer

(b) G.P.

cot⁡π3=13, cot⁡π4=1, cot⁡π6=3\cot\frac{\pi}{3}=\frac{1}{\sqrt3},\ \cot\frac{\pi}{4}=1,\ \cot\frac{\pi}{6}=\sqrt3. The ratios are 11/3=3\frac{1}{1/\sqrt3}=\sqrt3 and 31=3\frac{\sqrt3}{1}=\sqrt3, which are equal, so the terms are in G.P. (the differences are not equal, so they are not in A.P.).

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Two vectors a⃗\vec{a} and b⃗\vec{b} are parallel if (a) a⃗=kb⃗\vec{a} = k\vec{b} (b) a⃗=2b⃗\vec{a} = 2\vec{b} (c) a⃗=b⃗\vec{a} = \vec{b} (d) All of these

Answer

(a) a⃗=kb⃗\vec{a} = k\vec{b}

Two non-zero vectors are parallel exactly when one is a scalar multiple of the other. Options (b) and (c) are only the special cases k=2k=2 and k=1k=1.

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The sum of its nn-terms of the series 2+8+18+32+…\sqrt{2} + \sqrt{8} + \sqrt{18} + \sqrt{32} + \dots is ……. (a) 2 n(n+1)2\sqrt{2}\,\frac{n(n+1)}{2} (b) n(n+1)2\sqrt{\frac{n(n+1)}{2}} (c) n(n+1)n2\sqrt{\frac{n(n+1)n}{2}} (d) n(n+1)2\frac{n(n+1)}{2}

Answer

(a) 2 n(n+1)2\sqrt{2}\,\frac{n(n+1)}{2}

8=22, 18=32, 32=42\sqrt8=2\sqrt2,\ \sqrt{18}=3\sqrt2,\ \sqrt{32}=4\sqrt2, so the series is 2(1+2+3+⋯+n)=2 n(n+1)2\sqrt2(1+2+3+\dots+n)=\sqrt2\,\frac{n(n+1)}{2}.

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The equations 3x−4y=53x - 4y = 5 and 12x−16y=2012x - 16y = 20 have …. (a) no solution (b) exactly one solution (c) infinitely many solutions (d) none of above

Answer

(c) infinitely many solutions

The second equation is 44 times the first: 12x−16y=4(3x−4y)=2012x-16y=4(3x-4y)=20. The two equations represent the same line, so every point on it is a solution.

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Which of the following statement is/are correct? i) every integer is a rational number. ii) every rational number is an integer. iii) a real number is either a rational or irrational number. iv) every whole number is a natural number. (a) (ii) (b) (iii) (c) (i) & (iii) (d) (i), (ii) & (iii)

Answer

(c) (i) & (iii)

(i) is true since every integer n=n1n=\frac{n}{1} is rational. (ii) is false, e.g. 12\frac12. (iii) is true. (iv) is false because 00 is a whole number but not a natural number.

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The value of 2.999…2.999\ldots in the form of pq\frac{p}{q}, where pp and qq are integers and q≠0q \ne 0, is ……… (a) 29991000\frac{2999}{1000} (b) 1910\frac{19}{10} (c) 3 (d) 269\frac{26}{9}

Answer

(c) 3

Let x=2.999…x=2.999\ldots. Then 10x=29.999…10x=29.999\ldots, so 9x=279x=27 and x=3x=3.

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3245\sqrt[5]{\sqrt[4]{3^2}} equals ………. (a) 3103^{10} (b) 13−10\frac{1}{3^{-10}} (c) 31103^{\frac{1}{10}} (d) 3−103^{-10}

Answer

(c) 31103^{\frac{1}{10}}

3245=(32/4)1/5=3220=3110\sqrt[5]{\sqrt[4]{3^2}}=\left(3^{2/4}\right)^{1/5}=3^{\frac{2}{20}}=3^{\frac{1}{10}}.

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If x11+101x^{11} + 101 is divided by x+1x + 1, the remainder is ……… (a) 0 (b) −1-1 (c) 100 (d) 102

Answer

(c) 100

By the remainder theorem, put x=−1x=-1: (−1)11+101=−1+101=100(-1)^{11}+101=-1+101=100.

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Which of the following polynomials has (x+1)(x + 1) as a factor? (a) x4+x3+x2+x+1x^4 + x^3 + x^2 + x + 1 (b) x3+x2+x+1x^3 + x^2 + x + 1 (c) x3+2x2−2x+1x^3 + 2x^2 - 2x + 1 (d) x4+3x3+3x2+x+1x^4 + 3x^3 + 3x^2 + x + 1

Answer

(b) x3+x2+x+1x^3 + x^2 + x + 1

(x+1)(x+1) is a factor if the value at x=−1x=-1 is 00. For (b): −1+1−1+1=0-1+1-1+1=0. The others give (a) 11, (c) 44, (d) 11, none zero.

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A polynomial of degree 4 in yy has at most ……… (a) 4 terms (b) 5 terms (c) 3 terms (d) 8 terms

Answer

(b) 5 terms

The terms can have powers y4,y3,y2,y,y0y^4,y^3,y^2,y,y^0, so there are at most 55 terms.

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If the sides of a triangle are doubled then its area ……… (a) is doubled (b) remains the same (c) becomes three times (d) becomes four times

Answer

(d) becomes four times

Doubling all sides gives a similar triangle with ratio 22, so the area scales by 22=42^2=4.

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In parallelogram ABCD, the bisectors of angles A and B intersect each other at O. The value of ∠AOB\angle AOB is (a) 30∘30^\circ (b) 60∘60^\circ (c) 90∘90^\circ (d) cannot be determined

Answer

(c) 90∘90^\circ

Since ∠A+∠B=180∘\angle A+\angle B=180^\circ (co-interior angles), in △AOB\triangle AOB: ∠OAB+∠OBA=A2+B2=90∘\angle OAB+\angle OBA=\frac{A}{2}+\frac{B}{2}=90^\circ, so ∠AOB=90∘\angle AOB=90^\circ.

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The inverse of the matrix (2134)\begin{pmatrix} 2 & 1 \\ 3 & 4 \end{pmatrix} is ……. (a) 15(4132)\frac{1}{5}\begin{pmatrix} 4 & 1 \\ 3 & 2 \end{pmatrix} (b) 15(4−3−12)\frac{1}{5}\begin{pmatrix} 4 & -3 \\ -1 & 2 \end{pmatrix} (c) 15(4−1−32)\frac{1}{5}\begin{pmatrix} 4 & -1 \\ -3 & 2 \end{pmatrix} (d) 15(4312)\frac{1}{5}\begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix}

Answer

(c) 15(4−1−32)\frac{1}{5}\begin{pmatrix} 4 & -1 \\ -3 & 2 \end{pmatrix}

det⁡=2⋅4−1⋅3=5\det=2\cdot4-1\cdot3=5. Swap the diagonal entries and negate the off-diagonal ones: A−1=15(4−1−32)A^{-1}=\frac15\begin{pmatrix}4&-1\\-3&2\end{pmatrix}.

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If sin⁡A2=45\sin\frac{A}{2} = \frac{4}{5}, then the value of cos⁡A\cos A is ……. (a) 35\frac{3}{5} (b) 725\frac{7}{25} (c) −725\frac{-7}{25} (d) −2125\frac{-21}{25}

Answer

(c) −725\frac{-7}{25}

cos⁡A=1−2sin⁡2A2=1−2⋅1625=25−3225=−725\cos A=1-2\sin^2\frac A2=1-2\cdot\frac{16}{25}=\frac{25-32}{25}=-\frac{7}{25}.

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The value of sin⁡18∘\sin 18^\circ is ….. (a) 1+54\frac{1+\sqrt{5}}{4} (b) −1+54\frac{-1+\sqrt{5}}{4} (c) 1−54\frac{1-\sqrt{5}}{4} (d) −1+52\frac{-1+\sqrt{5}}{2}

Answer

(b) −1+54\frac{-1+\sqrt{5}}{4}

Let θ=18∘\theta=18^\circ, so 2θ=90∘−3θ2\theta=90^\circ-3\theta and cos⁡2θ=sin⁡3θ\cos2\theta=\sin3\theta. This gives 1−2s2=3s−4s31-2s^2=3s-4s^3, i.e. 4s3−2s2−3s+1=04s^3-2s^2-3s+1=0, i.e. (s−1)(4s2+2s−1)=0(s-1)(4s^2+2s-1)=0. Taking the root with 0<s<10<s<1: s=−1+54≈0.309s=\frac{-1+\sqrt5}{4}\approx0.309.

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The value of 1+sin⁡θ1−sin⁡θ\sqrt{\frac{1+\sin\theta}{1-\sin\theta}} is …….. (a) tan⁡(π4+θ2)\tan\left(\frac{\pi}{4}+\frac{\theta}{2}\right) (b) tan⁡(π4−θ2)\tan\left(\frac{\pi}{4}-\frac{\theta}{2}\right) (c) tan⁡(π4+θ)\tan\left(\frac{\pi}{4}+\theta\right) (d) tan⁡(π4−θ)\tan\left(\frac{\pi}{4}-\theta\right)

Answer

(a) tan⁡(π4+θ2)\tan\left(\frac{\pi}{4}+\frac{\theta}{2}\right)

Write 1±sin⁡θ=(cos⁡θ2±sin⁡θ2)21\pm\sin\theta=\left(\cos\frac\theta2\pm\sin\frac\theta2\right)^2. Then 1+sin⁡θ1−sin⁡θ=cos⁡θ2+sin⁡θ2cos⁡θ2−sin⁡θ2=1+tan⁡θ21−tan⁡θ2=tan⁡(π4+θ2).\sqrt{\frac{1+\sin\theta}{1-\sin\theta}}=\frac{\cos\frac\theta2+\sin\frac\theta2}{\cos\frac\theta2-\sin\frac\theta2}=\frac{1+\tan\frac\theta2}{1-\tan\frac\theta2}=\tan\left(\frac\pi4+\frac\theta2\right).

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The value of xx when cos⁡2x=sin⁡x\cos 2x = \sin x is …….. (a) 0∘0^\circ (b) 30∘30^\circ (c) 60∘60^\circ (d) 90∘90^\circ

Answer

(b) 30∘30^\circ

1−2sin⁡2x=sin⁡x⇒2sin⁡2x+sin⁡x−1=0⇒(2sin⁡x−1)(sin⁡x+1)=01-2\sin^2x=\sin x\Rightarrow 2\sin^2x+\sin x-1=0\Rightarrow(2\sin x-1)(\sin x+1)=0. So sin⁡x=12\sin x=\frac12, giving x=30∘x=30^\circ (the root sin⁡x=−1\sin x=-1 is not among the options). Check: cos⁡60∘=12=sin⁡30∘\cos60^\circ=\frac12=\sin30^\circ.

