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Chapter 10

Chemistry of Metals

NEB Class 11 past exam questions

Past questions and answers

20 questions set from this chapter. Most repeated first.

  • 2074 (2017) · Regular, 112 'A' · 2 marks

What is meant by slag? Write an example of it.

Answer

Slag is the fusible mass formed when a flux combines with the gangue (infusible impurities) during smelting. It is lighter than the molten metal, so it floats on top and is easily removed.

Example: in the extraction of iron, the basic flux CaO combines with the acidic gangue SiO2_2:

CaO+SiO2→CaSiO3 (slag)\mathrm{CaO + SiO_2 \rightarrow CaSiO_3\ (slag)}

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  • 2074 (2017) · Regular, 112 'A' · 1+1 marks

What happens when (i) Bleaching powder is treated with dil. H2SO4\mathrm{H_2SO_4} (ii) Gypsum salt is heated above 130∘C130^\circ\mathrm{C}

Answer

(i) Bleaching powder with dilute H2_2SO4_4 liberates chlorine (this is the chlorine that does the bleaching):

CaOCl2+H2SO4→CaSO4+H2O+Cl2\mathrm{CaOCl_2 + H_2SO_4 \rightarrow CaSO_4 + H_2O + Cl_2}

(ii) Gypsum first loses water to give plaster of Paris at about 120 °C. When heated above 130 °C it loses all its water and forms anhydrous calcium sulphate (dead burnt plaster), which has no setting property:

CaSO4⋅2H2O→>130∘CCaSO4+2H2O\mathrm{CaSO_4\cdot 2H_2O \xrightarrow{>130^\circ C} CaSO_4 + 2H_2O}

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  • 2074 (2017) · Regular, 112 'A' · 2.5+2.5 marks

Write short notes on: (i) Hydrometallurgy (ii) Zone refining

Answer

(i) Hydrometallurgy

It is a metallurgical process in which the metal is extracted from its ore by dissolving it in a suitable aqueous reagent (leaching), and then the metal is recovered from the solution by displacement with a more electropositive metal or by electrolysis. It is used for low-grade ores of noble metals such as gold, silver and also copper.

Example (cyanide process for gold/silver): the ore is leached with dilute NaCN solution in the presence of air:

4Au+8NaCN+2H2O+O2→4Na[Au(CN)2]+4NaOH\mathrm{4Au + 8NaCN + 2H_2O + O_2 \rightarrow 4Na[Au(CN)_2] + 4NaOH}

Gold is then displaced by zinc:

2Na[Au(CN)2]+Zn→Na2[Zn(CN)4]+2Au\mathrm{2Na[Au(CN)_2] + Zn \rightarrow Na_2[Zn(CN)_4] + 2Au}

(ii) Zone refining

It is used to obtain metals of very high purity (e.g. Ge, Si, Ga, B, which are used in semiconductors). Principle: impurities are more soluble in the molten metal than in the solid metal.

A rod of impure metal is fitted with a circular heater at one end. The heater creates a narrow molten zone and is slowly moved along the rod. As the heater moves on, pure metal crystallises out behind it while the impurities pass into the adjacent molten zone and are swept to the other end. The process is repeated several times, and the end containing the impurities is cut off.

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  • 2074 (2017) · Regular, 112 'A' · 6+1+1+2 marks

Write the principle and process along with self-explanatory diagram for the manufacture of sodium by Down's method. Why is sodium fire at laboratory not extinguished by adding water? Mention any two advantages of Down's process. How is sodium converted into washing soda.

Answer

Principle: Sodium is a very strong reducing agent, so it cannot be extracted by chemical reduction. It is obtained by electrolysis of fused (molten) sodium chloride. A little CaCl2\mathrm{CaCl_2} is added to lower the melting point from 801∘C801^\circ\mathrm{C} to about 600∘C600^\circ\mathrm{C}.

Process (Down's cell): The cell is a rectangular steel tank lined with firebrick. A graphite anode is placed at the centre, surrounded by a circular iron cathode. A wire-gauze diaphragm between the electrodes keeps the products apart. Above the cathode is an inverted trough that collects the molten sodium, and above the anode is a dome that collects chlorine.

        Cl2 out            Na out
          |                  |
       [ dome ]        [ trough ]
     ----|----------------|-------
     |   anode (C)  gauze  cathode (Fe) |
     |        molten NaCl + CaCl2       |
     ------------------------------------

On passing current through the molten mixture:

NaCl→Na++Cl−\mathrm{NaCl \rightarrow Na^+ + Cl^-}

At cathode: Na++e−→Na\mathrm{Na^+ + e^- \rightarrow Na} (liquid sodium floats up and is collected)

At anode: 2Cl−→Cl2+2e−\mathrm{2Cl^- \rightarrow Cl_2 + 2e^-} (chlorine is collected as by-product)

Overall: 2NaCl→2Na+Cl2\mathrm{2NaCl \rightarrow 2Na + Cl_2}

Why a sodium fire is not put out with water: Sodium reacts violently with water to form NaOH and hydrogen, 2Na+2H2O→2NaOH+H2\mathrm{2Na + 2H_2O \rightarrow 2NaOH + H_2}. The reaction is highly exothermic, so the hydrogen catches fire and the fire spreads. Dry sand or a dry powder extinguisher is used instead.

