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Chapter 3

Physics

+2 college entrance (after SEE) past exam questions

Past questions and answers

12 questions set from this chapter. Most repeated first.

  • Uniglobe SS/College Entrance Model Set

X rays are: (a) electromagnetic radiation (b) highly energetic (c) absorbed by metal like lead (d) all of the above

Answer

(d) all of the above X-rays are high-energy electromagnetic radiation of very short wavelength, and they are absorbed by dense metals such as lead, which is why lead shielding is used.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Which one of the following is effect of heat? (a) rise of temp. (b) increase in volume (c) change in state (d) all

Answer

(d) all Heat can raise the temperature of a body, increase its volume (thermal expansion) and change its state (melting, boiling).

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Numerical ratio of displacement to distance (a) <1< 1 (b) >1> 1 (c) ≤1\le 1 (d) ≥1\ge 1

Answer

(c) ≤1\le 1

Displacement is the shortest (straight-line) distance between the start and end points, while distance is the actual path length. So displacement ≤\le distance, and the ratio is displacementdistance≤1,\frac{\text{displacement}}{\text{distance}} \le 1, with equality only for motion along a straight line without reversing.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

A motorbike engine needs 1 HP so as to move with uniform velocity of 10 m/s. What is the friction force between tyre and road? (a) 10 N (b) 47.6 N (c) 746 N (d) 74.6 N

Answer

(d) 74.6 N

At uniform velocity the engine force equals the friction force, and P=FvP = Fv. With P=1 HP=746P = 1\ \text{HP} = 746 W: F=Pv=74610=74.6 NF = \frac{P}{v} = \frac{746}{10} = 74.6\ \text{N}

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Weight of body of mass mm at the centre of earth is (a) mgmg (b) 0 (c) infinity (d) none of above

Answer

(b) 0

At the centre of the earth the net gravitational pull from the surrounding mass cancels in all directions, so g=0g = 0 and the weight mg=0mg = 0.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Which of the following represents mass of the earth if acceleration due to gravity at earth surface is gg and radius of earth is RR? (a) g2R/Gg^2R/G (b) gR2/GgR^2/G (c) GR2/gGR^2/g (d) none of above

Answer

(b) gR2/GgR^2/G

At the surface g=GMR2g = \dfrac{GM}{R^2}, so M=gR2GM = \frac{gR^2}{G}

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

When a body is immersed in liquid, its apparent weight (a) decreases (b) increases (c) zero (d) is equal to actual weight

Answer

(a) decreases

An immersed body experiences an upward buoyant force, so apparent weight = actual weight −- upthrust, which is less than the actual weight.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Velocity of sound in air will not decreases when (a) temperature increases (b) Temperature decreases (c) frequency decreases (d) humidity decreases

Answer

(c) frequency decreases

The speed of sound in air depends on the medium: it rises with temperature and with humidity (so it falls when temperature or humidity decreases), but it does not depend on frequency (v=fλv = f\lambda, and λ\lambda adjusts). So lowering the frequency does not decrease the velocity.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

The critical angle of Diamond is: (a) 24 (b) 25 (c) 27 (d) 28

Answer

(a) 24

For diamond, n≈2.42n \approx 2.42: sin⁡C=1n=12.42≈0.413⇒C≈24.4∘≈24∘\sin C = \frac{1}{n} = \frac{1}{2.42} \approx 0.413 \Rightarrow C \approx 24.4^\circ \approx 24^\circ

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

What is the thermal capacity of 2 kg of water in J/°C? (a) 8.4×1038.4 \times 10^3 (b) 8.6×1038.6 \times 10^3 (c) 8.2×1038.2 \times 10^3 (d) 8.1×1038.1 \times 10^3

Answer

(a) 8.4×1038.4 \times 10^3

Thermal capacity =mc=2×4200=8400 J/∘C=8.4×103= mc = 2 \times 4200 = 8400\ \text{J/}^\circ\text{C} = 8.4 \times 10^3 J/°C, using c=4200c = 4200 J/kg°C for water.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

Light year is the unit of: (a) current (b) mass (c) time (d) length

Answer

(d) length

A light year is the distance light travels in one year, about 9.46×10159.46 \times 10^{15} m.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Uniglobe SS/College Entrance Model Set

The weight of body changes due to change in: (a) velocity (b) volume (c) acceleration (d) none

Answer

(c) acceleration

Weight W=mgW = mg, so it changes when the acceleration due to gravity gg changes (for example with altitude or place), while the mass stays constant.

Answer checked by Claude Sonnet · Oct 21, 2026

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Questions from Uniglobe SS/College Entrance Model Set (Science) (Model question set for the Class 11 Science entrance, 60 MCQs (English 10, Science 30, Mathematics 20); year not stated, collected on the gaurab123.com.np +2 entrance model-set page (2024)). Answers are written for this site; check them against your class notes.