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What is the value of θ\theta when cos⁡2θ2−cos⁡θ2+14=0\cos^2\frac{\theta}{2} - \cos\frac{\theta}{2} + \frac{1}{4} = 0? (a) 60∘60^\circ (b) 90∘90^\circ (c) 120∘120^\circ (d) 150∘150^\circ

Answer

(c) 120∘120^\circ

Let c=cos⁡θ2c=\cos\frac\theta2. Then c2−c+14=(c−12)2=0c^2-c+\frac14=\left(c-\frac12\right)^2=0, so cos⁡θ2=12\cos\frac\theta2=\frac12, θ2=60∘\frac\theta2=60^\circ and θ=120∘\theta=120^\circ.

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Two circles x2+y2+2ax+c2=0x^2 + y^2 + 2ax + c^2 = 0 and x2+y2+2by+c2=0x^2 + y^2 + 2by + c^2 = 0 touch externally if ……. (a) a2+b2=c2a^2 + b^2 = c^2 (b) a2+b2+c2=0a^2 + b^2 + c^2 = 0 (c) 1a2+1b2+1c2=0\frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} = 0 (d) 1a2+1b2=1c2\frac{1}{a^2} + \frac{1}{b^2} = \frac{1}{c^2}

Answer

(d) 1a2+1b2=1c2\frac{1}{a^2} + \frac{1}{b^2} = \frac{1}{c^2}

Centres (−a,0),(0,−b)(-a,0),(0,-b); radii r1=a2−c2, r2=b2−c2r_1=\sqrt{a^2-c^2},\ r_2=\sqrt{b^2-c^2}. External touching: a2+b2=(r1+r2)2=a2+b2−2c2+2r1r2a^2+b^2=(r_1+r_2)^2=a^2+b^2-2c^2+2r_1r_2, so c2=r1r2c^2=r_1r_2 and c4=(a2−c2)(b2−c2)c^4=(a^2-c^2)(b^2-c^2). This gives a2b2=c2(a2+b2)a^2b^2=c^2(a^2+b^2), i.e. 1c2=1a2+1b2\frac1{c^2}=\frac1{a^2}+\frac1{b^2}.

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A circle passes through (0,0)(0, 0), (a,0)(a, 0) and (0,b)(0, b). The co-ordinate of the centre is ……. (a) (a,b)(a, b) (b) (b,a)(b, a) (c) (−a,−b)(-a, -b) (d) (a2,b2)\left(\frac{a}{2}, \frac{b}{2}\right)

Answer

(d) (a2,b2)\left(\frac{a}{2}, \frac{b}{2}\right)

The points (0,0),(a,0),(0,b)(0,0),(a,0),(0,b) form a right triangle with the right angle at the origin, so the hypotenuse from (a,0)(a,0) to (0,b)(0,b) is a diameter. The centre is its midpoint (a2,b2)\left(\frac a2,\frac b2\right).

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The value of kk such that the equation 2x2+2y2−6x+8y+k=02x^2 + 2y^2 - 6x + 8y + k = 0 represents a point circle is …… (a) 0 (b) 25 (c) 252\frac{25}{2} (d) −252\frac{-25}{2}

Answer

(c) 252\frac{25}{2}

Divide by 22: x2+y2−3x+4y+k2=0x^2+y^2-3x+4y+\frac k2=0. The radius squared is 94+4−k2\frac94+4-\frac k2. For a point circle this is 00, so k2=254\frac k2=\frac{25}{4} and k=252k=\frac{25}{2}.

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The general equation ax2+2hxy+by2+2gx+2fy+c=0ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 represents a circle if ……. (a) a=b=ha = b = h (b) a=ba = b and h=0h = 0 (c) g=f=cg = f = c (d) a=ba = b and g=fg = f

Answer

(b) a=ba = b and h=0h = 0

A circle has equal coefficients of x2x^2 and y2y^2 and no xyxy term.

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The value of mm such that mx2−8xy+8y2=0mx^2 - 8xy + 8y^2 = 0 represents two coincident straight lines is ……. (a) −1-1 (b) −3-3 (c) 4 (d) 2

Answer

(d) 2

Two lines coincide when the discriminant condition h2=abh^2 = ab holds. Here a=ma=m, 2h=−82h=-8 so h=−4h=-4, b=8b=8:

16=8m⇒m=2.16 = 8m \Rightarrow m = 2.

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The angle between the lines xcos⁡α+ysin⁡α=βx\cos\alpha + y\sin\alpha = \beta and xcos⁡β+ysin⁡β=p1x\cos\beta + y\sin\beta = p_1 is ……. (a) α+β\alpha + \beta (b) α−β\alpha - \beta (c) αβ\alpha\beta (d) αβ,β≠0\frac{\alpha}{\beta}, \beta \ne 0

Answer

(b) α−β\alpha - \beta

The line xcos⁡α+ysin⁡α=px\cos\alpha + y\sin\alpha = p has normal making angle α\alpha with the xx-axis, and the second line has normal at angle β\beta. The angle between the lines equals the angle between their normals, α−β\alpha-\beta.

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The points (a,0)(a, 0), (0,b)(0, b) and (1,1)(1, 1) are collinear if ……… (a) a+b=aba + b = ab (b) a−b=aba - b = ab (c) b−a=abb - a = ab (d) a+b+ab=0a + b + ab = 0

Answer

(a) a+b=aba + b = ab

The line through (a,0)(a,0) and (0,b)(0,b) is xa+yb=1\frac{x}{a}+\frac{y}{b}=1. Passing through (1,1)(1,1) gives 1a+1b=1\frac1a+\frac1b=1, so a+b=aba+b=ab.

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If A and B are square matrices of the same order then …… (a) both AB and BA are defined (b) (AB)T=BTAT(AB)^T = B^T A^T (c) (AB)−1=B−1A−1(AB)^{-1} = B^{-1}A^{-1} (d) all of the above

Answer

(b) (AB)T=BTAT(AB)^T = B^TA^T

The reversal law for transposes holds for all matrices. Option (c) needs AA and BB to be invertible, so "all of the above" is not true in general.

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A square matrix A=[aij]A = [a_{ij}] in which aij=0a_{ij} = 0 for i≠ji \ne j and aija_{ij} = constant, is called …….. (a) diagonal matrix (b) scalar matrix (c) unit matrix (d) null matrix

Answer

(b) scalar matrix

All off-diagonal entries are 00 and all diagonal entries equal the same constant, which is the definition of a scalar matrix (a diagonal matrix whose diagonal entries are equal).

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The sum of the series 1+4+9+16+…1 + 4 + 9 + 16 + \dots to nn terms is ……. (a) n2n^2 (b) n(n+1)2\frac{n(n+1)}{2} (c) n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6} (d) [n(n+1)2]2\left[\frac{n(n+1)}{2}\right]^2

Answer

(c) n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}

The kk-th term is k2k^2, so the sum is ∑k=1nk2=n(n+1)(2n+1)6\sum_{k=1}^n k^2=\frac{n(n+1)(2n+1)}{6}. Check n=2n=2: 2⋅3⋅56=5=1+4\frac{2\cdot3\cdot5}{6}=5=1+4.

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If A and B are non-empty sets and A×B=B×AA \times B = B \times A then …… (a) A is a proper subset of B (b) A is a subset of B (c) B is a proper subset of A (d) A = B

Answer

(d) A = B

If A×B=B×AA\times B=B\times A, every (a,b)(a,b) with a∈A, b∈Ba\in A,\ b\in B must also satisfy a∈B, b∈Aa\in B,\ b\in A. Since both sets are non-empty, this gives A⊆BA\subseteq B and B⊆AB\subseteq A, so A=BA=B.

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A function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by f(x)=3x+5f(x) = 3x + 5, x∈Rx \in \mathbb{R} is …… (a) one-one (b) onto (c) both (a) & (b) (d) neither (a) nor (b)

Answer

(c) both (a) & (b)

One-one: 3x1+5=3x2+5⇒x1=x23x_1+5=3x_2+5\Rightarrow x_1=x_2. Onto: for any y∈Ry\in\mathbb R, x=y−53∈Rx=\frac{y-5}{3}\in\mathbb R gives f(x)=yf(x)=y.

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The curve of the function y=−x2+4x+3y = -x^2 + 4x + 3 ……….. (a) faced upward (b) faced downward (c) faced right side (d) faced left side

Answer

(b) faced downward

The coefficient of x2x^2 is −1<0-1<0, so the parabola opens downward.

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If (x+3)2=225(x + 3)^2 = 225, which of the following could be the value of x−1x - 1? (a) 12 (b) −12-12 (c) −16-16 (d) −19-19

Answer

(d) −19-19

x+3=±15x+3=\pm15, so x=12x=12 or x=−18x=-18. Then x−1=11x-1=11 or −19-19; only −19-19 is listed.

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Triangle ABC has vertices A(−2,−5)A(-2, -5), B(−7,5)B(-7, 5) and C(1,1)C(1, 1). AD is a median. The gradient of AD is … (a) −12-\frac{1}{2} (b) 2 (c) −8-8 (d) 8

Answer

(c) −8-8

The midpoint of BCBC is D(−7+12,5+12)=(−3,3)D\left(\frac{-7+1}{2},\frac{5+1}{2}\right)=(-3,3).

mAD=3−(−5)−3−(−2)=8−1=−8.m_{AD}=\frac{3-(-5)}{-3-(-2)}=\frac{8}{-1}=-8.

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If the sum of squares of 10 terms is 38500, variance is 825, then the coefficient of standard deviation is (a) 0.24 (b) 0.25 (c) 0.42 (d) 0.52

Answer

(d) 0.52

Mean of squares =3850010=3850=\frac{38500}{10}=3850, and variance =3850−xˉ2=825=3850-\bar x^2=825, so xˉ2=3025\bar x^2=3025 and xˉ=55\bar x=55.

σ=825≈28.72,coefficient of SD=σxˉ=28.7255≈0.52.\sigma=\sqrt{825}\approx28.72,\qquad \text{coefficient of SD}=\frac{\sigma}{\bar x}=\frac{28.72}{55}\approx0.52.

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The standard deviation of a data is 15 and the coefficient of variation is 75%, then the mean of the data is; (a) 15 (b) 20 (c) 25 (d) 30

Answer

(b) 20

CV=σxˉ×100⇒75=15xˉ×100⇒xˉ=20.CV=\frac{\sigma}{\bar x}\times100\Rightarrow 75=\frac{15}{\bar x}\times100\Rightarrow \bar x=20.

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If a⃗+b⃗+c⃗=0\vec{a} + \vec{b} + \vec{c} = 0, ∣a⃗∣=3|\vec{a}| = 3, ∣b⃗∣=5|\vec{b}| = 5 and ∣c⃗∣=7|\vec{c}| = 7, then the angle between a⃗\vec{a} and b⃗\vec{b} is ………. (a) 0 (b) π6\frac{\pi}{6} (c) π3\frac{\pi}{3} (d) π2\frac{\pi}{2}

Answer

(c) π3\frac{\pi}{3}

From a⃗+b⃗=−c⃗\vec a+\vec b=-\vec c, squaring: 9+25+2a⃗⋅b⃗=499+25+2\vec a\cdot\vec b=49, so a⃗⋅b⃗=152\vec a\cdot\vec b=\frac{15}{2}.

cos⁡θ=15/23⋅5=12⇒θ=π3.\cos\theta=\frac{15/2}{3\cdot5}=\frac12\Rightarrow\theta=\frac{\pi}{3}.