Two advantages of Down's process:

  • Fused NaCl with CaCl2\mathrm{CaCl_2} melts at a lower temperature (about 600∘C600^\circ\mathrm{C}), so less energy is used.
  • The diaphragm keeps sodium and chlorine apart, so pure sodium is obtained along with useful chlorine as a by-product. (Sodium also does not vapourise or burn as easily at this temperature.)

Sodium to washing soda: Sodium reacts with water to give NaOH, which absorbs CO2\mathrm{CO_2} to form sodium carbonate. Crystallisation from water gives washing soda.

2Na+2H2O→2NaOH+H2\mathrm{2Na + 2H_2O \rightarrow 2NaOH + H_2} 2NaOH+CO2→Na2CO3+H2O\mathrm{2NaOH + CO_2 \rightarrow Na_2CO_3 + H_2O} Na2CO3+10H2O→Na2CO3⋅10H2O\mathrm{Na_2CO_3 + 10H_2O \rightarrow Na_2CO_3\cdot 10H_2O}

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  • 2074 (2018) · Upgrading (Supplementary) · 2 marks

Define the terms: gangue and slag, giving proper example of each.

Answer

Gangue: The earthy and rocky impurities (sand, clay, etc.) present in an ore are called gangue. Example: silica (SiO2\mathrm{SiO_2}) in iron ore.

Slag: The fusible compound formed when flux reacts with gangue during smelting is called slag. Example: calcium silicate, formed in the blast furnace:

CaO+SiO2→CaSiO3\mathrm{CaO + SiO_2 \rightarrow CaSiO_3}

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  • 2074 (2018) · Upgrading (Supplementary) · 1+1 marks

What happens when: (i) Gypsum salt is heated at 120∘C120^\circ\mathrm{C} (ii) Chlorine gas is passed through slaked lime.

Answer

(i) On heating at 120∘C120^\circ\mathrm{C}, gypsum loses part of its water of crystallisation and forms plaster of Paris:

2CaSO4⋅2H2O→120∘C(CaSO4)2⋅H2O+3H2O\mathrm{2CaSO_4\cdot 2H_2O \xrightarrow{120^\circ C} (CaSO_4)_2\cdot H_2O + 3H_2O}

(ii) Chlorine reacts with slaked lime to form bleaching powder:

Ca(OH)2+Cl2→CaOCl2+H2O\mathrm{Ca(OH)_2 + Cl_2 \rightarrow CaOCl_2 + H_2O}

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  • 2074 (2018) · Upgrading (Supplementary) · 2.5+2.5 marks

Write short notes on: (i) Carbon reduction process (ii) Froth floatation process.

Answer

(i) Carbon reduction process: Oxides of less reactive metals are reduced by heating with carbon (coke), which acts as the reducing agent. The metal is obtained and carbon monoxide or dioxide is released. The oxide is obtained first if the ore is a carbonate (by calcination) or a sulphide (by roasting).

ZnO+C→ΔZn+CO\mathrm{ZnO + C \xrightarrow{\Delta} Zn + CO} Fe2O3+3CO→Δ2Fe+3CO2\mathrm{Fe_2O_3 + 3CO \xrightarrow{\Delta} 2Fe + 3CO_2}

It is used for metals such as Fe, Zn, Sn and Pb, whose oxides are easily reduced by carbon at feasible temperatures.

(ii) Froth floatation process: This is used to concentrate sulphide ores (e.g. galena PbS, zinc blende ZnS, copper pyrites). The finely powdered ore is mixed with water, pine oil (a frothing agent) and a collector such as sodium ethyl xanthate in a tank, and air is blown in. The oil wets the sulphide particles, which stick to the air bubbles and rise with the froth. The gangue is wetted by water and settles. The froth is skimmed off and the concentrated ore is obtained. Depressants such as NaCN can be used to separate ores of different metals (e.g. ZnS from PbS).

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  • 2075 (2018) · 112 'B' · 2 marks

Name any four important ores which are found in different parts of Nepal.

Answer

Four important ores of Nepal:

  1. Haematite (Fe2O3\mathrm{Fe_2O_3}), iron ore, found at Phulchoki (Lalitpur).
  2. Copper pyrites (CuFeS2\mathrm{CuFeS_2}), found in Kavrepalanchok and Dhading.
  3. Galena (PbS\mathrm{PbS}), lead ore, found in the Ganesh Himal area.
  4. Magnesite (MgCO3\mathrm{MgCO_3}), found at Kharidhunga, Dolakha.

(Zinc blende, ZnS, and limestone are also found.)

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  • 2075 (2018) · 112 'B' · 1+1 marks

Give reason. (i) Sodium metal gets tarnished in air. (ii) Carbon reduction process is not applied for the extraction of alkali metals.