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If a matrix AA is such that A2=AA^2 = A, then AA is called ……… (a) Square matrix (b) Symmetric matrix (c) Idempotent matrix (d) Null matrix

Answer

(c) Idempotent matrix

A matrix satisfying A2=AA^2=A is called idempotent.

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The probability that a non-leap year contains 53 Sundays is ……… (a) 1365\frac{1}{365} (b) 27\frac{2}{7} (c) 2365\frac{2}{365} (d) 17\frac{1}{7}

Answer

(d) 17\frac17

A non-leap year has 5252 weeks plus 11 extra day. That day must be a Sunday for 5353 Sundays, and it is equally likely to be any of 77 days, so P=17P=\frac17.

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If cos⁡θ−sin⁡θ=2sin⁡θ\cos\theta - \sin\theta = \sqrt{2}\sin\theta, then cos⁡θ+sin⁡θ=\cos\theta + \sin\theta = ……… (a) 2cos⁡θ\sqrt{2}\cos\theta (b) 2sin⁡θ\sqrt{2}\sin\theta (c) 2cos⁡θ2\cos\theta (d) −2sin⁡θ-\sqrt{2}\sin\theta

Answer

(a) 2cos⁡θ\sqrt2\cos\theta

From cos⁡θ=(2+1)sin⁡θ\cos\theta=(\sqrt2+1)\sin\theta, we get sin⁡θ=(2−1)cos⁡θ\sin\theta=(\sqrt2-1)\cos\theta. Then

cos⁡θ+sin⁡θ=cos⁡θ+(2−1)cos⁡θ=2cos⁡θ.\cos\theta+\sin\theta=\cos\theta+(\sqrt2-1)\cos\theta=\sqrt2\cos\theta.

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What is 10% of 20% of 30%? (a) 0.006% (b) 0.06% (c) 0.6% (d) 6%

Answer

(c) 0.6%

0.1×0.2×30%=0.02×30%=0.6%.0.1\times0.2\times30\% = 0.02\times30\% = 0.6\%.

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What is the measure, in degrees, of each interior angle in a regular decagon? (a) 102∘102^\circ (b) 120∘120^\circ (c) 144∘144^\circ (d) 152∘152^\circ

Answer

(c) 144∘144^\circ

Each interior angle of a regular nn-gon is (n−2)180∘n\frac{(n-2)180^\circ}{n}. For n=10n=10: 8⋅180∘10=144∘\frac{8\cdot180^\circ}{10}=144^\circ.

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If 0<x<10 < x < 1, which of the following lists the numbers in increasing order? (a) x,x,x2\sqrt{x}, x, x^2 (b) x2,x,xx^2, x, \sqrt{x} (c) x2,x,xx^2, \sqrt{x}, x (d) x,x,x2x, \sqrt{x}, x^2

Answer

(b) x2,x,xx^2, x, \sqrt{x}

For 0<x<10<x<1, multiplying by xx shrinks a number, so x2<xx^2<x; and x<xx<\sqrt x. Check x=14x=\frac14: 116<14<12\frac1{16}<\frac14<\frac12.

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In triangle ABC, the bisectors of ∠B\angle B and ∠C\angle C meet at O. Then ∠BOC\angle BOC is …… (a) 90∘−12∠A90^\circ - \frac{1}{2}\angle A (b) 180∘−12∠A180^\circ - \frac{1}{2}\angle A (c) 90∘+12∠A90^\circ + \frac{1}{2}\angle A (d) 180∘+12∠A180^\circ + \frac{1}{2}\angle A

Answer

(c) 90∘+12∠A90^\circ+\frac12\angle A

In △BOC\triangle BOC, ∠BOC=180∘−12(∠B+∠C)=180∘−12(180∘−∠A)=90∘+12∠A.\angle BOC=180^\circ-\frac12(\angle B+\angle C)=180^\circ-\frac12(180^\circ-\angle A)=90^\circ+\frac12\angle A.

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Axioms are assumed …… (a) universal truth specific to geometry (b) theorems (c) definition (d) universal truth in all branches of mathematics

Answer

(d) universal truth in all branches of mathematics

Euclid's axioms (common notions) are self-evident truths assumed without proof that apply across all of mathematics, unlike postulates, which are specific to geometry.

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Which of the following doesn't represent a function (graphs of the relations are shown) (a) x=yx = y (b) y2=xy^2 = x (c) y=x2y = x^2 (d) y=−xy = -x

Answer

(b) y2=xy^2 = x

A relation is a function only if each xx gives exactly one yy. For y2=xy^2 = x, x=4x = 4 gives y=2y = 2 and y=−2y = -2, so a vertical line cuts the graph twice. The others, y=xy = x, y=x2y = x^2 and y=−xy = -x, give one yy per xx.

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If (x+3),3x,(4x+1)(x+3), 3x, (4x+1) are in AP then xx is equal to (a) 3 (b) 4 (c) 5 (d) 1

Answer

(b) 4

For an AP the common difference is equal, so 3x−(x+3)=(4x+1)−3x3x-(x+3)=(4x+1)-3x. This gives 2x−3=x+12x-3=x+1, so x=4x=4. Check: the terms are 7, 12, 17.

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The sum of all two digits numbers is (a) 4895 (b) 4905 (c) 3065 (d) 2015

Answer

(b) 4905

The two-digit numbers 10, 11, ..., 99 form an AP with n=90n=90, a=10a=10, l=99l=99.

S=902(10+99)=45×109=4905S=\frac{90}{2}(10+99)=45\times109=4905

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The value of x12×x14×x18×…∞x^{\frac{1}{2}} \times x^{\frac{1}{4}} \times x^{\frac{1}{8}} \times \dots \infty is (a) xx (b) x2x^2 (c) 1x\frac{1}{x} (d) x3x^3

Answer

(a) xx

The exponents add to a GP with a=12a=\tfrac12, r=12r=\tfrac12:

12+14+18+⋯=1/21−1/2=1\frac12+\frac14+\frac18+\dots=\frac{1/2}{1-1/2}=1

so the product is x1=xx^1=x.

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AA is a matrix of 3×43 \times 4. Both ATBA^T B and BATBA^T are defined, then the order of BB is (a) 3×43 \times 4 (b) 3×43 \times 4 (c) 4×34 \times 3 (d) 4×44 \times 4

Answer

(a) 3×43\times4 (option (b) is the same order)

ATA^T is 4×34\times3. For ATBA^TB to be defined, BB must have 3 rows. For BATBA^T to be defined, BB must have 4 columns. So BB is 3×43\times4.

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Let a⃗\vec{a} and b⃗\vec{b} be two given vectors such that ∣a⃗∣=3|\vec{a}| = \sqrt{3}, ∣b⃗∣=2|\vec{b}| = 2 and a⃗⋅b⃗=6\vec{a}\cdot\vec{b} = \sqrt{6}, then the angle between a⃗\vec{a} and b⃗\vec{b} is …………. (a) π3\frac{\pi}{3} (b) π4\frac{\pi}{4} (c) π2\frac{\pi}{2} (d) 0

Answer

(b) π4\dfrac{\pi}{4}

cos⁡θ=a⃗⋅b⃗∣a⃗∣∣b⃗∣=623=22=12\cos\theta=\frac{\vec a\cdot\vec b}{|\vec a||\vec b|}=\frac{\sqrt6}{2\sqrt3}=\frac{\sqrt2}{2}=\frac{1}{\sqrt2}

so θ=π4\theta=\dfrac{\pi}{4}.

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The area of the triangle formed by the line 2x+3y=122x + 3y = 12 with the coordinate axes is ………. (a) 24 (b) 12 (c) 6 (d) 3

Answer

(b) 12

Intercepts of 2x+3y=122x+3y=12: xx-intercept 6 (put y=0y=0), yy-intercept 4 (put x=0x=0).

Area=12×6×4=12\text{Area}=\tfrac12\times6\times4=12

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If the radius of a circle is decreased by 30%, by what percent will the area of the circular region be decreased? (a) 15% (b) 49% (c) 51% (d) 60%

Answer

(c) 51%

New radius is 0.7r0.7r, so the new area is π(0.7r)2=0.49πr2\pi(0.7r)^2=0.49\pi r^2. The area decreases by 100−49=51%100-49=51\%.

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The sum of the roots of 3x2−4x+4=03x^2 - 4x + 4 = 0 is ………. (a) 43\frac{4}{3} (b) 34\frac{3}{4} (c) −43-\frac{4}{3} (d) 4

Answer

(a) 43\dfrac43

For ax2+bx+c=0ax^2+bx+c=0, the sum of roots is −ba=−−43=43-\dfrac ba=-\dfrac{-4}{3}=\dfrac43.

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The remainder when 4x3−3x2+24x^3 - 3x^2 + 2 is divided by x−2x - 2 is ……… (a) 20 (b) 22 (c) 16 (d) 24

Answer

(b) 22

By the remainder theorem, the remainder is f(2)f(2):

4(8)−3(4)+2=32−12+2=224(8)-3(4)+2=32-12+2=22

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The maximum value of 3cos⁡θ+4sin⁡θ3\cos\theta + 4\sin\theta is ……. (a) 3 (b) 4 (c) 5 (d) 7

Answer

(c) 5

The maximum of acos⁡θ+bsin⁡θa\cos\theta+b\sin\theta is a2+b2=9+16=5\sqrt{a^2+b^2}=\sqrt{9+16}=5.

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If tan⁡θ+sin⁡θ=m\tan\theta + \sin\theta = m and tan⁡θ−sin⁡θ=n\tan\theta - \sin\theta = n, then m2−n2=m^2 - n^2 = ………… (a) 4mn4mn (b) 4mn4\sqrt{mn} (c) 2mn2\sqrt{mn} (d) m2+n2m^2 + n^2

Answer

(b) 4mn4\sqrt{mn}

m2−n2=(m+n)(m−n)=(2tan⁡θ)(2sin⁡θ)=4tan⁡θsin⁡θm^2-n^2=(m+n)(m-n)=(2\tan\theta)(2\sin\theta)=4\tan\theta\sin\theta

mn=tan⁡2θ−sin⁡2θ=tan⁡2θ(1−cos⁡2θ)=tan⁡2θsin⁡2θmn=\tan^2\theta-\sin^2\theta=\tan^2\theta(1-\cos^2\theta)=\tan^2\theta\sin^2\theta

so mn=tan⁡θsin⁡θ\sqrt{mn}=\tan\theta\sin\theta and m2−n2=4mnm^2-n^2=4\sqrt{mn}.

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If cos⁡θ−sin⁡θ=2sin⁡θ\cos\theta - \sin\theta = \sqrt{2}\sin\theta, then cos⁡θ+sin⁡θ=\cos\theta + \sin\theta = ……….. (a) 2cos⁡θ\sqrt{2}\cos\theta (b) 2sin⁡θ\sqrt{2}\sin\theta (c) 2cos⁡θ2\cos\theta (d) −2cos⁡θ-\sqrt{2}\cos\theta

Answer

(a) 2cos⁡θ\sqrt2\cos\theta

From cos⁡θ−sin⁡θ=2sin⁡θ\cos\theta-\sin\theta=\sqrt2\sin\theta we get cos⁡θ=(2+1)sin⁡θ\cos\theta=(\sqrt2+1)\sin\theta, so

sin⁡θ=cos⁡θ2+1=(2−1)cos⁡θ\sin\theta=\frac{\cos\theta}{\sqrt2+1}=(\sqrt2-1)\cos\theta

cos⁡θ+sin⁡θ=cos⁡θ+(2−1)cos⁡θ=2cos⁡θ\cos\theta+\sin\theta=\cos\theta+(\sqrt2-1)\cos\theta=\sqrt2\cos\theta

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If 13,y1,y2,9\frac{1}{3}, y_1, y_2, 9 are in G.P. then the value of y2y_2 is ……… (a) 3 (b) 6 (c) 1 (d) None of above

Answer

(a) 3

The common ratio satisfies r3=91/3=27r^3=\dfrac{9}{1/3}=27, so r=3r=3. Then y1=1y_1=1 and y2=13⋅32=3y_2=\dfrac13\cdot3^2=3.

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The value of sin⁡(A+B)⋅sin⁡(A−B)\sin(A+B)\cdot\sin(A-B) is ……… (a) sin⁡(A2−B2)\sin(A^2 - B^2) (b) sin⁡2(A−B)\sin^2(A-B) (c) sin⁡2A−sin⁡2B\sin^2 A - \sin^2 B (d) cos⁡2A−cos⁡2B\cos^2 A - \cos^2 B

Answer

(c) sin⁡2A−sin⁡2B\sin^2A-\sin^2B

sin⁡(A+B)sin⁡(A−B)=(sin⁡Acos⁡B)2−(cos⁡Asin⁡B)2=sin⁡2A(1−sin⁡2B)−(1−sin⁡2A)sin⁡2B=sin⁡2A−sin⁡2B\sin(A+B)\sin(A-B)=(\sin A\cos B)^2-(\cos A\sin B)^2=\sin^2A(1-\sin^2B)-(1-\sin^2A)\sin^2B=\sin^2A-\sin^2B

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If acos⁡θ+bsin⁡θ=ma\cos\theta + b\sin\theta = m and asin⁡θ−bcos⁡θ=na\sin\theta - b\cos\theta = n then the value of a2+b2a^2 + b^2 is ………. (a) m+nm + n (b) mnmn (c) m2+n2m^2 + n^2 (d) mn\sqrt{mn}

Answer

(c) m2+n2m^2+n^2

m2+n2=(acos⁡θ+bsin⁡θ)2+(asin⁡θ−bcos⁡θ)2=a2(cos⁡2θ+sin⁡2θ)+b2(sin⁡2θ+cos⁡2θ)=a2+b2m^2+n^2=(a\cos\theta+b\sin\theta)^2+(a\sin\theta-b\cos\theta)^2=a^2(\cos^2\theta+\sin^2\theta)+b^2(\sin^2\theta+\cos^2\theta)=a^2+b^2

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Which of the following matrices is a scalar matrix? (a) (1111)\begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} (b) (5005)\begin{pmatrix} 5 & 0 \\ 0 & 5 \end{pmatrix} (c) (1004)\begin{pmatrix} 1 & 0 \\ 0 & 4 \end{pmatrix} (d) (0210)\begin{pmatrix} 0 & 2 \\ 1 & 0 \end{pmatrix}

Answer

(b) (5005)\begin{pmatrix}5&0\\0&5\end{pmatrix}

A scalar matrix is a diagonal matrix whose diagonal entries are all equal, and this one has both diagonal entries equal to 5 with zeros elsewhere.

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The number of subsets of the set {2,3,5}\{2, 3, 5\} is …….. (a) 3 (b) 6 (c) 8 (d) 10

Answer

(c) 8

A set with nn elements has 2n2^n subsets, so 23=82^3=8.

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If the price of milk is reduced from Rs. 22.50 per litre to Rs. 18 per litre, in what proportion is the water mixed? (a) 1 : 4 (b) 4 : 1 (c) 4 : 3 (d) 3 : 4

Answer

(a) 1 : 4

Let the mixture contain 1 litre of milk-and-water. Its price is Rs 18 against Rs 22.50 for pure milk, so the milk fraction is 1822.5=45\dfrac{18}{22.5}=\dfrac45 and the water fraction is 15\dfrac15.

Water : milk =1:4=1:4.

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If A=(123025003)A = \begin{pmatrix} 1 & 2 & 3 \\ 0 & 2 & 5 \\ 0 & 0 & 3 \end{pmatrix}, the name of this matrix is …… (a) Identity matrix (b) Diagonal matrix (c) Triangular matrix (d) Symmetric matrix

Answer

(c) Triangular matrix

All entries below the main diagonal are zero, so AA is an upper triangular matrix. It is not diagonal (the entries above the diagonal are non-zero), not an identity matrix, and not symmetric (a12=2≠a21=0a_{12}=2\ne a_{21}=0).

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If A=[0110]A = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}, then A4=A^4 = ……….. (a) [1001]\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} (b) [1100]\begin{bmatrix} 1 & 1 \\ 0 & 0 \end{bmatrix} (c) [0011]\begin{bmatrix} 0 & 0 \\ 1 & 1 \end{bmatrix} (d) [0110]\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}

Answer

(a) [1001]\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}

A2=[0110][0110]=[1001]=IA^2=\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}=\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}=I

so A4=(A2)2=I2=IA^4=(A^2)^2=I^2=I.

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In an A.P. the pthp^{th} term is qq and the (p+q)th(p+q)^{th} term is 0, then the common difference is ……. (a) −p-p (b) qq (c) −1-1 (d) 0

Answer

(c) −1-1

a+(p−1)d=qa+(p-1)d=q and a+(p+q−1)d=0a+(p+q-1)d=0. Subtracting the first from the second gives qd=−qqd=-q, so d=−1d=-1.

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The sum of the first nn natural numbers is 15\frac{1}{5} times the sum of their squares, then n=n = ……… (a) 5 (b) 6 (c) 7 (d) 8

Answer

(c) 7

n(n+1)2=15⋅n(n+1)(2n+1)6⇒12=2n+130⇒2n+1=15⇒n=7.\frac{n(n+1)}{2}=\frac15\cdot\frac{n(n+1)(2n+1)}{6}\Rightarrow \frac12=\frac{2n+1}{30}\Rightarrow 2n+1=15\Rightarrow n=7.

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The equation ax2+2hxy+by2+2gx+2fy+c=0ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 represents a circle if ……… (a) h=0h = 0 (b) a=ba = b (c) a=ba = b and h=0h = 0 (d) a=b=ha = b = h

Answer

(c) a=ba = b and h=0h = 0

A circle has equal coefficients of x2x^2 and y2y^2 and no xyxy term, so a=ba=b and h=0h=0 (together with a real, positive radius).

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The circumcentre of the triangle whose vertices are (0,0)(0, 0), (6,0)(6, 0) and (0,4)(0, 4) is ……… (a) (2,0)(2, 0) (b) (3,0)(3, 0) (c) (0,3)(0, 3) (d) (3,2)(3, 2)

Answer

(d) (3,2)(3, 2)

The triangle has a right angle at (0,0)(0,0), so the circumcentre is the midpoint of the hypotenuse joining (6,0)(6,0) and (0,4)(0,4): (6+02,0+42)=(3,2).\left(\frac{6+0}{2},\frac{0+4}{2}\right)=(3,2).

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A,B,CA, B, C are the vertices of a triangle, then AB→+BC→+CA→\overrightarrow{AB} + \overrightarrow{BC} + \overrightarrow{CA} is equal to …………. (a) 0 (b) 1 (c) 3 (d) None

Answer

(a) 0

AB→+BC→=AC→\overrightarrow{AB}+\overrightarrow{BC}=\overrightarrow{AC}, and AC→+CA→=0⃗\overrightarrow{AC}+\overrightarrow{CA}=\vec 0. The sides taken round a closed triangle sum to the zero vector.

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If a⃗,b⃗\vec{a}, \vec{b} and c⃗\vec{c} are unit vectors such that a⃗+b⃗−c⃗=0\vec{a} + \vec{b} - \vec{c} = 0, then the angle between a⃗\vec{a} and b⃗\vec{b} is ……. (a) π6\frac{\pi}{6} (b) π3\frac{\pi}{3} (c) π2\frac{\pi}{2} (d) 2π3\frac{2\pi}{3}

Answer

(d) 2π3\frac{2\pi}{3}

a⃗+b⃗=c⃗\vec a+\vec b=\vec c, so ∣a⃗+b⃗∣2=∣c⃗∣2|\vec a+\vec b|^2=|\vec c|^2: 1+1+2cos⁡θ=1⇒cos⁡θ=−12⇒θ=2π3.1+1+2\cos\theta=1\Rightarrow\cos\theta=-\frac12\Rightarrow\theta=\frac{2\pi}{3}.

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The normal form of the equation of the line given by 3x+4y+7=03x + 4y + 7 = 0 is xcos⁡α+ysin⁡α=px\cos\alpha + y\sin\alpha = p where ……… (a) tan⁡α=43,p=−75\tan\alpha = \frac{4}{3}, p = -\frac{7}{5} (b) tan⁡α=−34,p=−75\tan\alpha = -\frac{3}{4}, p = -\frac{7}{5} (c) tan⁡α=34,p=−75\tan\alpha = \frac{3}{4}, p = -\frac{7}{5} (d) tan⁡α=34,p=75\tan\alpha = \frac{3}{4}, p = \frac{7}{5}

Answer

(a) tan⁡α=43,p=−75\tan\alpha = \frac{4}{3}, p = -\frac{7}{5}

Write 3x+4y=−73x+4y=-7 and divide by 32+42=5\sqrt{3^2+4^2}=5: 35x+45y=−75.\frac35x+\frac45y=-\frac75. So cos⁡α=35\cos\alpha=\frac35, sin⁡α=45\sin\alpha=\frac45, giving tan⁡α=43\tan\alpha=\frac43 and p=−75p=-\frac75, which matches option (a).

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The minimum value of 3cos⁡θ+4sin⁡θ+83\cos\theta + 4\sin\theta + 8 is ……… (a) 9 (b) 7 (c) 5 (d) 3

Answer

(d) 3

3cos⁡θ+4sin⁡θ3\cos\theta+4\sin\theta ranges over [−5,5][-5,5] since 32+42=5\sqrt{3^2+4^2}=5. The minimum of the expression is −5+8=3-5+8=3.

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If xx and yy are rational numbers such that xy\sqrt{xy} is irrational, then x+y\sqrt{x} + \sqrt{y} is ……. (a) Rational (b) Irrational (c) Non-real (d) None Of Above

Answer

(b) Irrational

Suppose x+y=r\sqrt x+\sqrt y=r were rational. Squaring, x+y+2xy=r2x+y+2\sqrt{xy}=r^2, so xy=r2−x−y2\sqrt{xy}=\frac{r^2-x-y}{2} would be rational, contradicting the given condition. Hence x+y\sqrt x+\sqrt y is irrational.

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  • 2080 · Science Model · 1 mark
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The L.C.M. of x3+2x2−x−2x^3 + 2x^2 - x - 2 and x3+x2−4x−4x^3 + x^2 - 4x - 4 is ……… (a) (x+1)(x−2)(x+1)(x-2) (b) (x+1)(x−1)(x+2)(x+1)(x-1)(x+2) (c) (x+1)(x+2)(x−2)(x+1)(x+2)(x-2) (d) (x2−1)(x2−4)(x^2-1)(x^2-4)

Answer

(d) (x2−1)(x2−4)(x^2-1)(x^2-4)

x3+2x2−x−2=x2(x+2)−(x+2)=(x+2)(x−1)(x+1)x^3+2x^2-x-2=x^2(x+2)-(x+2)=(x+2)(x-1)(x+1) x3+x2−4x−4=x2(x+1)−4(x+1)=(x+1)(x−2)(x+2)x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x+1)(x-2)(x+2) The L.C.M. is (x+1)(x−1)(x+2)(x−2)=(x2−1)(x2−4)(x+1)(x-1)(x+2)(x-2)=(x^2-1)(x^2-4).

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

If 2x=3y=6−z2^x = 3^y = 6^{-z}, then the value of 1x+1y+1z\frac{1}{x} + \frac{1}{y} + \frac{1}{z} equals ……… (a) 0 (b) 1 (c) −1-1 (d) 12

Answer

(a) 0

Let 2x=3y=6−z=k2^x=3^y=6^{-z}=k. Then 2=k1/x2=k^{1/x}, 3=k1/y3=k^{1/y}, 6=k−1/z6=k^{-1/z}. Since 6=2⋅36=2\cdot3, −1z=1x+1y⇒1x+1y+1z=0.-\frac1z=\frac1x+\frac1y\Rightarrow\frac1x+\frac1y+\frac1z=0.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

A number of two digits exceeds four times the sum of its digits by 3. If 36 is added to the number, the digits are reversed. Then the number is …….. (a) 27 (b) 63 (c) 59 (d) 72

Answer

(c) 59

Let the number be 10a+b10a+b. Then 10a+b=4(a+b)+3⇒2a−b=110a+b=4(a+b)+3\Rightarrow 2a-b=1. Also 10a+b+36=10b+a⇒b−a=410a+b+36=10b+a\Rightarrow b-a=4. Solving, a=5a=5, b=9b=9.

Check: 4(14)+3=594(14)+3=59 and 59+36=9559+36=95.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

If the diagonals of a rhombus are 10 cm and 8 cm respectively, then the area of the rhombus is ……. (a) 80 cm280\ \text{cm}^2 (b) 40 cm240\ \text{cm}^2 (c) 36 cm236\ \text{cm}^2 (d) 60 cm260\ \text{cm}^2

Answer

(b) 40 cm240\ \text{cm}^2

Area=12d1d2=12×10×8=40 cm2.\text{Area}=\frac12d_1d_2=\frac12\times10\times8=40\ \text{cm}^2.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

If the mean of 2,6,x,10,142, 6, x, 10, 14 is 8, then its median is ……….. (a) 8 (b) 8.5 (c) 9 (d) 10

Answer

(a) 8

2+6+x+10+145=8⇒x+32=40⇒x=8\frac{2+6+x+10+14}{5}=8\Rightarrow x+32=40\Rightarrow x=8. The ordered data 2,6,8,10,142,6,8,10,14 has median 88.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

Which of the following is a polynomial? (a) x32−5x2\frac{x^3}{2} - \frac{5}{x^2} (b) 3x−1\sqrt{3}x - 1 (c) x2+4x3/2xx^2 + \frac{4x^{3/2}}{\sqrt{x}} (d) x+1x−1\frac{x+1}{x-1}

Answer

(b) 3x−1\sqrt{3}x - 1

A polynomial has only non-negative integer powers of xx. 3x−1\sqrt3x-1 qualifies (the coefficient 3\sqrt3 is allowed). The others contain x−2x^{-2}, a fractional power, or a variable denominator. In (c), 4x3/2x=4x\frac{4x^{3/2}}{\sqrt x}=4x simplifies to a polynomial term, but the expression as written is not in polynomial form, so (b) is the clear choice.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

Zero of the zero polynomial is ……. (a) 1 (b) any real number (c) not defined (d) 0

Answer

(b) any real number

The zero polynomial is p(x)=0p(x)=0, and p(c)=0p(c)=0 for every real cc, so every real number is a zero of it.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

Mathematician Euclid belongs to the country ……….. (a) Babylonian (b) Greece (c) Germany (d) France

Answer

(b) Greece

Euclid was a Greek mathematician (of Alexandria), known as the "father of geometry" and author of The Elements.

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  • 2080 · Science Model · 1 mark
  • 2081 · Science Model · 1 mark

"Lines are parallel if they do not intersect" is stated in the term of …….. (a) Postulate (b) a definition (c) an axiom (d) a proof

Answer

(b) a definition

The statement explains what the term "parallel lines" means, so it is a definition, not a postulate, axiom or proof.

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  • 2080 · Management Model · 1 mark
  • 2083 · Management Model · 1 mark

If x+1x=4x + \frac{1}{x} = 4, then the value of x2+1x2x^2 + \frac{1}{x^2} is ……….. (a) 16 (b) 14 (c) 20 (d) 18

Answer

(b) 14

x2+1x2=(x+1x)2−2=42−2=14.x^2 + \frac{1}{x^2} = \left(x + \frac1x\right)^2 - 2 = 4^2 - 2 = 14.

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  • 2079 · Management and Humanities Model
  • 2077 · Management Model

In a throw of a die, the probability of getting an even number is ……… (a) 13\frac{1}{3} (b) 12\frac{1}{2} (c) 23\frac{2}{3} (d) 16\frac{1}{6}

Answer

(b) 12\frac{1}{2}

Even numbers: 2, 4, 6, so P=36=12P = \frac{3}{6} = \frac12.

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  • 2079 · Law Model · 1 mark
  • 2080 · Law Model · 1 mark

What is 10% of 20% of 200? (a) 40 (b) 4 (c) 0.4 (d) 400

Answer

(b) 4

20% of 200=40,10% of 40=420\% \text{ of } 200 = 40,\qquad 10\% \text{ of } 40 = 4

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  • 2079 · Law Model · 1 mark
  • 2080 · Law Model · 1 mark

If mean is 16 and median is 15, what is the value of mode? (a) 15 (b) 1 (c) 14 (d) 4

Answer

(c) 14 (nearest option)

By the empirical relation, Mode=3 Median−2 Mean=3(15)−2(16)=45−32=13\text{Mode} = 3\,\text{Median} - 2\,\text{Mean} = 3(15) - 2(16) = 45 - 32 = 13. The exact value 13 is not listed, so the closest option, 14, is the intended choice.

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  • 2079 · Management and Humanities Model

The arithmetic mean of the first five natural numbers is …….. (a) 4 (b) 5 (c) 3 (d) 2

Similar questions: What is the arithmetic mean of the first 10 (2077 · Management Model)

Answer

(c) 3

Mean=1+2+3+4+55=155=3.\text{Mean} = \frac{1+2+3+4+5}{5} = \frac{15}{5} = 3.

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  • 2079 · Management and Humanities Model

The length of each side of an equilateral triangle having area 163 cm216\sqrt{3}\ \text{cm}^2 is ……. (a) 10 cm (b) 4 cm (c) 6 cm (d) 8 cm

Similar questions: Area of an equilateral triangle having side a is (2077 · Management Model)

Answer

(d) 8 cm

34a2=163⇒a2=64⇒a=8 cm.\frac{\sqrt3}{4}a^2 = 16\sqrt3 \Rightarrow a^2 = 64 \Rightarrow a = 8 \text{ cm}.

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  • 2077 · Management Model

Area of an equilateral triangle having side aa is …… (a) 32a2\frac{\sqrt{3}}{2}a^2 (b) 32 a2\sqrt{\frac{3}{2}}\,a^2 (c) 34 a2\sqrt{\frac{3}{4}}\,a^2 (d) 34a2\frac{\sqrt{3}}{4}a^2

Similar questions: The length of each side of an equilateral (2079 · Management and Humanities Model)

Answer

(d) 34a2\frac{\sqrt3}{4}a^2

The height is 32a\frac{\sqrt3}{2}a, so the area is 12×a×32a=34a2\frac12\times a\times\frac{\sqrt3}{2}a=\frac{\sqrt3}{4}a^2.

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  • 2077 · Management Model

What is the arithmetic mean of the first 10 natural numbers? (a) 5 (b) 4.5 (c) 5.5 (d) 6

Similar questions: The arithmetic mean of the first five natural (2079 · Management and Humanities Model)

Answer

(c) 5.5

xˉ=1+2+⋯+1010=5510=5.5\bar x=\frac{1+2+\dots+10}{10}=\frac{55}{10}=5.5

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  • 2079 · Management and Humanities Model

Which of the following is an irrational number? (a) 227\frac{22}{7} (b) π\pi (c) 0.333 (d) 4.5679

Answer

(b) π\pi

π\pi is non-terminating and non-recurring, so it cannot be written as a ratio of integers. 227\frac{22}{7}, 0.3330.333 and 4.56794.5679 are rational.

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  • 2079 · Management and Humanities Model

If AA and BB are disjoint sets then A−B=A - B = ……….. (a) AA (b) BB (c) A∩BA \cap B (d) A∪BA \cup B

Answer

(a) AA

Disjoint sets have no common element, so removing BB from AA removes nothing: A−B=AA - B = A.

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  • 2079 · Management and Humanities Model

How many dollars shall we receive for Rs. 12,000 if Rs. 100 is equal to 136 marks and 400 marks is equal to 95 dollars? (a) USD 3786 (b) USD 8763 (c) USD 6783 (d) USD 3876

Answer

(d) USD 3876

Rs 100 = 136 marks, so Rs 12,000 = 120×136=16320120 \times 136 = 16320 marks.

400 marks = 95 dollars, so 16320×95400=40.8×95=3876 dollars.\frac{16320 \times 95}{400} = 40.8 \times 95 = 3876 \text{ dollars}.

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  • 2079 · Management and Humanities Model

What will be the population of a town in 3 years if its present population is 24,000 increasing at 5% annually? (a) 27,378 (b) 27,873 (c) 27,783 (d) 27,387

Answer

(c) 27,783

P=24000(1+5100)3=24000×(1.05)3=24000×1.157625=27783.P = 24000\left(1+\frac{5}{100}\right)^3 = 24000 \times (1.05)^3 = 24000 \times 1.157625 = 27783.

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  • 2079 · Management and Humanities Model

If the side of an equilateral triangle is aa unit, then the area of the triangle is ……… (a) 3a2\sqrt{3}a^2 sq. unit (b) 32a2\frac{\sqrt{3}}{2}a^2 sq. unit (c) 34a2\frac{\sqrt{3}}{4}a^2 sq. unit (d) a2a^2 sq. unit

Answer

(c) 34a2\frac{\sqrt{3}}{4}a^2 sq. unit

The height is a2−a24=32a\sqrt{a^2 - \frac{a^2}{4}} = \frac{\sqrt{3}}{2}a, so area =12⋅a⋅32a=34a2= \frac12 \cdot a \cdot \frac{\sqrt3}{2}a = \frac{\sqrt3}{4}a^2.

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  • 2079 · Management and Humanities Model

The value of (81)0.16×(81)0.09(81)^{0.16} \times (81)^{0.09} is equal to …… (a) 9 (b) 3 (c) 81.25 (d) 27

Answer

(b) 3

Add the powers: (81)0.16+0.09=(81)0.25=(34)1/4=3(81)^{0.16+0.09} = (81)^{0.25} = (3^4)^{1/4} = 3.

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  • 2079 · Management and Humanities Model

The value of the polynomial 4x2−5x+94x^2 - 5x + 9, when x=12x = \frac{1}{2} is …….. (a) 132\frac{13}{2} (b) 152\frac{15}{2} (c) 8 (d) 12\frac{1}{2}

Answer

(b) 152\frac{15}{2}

4(12)2−5(12)+9=1−52+9=10−52=152.4\left(\tfrac12\right)^2 - 5\left(\tfrac12\right) + 9 = 1 - \tfrac52 + 9 = 10 - \tfrac52 = \tfrac{15}{2}.

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  • 2079 · Management and Humanities Model

In △ABC\triangle ABC, if ∠A>∠B\angle A > \angle B, then ………. (a) AB>BCAB > BC (b) BC<ACBC < AC (c) AC>ABAC > AB (d) BC>ACBC > AC

Answer

(d) BC>ACBC > AC

The larger angle has the longer opposite side. BCBC is opposite ∠A\angle A and ACAC is opposite ∠B\angle B, so ∠A>∠B\angle A > \angle B gives BC>ACBC > AC.

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  • 2079 · Management and Humanities Model

Abscissa of a point is negative in ………. (a) I and II quadrants (b) only II quadrant (c) only III quadrant (d) II and III quadrant

Answer

(d) II and III quadrant

The abscissa is the xx-coordinate, which is negative to the left of the yy-axis, that is in the II and III quadrants.

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  • 2079 · Management and Humanities Model

The point which lies on the line y=−3xy = -3x is ……… (a) (2,−7)(2, -7) (b) (3,−6)(3, -6) (c) (3,9)(3, 9) (d) (3,−9)(3, -9)

Answer

(d) (3,−9)(3, -9)

A point lies on y=−3xy=-3x if its coordinates satisfy it. For (3,−9)(3,-9): −3(3)=−9-3(3) = -9. The others fail: (2,−7)(2,-7) needs −6-6, (3,−6)(3,-6) needs −9-9, (3,9)(3,9) needs −9-9.

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  • 2079 · Management and Humanities Model

The equation of the y-axis is of the form ………. (a) y=0y = 0 (b) x=0x = 0 (c) x=yx = y (d) x+y=0x + y = 0

Answer

(b) x=0x = 0

Every point on the yy-axis has xx-coordinate 00.

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  • 2079 · Management and Humanities Model

A quadrilateral which has exactly one pair of parallel sides is called ………. (a) a rectangle (b) a parallelogram (c) a trapezium (d) a rhombus

Answer

(c) a trapezium

A trapezium has exactly one pair of parallel sides; a rectangle, parallelogram and rhombus have two pairs.

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  • 2079 · Management and Humanities Model

ABCD is a rhombus. If ∠ACB=50∘\angle ACB = 50^\circ, then ∠ADB\angle ADB is ………. (a) 50∘50^\circ (b) 60∘60^\circ (c) 45∘45^\circ (d) 40∘40^\circ

Answer

(d) 40∘40^\circ

Diagonals of a rhombus bisect the vertex angles, so ∠BCD=2×50∘=100∘\angle BCD = 2 \times 50^\circ = 100^\circ. Then ∠BAD=100∘\angle BAD = 100^\circ (opposite angles). In △ABD\triangle ABD, AB=ADAB = AD, so ∠ADB=180∘−100∘2=40∘.\angle ADB = \frac{180^\circ - 100^\circ}{2} = 40^\circ.

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  • 2079 · Management and Humanities Model

The diameter of a circle is also ……. (a) secant (b) tangent (c) radius (d) chord

Answer

(d) chord

A diameter is a chord that passes through the centre (and it is the longest chord).

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  • 2079 · Management and Humanities Model

The median of the data 12, 14, 15, 13, 11, 17, 10 is ……… (a) 13 (b) 12 (c) 14 (d) 15

Answer

(a) 13

Arranged in order: 10, 11, 12, 13, 14, 15, 17. There are 7 values, so the median is the 4th value, 13.

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  • 2079 · Management and Humanities Model

A card is drawn from a normal pack of 52 cards. What is the probability that it is a face card? (a) 14\frac{1}{4} (b) 313\frac{3}{13} (c) 113\frac{1}{13} (d) 413\frac{4}{13}

Answer

(b) 313\frac{3}{13}

There are 3×4=123 \times 4 = 12 face cards (J, Q, K in each suit), so P=1252=313P = \frac{12}{52} = \frac{3}{13}.

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  • 2079 · Management and Humanities Model

If x+1x=4x + \frac{1}{x} = 4, then the value of x3+1x3x^3 + \frac{1}{x^3} is ……….. (a) 64 (b) 58 (c) 56 (d) 52

Answer

(d) 52

x3+1x3=(x+1x)3−3(x+1x)=64−12=52.x^3 + \frac1{x^3} = \left(x+\frac1x\right)^3 - 3\left(x+\frac1x\right) = 64 - 12 = 52.

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  • 2079 · Management and Humanities Model

The value of x−1x3⋅x−4\sqrt{x^{-1}\sqrt{x^3 \cdot x^{-4}}} is …….. (a) x−1x^{-1} (b) x−3/4x^{-3/4} (c) x−4/3x^{-4/3} (d) x−1/4x^{-1/4}

Answer

(b) x−3/4x^{-3/4}

Inside: x3⋅x−4=x−1x^3 \cdot x^{-4} = x^{-1}, and x−1=x−1/2\sqrt{x^{-1}} = x^{-1/2}.

Then x−1⋅x−1/2=x−3/2x^{-1}\cdot x^{-1/2} = x^{-3/2}, and x−3/2=x−3/4\sqrt{x^{-3/2}} = x^{-3/4}.

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  • 2079 · Management and Humanities Model

11+xm−n+11+xn−m\frac{1}{1 + x^{m-n}} + \frac{1}{1 + x^{n-m}} is equal to ………. (a) 0 (b) 1 (c) 12\frac{1}{2} (d) am+na^{m+n}

Answer

(b) 1

Let t=xm−nt = x^{m-n}. Then 11+t+11+1t=11+t+tt+1=1+t1+t=1.\frac{1}{1+t} + \frac{1}{1+\frac1t} = \frac{1}{1+t} + \frac{t}{t+1} = \frac{1+t}{1+t} = 1.

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  • 2079 · Management and Humanities Model

If 5a+2b:7a+3b=9:135a + 2b : 7a + 3b = 9 : 13, then a:ba : b is ……… (a) 1 : 2 (b) 2 : 1 (c) 2 : 3 (d) 3 : 2

Answer

(a) 1 : 2

Cross-multiplying: 13(5a+2b)=9(7a+3b)13(5a+2b) = 9(7a+3b), so 65a+26b=63a+27b65a + 26b = 63a + 27b, giving 2a=b2a = b. Hence a:b=1:2a : b = 1 : 2.

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  • 2079 · Management and Humanities Model

If a=21a = 21, b=13b = 13 and c=20c = 20 then the area of triangle ABC is ……… (a) 116 (b) 120 (c) 84 (d) 96

Answer

(b) 120 (nearest option; the exact area is 126 sq. unit)

By Heron's formula, s=21+13+202=27s = \frac{21+13+20}{2} = 27.

Area=27(27−21)(27−13)(27−20)=27⋅6⋅14⋅7=15876=126.\text{Area} = \sqrt{27(27-21)(27-13)(27-20)} = \sqrt{27 \cdot 6 \cdot 14 \cdot 7} = \sqrt{15876} = 126.

Check: with base 21, height h=12h = 12 gives feet at distances 55 and 1616 (5+16=215+16=21) and area 12⋅21⋅12=126\frac12 \cdot 21 \cdot 12 = 126. None of the listed options equals 126, so the printed options appear to contain an error; 120 is the closest.

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  • 2079 · Management and Humanities Model

A cycle of cost Rs. 1,000 is depreciated at 10% p.a., then what will be its value after 1 year? (a) Rs. 950 (b) Rs. 925 (c) Rs. 900 (d) Rs. 875

Answer

(c) Rs. 900

Depreciation is 10%10\% of Rs 1,000 == Rs 100, so the value after 1 year is 1000−100=1000 - 100 = Rs 900.

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  • 2079 · Management and Humanities Model

What is the actual discount amount when 1.25% discount is given on a car marked at Rs. 5,00,000? (a) Rs. 6250 (b) Rs. 6000 (c) Rs. 5850 (d) Rs. 5500

Answer

(a) Rs. 6250

Discount =1.25%×500000=1.25100×500000== 1.25\% \times 500000 = \dfrac{1.25}{100}\times 500000 = Rs 6,250.

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  • 2079 · Management and Humanities Model

P and Q together can do a piece of work in 10 hours but P alone can do it in 15 hours. How many hours would Q alone take to do the same work? (a) 20 hours (b) 25 hours (c) 30 hours (d) 35 hours

Answer

(c) 30 hours

Q's one-hour work =110−115=3−230=130= \dfrac{1}{10}-\dfrac{1}{15}=\dfrac{3-2}{30}=\dfrac{1}{30}, so Q alone takes 30 hours.

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  • 2079 · Management and Humanities Model

H.C.F. of x3−1x^3 - 1 and x4+x2+1x^4 + x^2 + 1 is …….. (a) x−1x - 1 (b) x2−x+1x^2 - x + 1 (c) x2+x+1x^2 + x + 1 (d) x2−x−1x^2 - x - 1

Answer

(c) x2+x+1x^2 + x + 1

x3−1=(x−1)(x2+x+1)x^3-1=(x-1)(x^2+x+1) x4+x2+1=(x2+1)2−x2=(x2+x+1)(x2−x+1)x^4+x^2+1=(x^2+1)^2-x^2=(x^2+x+1)(x^2-x+1)

The common factor is x2+x+1x^2+x+1.

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  • 2079 · Management and Humanities Model

The value of (827)−23\left(\frac{8}{27}\right)^{-\frac{2}{3}} is …….. (a) 94\frac{9}{4} (b) 49\frac{4}{9} (c) 32\frac{3}{2} (d) 23\frac{2}{3}

Answer

(a) 94\dfrac{9}{4}

(827)−23=(278)23=(3323)23=3222=94\left(\frac{8}{27}\right)^{-\frac23}=\left(\frac{27}{8}\right)^{\frac23}=\left(\frac{3^3}{2^3}\right)^{\frac23}=\frac{3^2}{2^2}=\frac94

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  • 2079 · Management and Humanities Model

If N=50N = 50 and ∑fx=750\sum fx = 750, then the number of terms (N)=(N) = …….. (a) 45 (b) 30 (c) 15 (d) 5

Answer

(c) 15

The quantity that can be found from the given data is the mean: xˉ=∑fxN=75050=15\bar{x}=\frac{\sum fx}{N}=\frac{750}{50}=15

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  • 2079 · Management and Humanities Model

If 3 is subtracted from the square of a number, the remainder is 6, then the number is …….. (a) ±6\pm 6 (b) ±5\pm 5 (c) ±4\pm 4 (d) ±3\pm 3

Answer

(d) ±3\pm 3

Let the number be xx. Then x2−3=6⇒x2=9⇒x=±3x^2-3=6\Rightarrow x^2=9\Rightarrow x=\pm 3.

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  • 2079 · Law Model · 1 mark

13\frac{1}{3} of a right angle is (a) 60∘60^\circ (b) 45∘45^\circ (c) 30∘30^\circ (d) 90∘90^\circ

Answer

(c) 30∘30^\circ

A right angle is 90∘90^\circ, so 13×90∘=30∘\frac{1}{3}\times 90^\circ = 30^\circ.

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  • 2079 · Law Model · 1 mark

The perimeter of a rectangle with length 50 cm and breadth 25 cm is (a) 1250 cm (b) 150 cm (c) 75 cm (d) none

Answer

(b) 150 cm

P=2(l+b)=2(50+25)=150 cmP = 2(l+b) = 2(50+25) = 150 \text{ cm}

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  • 2079 · Law Model · 1 mark

By selling 12 books for the cost of 15 books, how much is the profit? (a) 20% (b) 25% (c) 24% (d) 15%

Answer

(b) 25%

Let the cost of one book be Rs 1. Then the cost of 12 books is Rs 12, and the selling price of 12 books equals the cost of 15 books, Rs 15.

Profit=15−1212×100%=25%\text{Profit} = \frac{15-12}{12}\times 100\% = 25\%

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  • 2079 · Law Model · 1 mark

If Indian Currency 100 is equivalent to Nepali Rupees 160, how much Indian Currency is equivalent to Rs. 100? (a) IC 62.5 (b) IC 67.5 (c) IC 65.2 (d) IC 58.5

Answer

(a) IC 62.5

Rs 160 = IC 100, so Rs 100 = 100160×100=62.5\frac{100}{160}\times 100 = 62.5 IC.

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  • 2077 · Management Model

A−B‾A - \overline{B} equals ……….. (a) AA (b) A∪BA \cup B (c) A∩BA \cap B (d) A∩B‾\overline{A \cap B}

Answer

(c) A∩BA \cap B

A−B‾A - \overline{B} means elements of AA that are not in B‾\overline{B}, that is, elements of AA that are in BB. So A−B‾=A∩BA - \overline{B} = A \cap B.

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  • 2077 · Management Model

If n(A)=55%n(A) = 55\%, n(B)=65%n(B) = 65\% and n(A∩B)=35%n(A \cap B) = 35\% then n(A∪B‾)=n(\overline{A \cup B}) = ……….. (a) 5% (b) 10% (c) 15% (d) 20%

Answer

(c) 15%

n(A∪B)=55+65−35=85%n(A\cup B)=55+65-35=85\%

n(A∪B‾)=100−85=15%n(\overline{A\cup B})=100-85=15\%

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  • 2077 · Management Model

The number of subsets of a set containing nn elements is …… (a) nn (b) 2n2n (c) 2n2^n (d) 2n−12^{n-1}

Answer

(c) 2n2^n

Each of the nn elements is either in a subset or not, giving 2×2×⋯×2=2n2\times2\times\cdots\times2=2^n subsets.

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  • 2077 · Management Model

The compound interest on Rs. 2000 in 3 years at 5% per annum is …….. (a) Rs. 315.25 (b) Rs. 300 (c) Rs. 328 (d) Rs. 351.50

Answer

(a) Rs. 315.25

A=2000(1+5100)3=2000×1.157625=Rs. 2315.25A=2000\left(1+\frac{5}{100}\right)^3=2000\times1.157625=\text{Rs. }2315.25

CI=A−P=2315.25−2000=Rs. 315.25CI=A-P=2315.25-2000=\text{Rs. }315.25

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  • 2077 · Management Model

In △PQR\triangle PQR, if ∠P>∠Q\angle P > \angle Q, then …….. (a) QR<PRQR < PR (b) QR>PRQR > PR (c) PQ>QRPQ > QR (d) PQ<QRPQ < QR

Answer

(b) QR>PRQR > PR

The larger angle has the larger side opposite it. QRQR is opposite ∠P\angle P and PRPR is opposite ∠Q\angle Q, so ∠P>∠Q\angle P>\angle Q gives QR>PRQR>PR.

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  • 2077 · Management Model

The point which lies on the line y=−3xy = -3x is …….. (a) (1,3)(1, 3) (b) (1,−3)(1, -3) (c) (3,1)(3, 1) (d) (3,−1)(3, -1)

Answer

(b) (1,−3)(1,-3)

Put x=1x=1: y=−3(1)=−3y=-3(1)=-3, so (1,−3)(1,-3) satisfies y=−3xy=-3x. The others do not: (1,3)(1,3) gives −3≠3-3\ne3, (3,1)(3,1) gives −9≠1-9\ne1, (3,−1)(3,-1) gives −9≠−1-9\ne-1.

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  • 2077 · Management Model

If x+1x=5x + \frac{1}{x} = 5, then the value of x2+1x2x^2 + \frac{1}{x^2} is …….. (a) 25 (b) 20 (c) 23 (d) 27

Answer

(c) 23

x2+1x2=(x+1x)2−2=25−2=23x^2+\frac1{x^2}=\left(x+\frac1x\right)^2-2=25-2=23

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  • 2077 · Management Model

The volume of a ball is 38808 cm338808\ \text{cm}^3, then the radius is ……. (a) 7 cm (b) 14 cm (c) 21 cm (d) 28 cm

Answer

(c) 21 cm

43πr3=38808⇒r3=38808×3×74×22=441×21=9261\frac43\pi r^3=38808\Rightarrow r^3=\frac{38808\times3\times7}{4\times22}=441\times21=9261

r=92613=21 cmr=\sqrt[3]{9261}=21\text{ cm}

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  • 2077 · Management Model

The value of (64)−13=\sqrt[3]{\sqrt{(64)^{-1}}} = ……. (a) 1 (b) 12\frac{1}{2} (c) 2 (d) 4

Answer

(b) 12\frac12

64−1=18,183=12\sqrt{64^{-1}}=\frac18,\qquad \sqrt[3]{\frac18}=\frac12

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  • 2077 · Management Model

Which of the following numbers is an irrational? (a) 2\sqrt{2} (b) π\pi (c) ee (d) all of these

Answer

(d) all of these

2\sqrt2, π\pi and ee are all non-terminating, non-repeating decimals, so each is irrational.

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  • 2077 · Management Model

If a number is added to its square the result is 30, then the number is …… (a) 4 (b) 5 (c) 6 (d) 7

Answer

(b) 5

n+n2=30⇒n2+n−30=0⇒(n+6)(n−5)=0n+n^2=30\Rightarrow n^2+n-30=0\Rightarrow(n+6)(n-5)=0

Among the options, n=5n=5 (check: 5+25=305+25=30).

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  • 2077 · Management Model

The area of the trapezium ABCD (AB parallel to DC, AB = 4 cm, DC = 6 cm, and the distance between the parallel sides 3 cm) is ………. (a) 15 cm215\ \text{cm}^2 (b) 30 cm230\ \text{cm}^2 (c) 60 cm260\ \text{cm}^2 (d) none

Answer

(a) 15 cm215\ \text{cm}^2

A=12(AB+DC)×h=12(4+6)×3=15 cm2A=\frac12(AB+DC)\times h=\frac12(4+6)\times3=15\text{ cm}^2

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  • 2077 · Management Model

The angle in a semi-circle is a ……. (a) complementary (b) supplementary (c) half of complementary (d) none of these

Answer

(d) none of these

The angle in a semi-circle is a right angle, 90∘90^\circ. It is not supplementary (180∘180^\circ) and not half of complementary (45∘45^\circ), so none of (a) to (c) fits.

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  • 2077 · Management Model

Every whole number is ……….. (a) real number (b) integers (c) rational number (d) all of these

Answer

(d) all of these

Whole numbers 0,1,2,…0,1,2,\dots are integers, hence rational (n=n1n=\frac{n}{1}), hence real.

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  • 2077 · Management Model

The area of the triangle whose sides are 5 cm, 12 cm and 13 cm is ……. (a) 60 cm260\ \text{cm}^2 (b) 40 cm240\ \text{cm}^2 (c) 30 cm230\ \text{cm}^2 (d) 20 cm220\ \text{cm}^2

Answer

(c) 30 cm230\ \text{cm}^2

Since 52+122=1325^2+12^2=13^2, it is a right triangle, so area =12×5×12=30 cm2=\frac12\times5\times12=30\ \text{cm}^2.

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  • 2077 · Management Model

Two sides of a triangle are 4 cm and 1.5 cm, the length of the third side can't be …… (a) 2.6 cm (b) 2.7 cm (c) 2.8 cm (d) 2.4 cm

Answer

(d) 2.4 cm

The third side cc must satisfy 4−1.5<c<4+1.54-1.5<c<4+1.5, i.e. 2.5<c<5.52.5<c<5.5. Only 2.4 cm lies outside this range.

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  • 2077 · Management Model

L.C.M. of x3−y3x^3 - y^3 and x4+x2y2+y4x^4 + x^2y^2 + y^4 is …….. (a) (x−y)(x - y) (b) x2+xy+y2x^2 + xy + y^2 (c) (x−y)(x4+x2y2+y4)(x - y)(x^4 + x^2y^2 + y^4) (d) x2−xy+y2x^2 - xy + y^2

Answer

(c) (x−y)(x4+x2y2+y4)(x - y)(x^4 + x^2y^2 + y^4)

x3−y3=(x−y)(x2+xy+y2),x4+x2y2+y4=(x2+xy+y2)(x2−xy+y2)x^3-y^3=(x-y)(x^2+xy+y^2),\qquad x^4+x^2y^2+y^4=(x^2+xy+y^2)(x^2-xy+y^2)

LCM =(x−y)(x2+xy+y2)(x2−xy+y2)=(x−y)(x4+x2y2+y4)=(x-y)(x^2+xy+y^2)(x^2-xy+y^2)=(x-y)(x^4+x^2y^2+y^4).

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  • 2077 · Management Model

Simplify: 3x+2−3x8⋅3x\frac{3^{x+2} - 3^x}{8 \cdot 3^x} (a) 1 (b) −1-1 (c) 0 (d) none of these

Answer

(a) 1

3x+2−3x8⋅3x=3x(9−1)8⋅3x=1\frac{3^{x+2}-3^x}{8\cdot3^x}=\frac{3^x(9-1)}{8\cdot3^x}=1

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  • 2077 · Management Model

Which of the following represents the degree of f(x,y)=x3y2+2x2y+4x4f(x, y) = x^3y^2 + 2x^2y + 4x^4? (a) 4 (b) 5 (c) 3 (d) 11

Answer

(b) 5

The degrees of the terms are 3+2=53+2=5, 2+1=32+1=3 and 44. The highest is 5.

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  • 2077 · Management Model

A man earns Rs. 7,500 and spends Rs. 5,000 in a month. What percent does he save? (a) 25% (b) 1003%\frac{100}{3}\% (c) 2003%\frac{200}{3}\% (d) none of these

Answer

(b) 1003%\frac{100}{3}\%

Savings == Rs 7,500 −- Rs 5,000 == Rs 2,500, so saving percent =25007500×100=1003%=\frac{2500}{7500}\times100=\frac{100}{3}\%.

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  • 2077 · Management Model

Two types of rice costing Rs. 21 per kg and Rs. 30 per kg are mixed in the ratio of 4 : 5, then the cost per kg of the mixture is …… (a) Rs. 24 (b) Rs. 25 (c) Rs. 26 (d) Rs. 27

Answer

(c) Rs. 26

4×21+5×304+5=84+1509=2349=26\frac{4\times21+5\times30}{4+5}=\frac{84+150}{9}=\frac{234}{9}=26

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  • 2077 · Management Model

In what time will a sum of money double itself at 8% p.a.? (a) 10 yrs. (b) 12.5 yrs. (c) 15 yrs. (d) 17.5 yrs.

Answer

(b) 12.5 yrs.

To double, interest == principal, so P=P×8×T100P=\frac{P\times8\times T}{100}, giving T=1008=12.5T=\frac{100}{8}=12.5 years.

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  • 2077 · Management Model

Given that Rs. 270 = £ 2 and £ 5 = USD 9.12, then USD 170 equals ….. (a) 12852.23 (b) 12258.23 (c) 12582.23 (d) none

Answer

(c) 12582.23

Rs 270 == £2, so £1 == Rs 135. Also £5 =USD9.12=USD 9.12, so USD170=170×59.12USD 170=\frac{170\times5}{9.12} £ =93.2018=93.2018 £.

Rs value =93.2018×135≈12582.2=93.2018\times135\approx12582.2, which matches option (c) 12582.23.

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  • 2077 · Management Model

If a:b=2:3a : b = 2 : 3, then (6a+7b):(9a+8b)(6a + 7b) : (9a + 8b) equals …….. (a) 14 : 11 (b) 11 : 14 (c) 10 : 13 (d) 13 : 10

Answer

(b) 11 : 14

Let a=2k, b=3ka=2k,\ b=3k. Then 6a+7b=12k+21k=33k6a+7b=12k+21k=33k and 9a+8b=18k+24k=42k9a+8b=18k+24k=42k.

33k:42k=11:1433k:42k=11:14

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  • 2077 · Management Model

The value of xx if 4:x::7:424 : x :: 7 : 42 is ……. (a) 24 (b) 18 (c) 14 (d) 28

Answer

(a) 24

4:x::7:424:x::7:42 gives 4x=742\frac4x=\frac7{42}, so x=4×427=24x=\frac{4\times42}{7}=24.

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  • 2077 · Management Model

If Rs. 12,750 is left after paying an income tax at the rate of 15% without any allowances, find the income … (a) Rs. 14,000 (b) Rs. 14,500 (c) Rs. 15,000 (d) Rs. 15,500

Answer

(c) Rs. 15,000

After 15% tax, 85% of the income remains: 0.85I=127500.85I=12750, so I=127500.85=I=\frac{12750}{0.85}= Rs 15,000.

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  • 2077 · Management Model

Ordinate of a point is negative in ……. (a) IInd and IIIrd quadrant (b) only in IInd quadrant (c) only in IIIrd quadrant (d) IIIrd and IVth quadrant

Answer

(d) IIIrd and IVth quadrant

The ordinate is the yy-coordinate, which is negative below the xx-axis, i.e. in the third and fourth quadrants.

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  • 2077 · Management Model

If N=50N = 50 and mean =15= 15 then ∑fx\sum fx equals ……… (a) 150 (b) 65 (c) 750 (d) 450

Answer

(c) 750

xˉ=∑fxN⇒∑fx=15×50=750\bar x=\frac{\sum fx}{N}\Rightarrow \sum fx=15\times50=750

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  • 2077 · Management Model

The value of cos⁡30∘\cos 30^\circ is ….. (a) 12\frac{1}{2} (b) 32\frac{\sqrt{3}}{2} (c) 12\frac{1}{\sqrt{2}} (d) 13\frac{1}{\sqrt{3}}

Answer

(b) 32\frac{\sqrt{3}}{2}

Standard value: cos⁡30∘=32\cos30^\circ=\frac{\sqrt3}{2}.

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  • 2077 · Management Model

In how many ways can 10 persons shake their hands without repetition? (a) 45 (b) 50 (c) 55 (d) 60

Answer

(a) 45

Each handshake involves a pair of persons: (102)=10×92=45\binom{10}{2}=\frac{10\times9}{2}=45.

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  • 2077 · Management Model

(2.1)2−(1.9)2(2.1)^2 - (1.9)^2 equals ……. (a) 0.4 (b) 0.3 (c) 0.7 (d) 0.8

Answer

(d) 0.8

(2.1)2−(1.9)2=(2.1+1.9)(2.1−1.9)=4×0.2=0.8(2.1)^2-(1.9)^2=(2.1+1.9)(2.1-1.9)=4\times0.2=0.8

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  • 2077 · Management Model

What is the probability of getting a vowel letter from the word "EDUCATION" when one letter is selected? (a) 58\frac{5}{8} (b) 49\frac{4}{9} (c) 59\frac{5}{9} (d) 68\frac{6}{8}

Answer

(c) 59\frac{5}{9}

EDUCATION has 9 letters, of which E, U, A, I, O are vowels (5). Probability =59=\frac59.

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  • 2080 · Law Model · 1 mark

14\frac{1}{4} of a complete angle is (a) 60∘60^\circ (b) 45∘45^\circ (c) 30∘30^\circ (d) 90∘90^\circ

Answer

(d) 90∘90^\circ

A complete angle is 360∘360^\circ, so

14×360∘=90∘\frac{1}{4} \times 360^\circ = 90^\circ

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  • 2080 · Law Model · 1 mark

The perimeter of a square with measuring side 25 cm is (a) 100 cm (b) 150 cm (c) 75 cm (d) none

Answer

(a) 100 cm

P=4×side=4×25=100 cmP = 4 \times \text{side} = 4 \times 25 = 100 \text{ cm}

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  • 2080 · Law Model · 1 mark

What is the total sum of interior angles of a triangle? (a) 360 (b) 180 (c) 90 (d) 0

Answer

(b) 180

The sum of the interior angles of any triangle is 180∘180^\circ.

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  • 2080 · Law Model · 1 mark

If USD 1 is equivalent to Nepali Rupees 128, how much USD is equivalent to Rs. 100? (a) USD 0.78 (b) USD 12800 (c) USD 1.28 (d) none

Answer

(a) USD 0.78

USD=100128=0.78125≈0.78\text{USD} = \frac{100}{128} = 0.78125 \approx 0.78

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  • 2080 · Law Model · 1 mark

The mean of the data 4, 10, 5, 9, 12 is (a) 8 (b) 10 (c) 9 (d) 15

Answer

(a) 8

Mean=4+10+5+9+125=405=8\text{Mean} = \frac{4+10+5+9+12}{5} = \frac{40}{5} = 8

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  • 2080 · Law Model · 1 mark

Which of the following is not a sub-set of A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\}? (a) { }\{\ \} (b) {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\} (c) both (d) none

Answer

(b) {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\}

A subset can contain only elements of AA. The set in (b) contains 6, which is not in AA. The empty set { }\{\ \} is a subset of every set.

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Questions from CCRC Entrance Model Question 2077 (Science) (College model paper for the +2 Science entrance, 100 MCQs, 2077 BS; page images posted on a student blog), CCRC Entrance Examination Model Questions 2080 (Science) (College model paper for the +2 Science entrance, 100 MCQs; linked from the CCRC model questions page (ccrc.edu.np/modelquestions/) and posted as 2080 images on a student blog), CCRC Entrance Examination Model Questions 2080 (Management) (College model paper for the +2 Management entrance, 100 MCQs, 2080 BS), CCRC Entrance Examination Model Questions (Management), current model on the admission page (Management model paper linked from ccrc.edu.np/modelquestions/ for the 2083/84 admission; same questions as the 2080 paper), CCRC Entrance Model Question 2079 (Management/Humanities) (College model paper for the +2 Management/Humanities entrance, 2079 BS), CCRC Model Question for Grade XI Admission (+2 Law) (College model paper for the +2 Law entrance (language test and 50 MCQs), posted 2022 (2079 BS)), CCRC Entrance Examination Model Questions 2081 (Science) (College model paper for the +2 Science entrance, 100 MCQs, posted June 2024 (2081 BS)), CCRC Entrance Examination Model Questions 2081 (Management) (College model paper for the +2 Management entrance, 100 MCQs, posted June 2024 (2081 BS)), CCRC Entrance Model Question 2079 (Science) (College model paper for the +2 Science entrance, 100 MCQs, 2079 BS), CCRC Entrance Model Question 2077 (Management) (College model paper for the +2 Management entrance, 75 MCQs, 2077 BS) and CCRC Entrance Examination Model Questions 2080 (Law) (College model paper for the +2 Law entrance (language test and 50 MCQs), 2080 BS). Answers are written for this site; check them against your class notes.