Answer

(i) Sodium is very reactive. In air it reacts with oxygen, moisture and CO₂ to form a dull layer of Na₂O, NaOH and Na₂CO₃ on its surface, so the shiny metal tarnishes. (It is therefore kept under kerosene.)

(ii) Alkali metals are very strong reducing agents, and their oxides are much more stable than the oxides of carbon, so carbon cannot reduce them (and at high temperature carbides form). They are extracted by electrolysis of their fused chlorides.

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  • 2075 (2018) · 112 'B' · 5 marks

Write down the chemistry of Epsom salt.

Answer

Epsom salt is hydrated magnesium sulphate, MgSO4⋅7H2O\mathrm{MgSO_4\cdot 7H_2O}. It is a colourless, crystalline, bitter-tasting solid, very soluble in water.

Preparation. It is obtained by dissolving magnesite or magnesium oxide in dilute sulphuric acid, filtering, and crystallising below 48∘C48^\circ\mathrm{C} (the heptahydrate separates):

MgCO3+H2SO4→MgSO4+H2O+CO2\mathrm{MgCO_3 + H_2SO_4 \rightarrow MgSO_4 + H_2O + CO_2}

Industrially it is also obtained from the mineral kieserite, MgSO4⋅H2O\mathrm{MgSO_4\cdot H_2O}, by dissolving it in water and recrystallising.

Action of heat. On heating it loses water in stages:

MgSO4⋅7H2O→150∘CMgSO4⋅H2O→>200∘CMgSO4\mathrm{MgSO_4\cdot 7H_2O \xrightarrow{150^\circ C} MgSO_4\cdot H_2O \xrightarrow{>200^\circ C} MgSO_4}

At very high temperature the anhydrous salt decomposes to MgO\mathrm{MgO} and SO3\mathrm{SO_3}.

Chemical reactions.

  • With BaCl2\mathrm{BaCl_2} it gives a white precipitate of BaSO4\mathrm{BaSO_4} (test for sulphate): MgSO4+BaCl2→BaSO4↓+MgCl2\mathrm{MgSO_4 + BaCl_2 \rightarrow BaSO_4\downarrow + MgCl_2}
  • With NaOH\mathrm{NaOH}: MgSO4+2NaOH→Mg(OH)2↓+Na2SO4\mathrm{MgSO_4 + 2NaOH \rightarrow Mg(OH)_2\downarrow + Na_2SO_4}
  • With Na2HPO4\mathrm{Na_2HPO_4} in presence of NH4Cl\mathrm{NH_4Cl} and NH4OH\mathrm{NH_4OH} it gives a white precipitate of magnesium ammonium phosphate, MgNH4PO4\mathrm{MgNH_4PO_4}.
  • With sodium carbonate it gives a white precipitate of basic magnesium carbonate.

Uses.

  • As a purgative (laxative) in medicine and for relieving muscle pain in baths.
  • In dyeing and calico printing, and for making cotton and silk fabrics fire-proof and heavy.
  • As a source of magnesium in fertilisers and in tanning leather.

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  • 2076 (2019) · 112 'B' · 1+1 marks

Distinguish between alloys and amalgams giving an example of each.

Answer

An alloy is a homogeneous mixture of a metal with one or more other metals or non-metals, made by melting them together. Example: brass (Cu+Zn\mathrm{Cu + Zn}).

An amalgam is a special alloy in which one of the metals is mercury. Example: sodium amalgam, Na−Hg\mathrm{Na-Hg} (or the silver-tin amalgam used in dental filling).

So every amalgam is an alloy, but an alloy is an amalgam only if it contains mercury.

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  • 2076 (2019) · 112 'B' · 2 marks

Why do alkali metals impart characteristic colours when introduced to the flame?

Answer

Alkali metals have low ionisation energies and a single loosely held valence electron. In a flame, this electron absorbs a small amount of energy and jumps to a higher energy level. The excited electron is unstable and returns to the ground state, releasing the absorbed energy as radiation. For alkali metals this energy falls in the visible region, so the flame is coloured. Each metal has its own energy-level spacing, so the colour is characteristic: Li crimson red, Na golden yellow, K lilac (violet), Rb red-violet, Cs blue.

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  • 2076 (2019) · 112 'B' · 5 marks

Give the chemistry of plaster of Paris.

Answer

Plaster of Paris (POP)

Chemical name: calcium sulphate hemihydrate; formula CaSO4⋅12H2O\mathrm{CaSO_4\cdot\tfrac{1}{2}H_2O} (or 2CaSO4⋅H2O\mathrm{2CaSO_4\cdot H_2O}).

Preparation

It is prepared by heating gypsum, CaSO4⋅2H2O\mathrm{CaSO_4\cdot 2H_2O}, at about 120120–130∘C130^\circ\mathrm{C} (the temperature must be controlled):

CaSO4⋅2H2O→120−130∘CCaSO4⋅12H2O+112H2O\mathrm{CaSO_4\cdot 2H_2O \xrightarrow{120-130^\circ C} CaSO_4\cdot\tfrac{1}{2}H_2O + 1\tfrac{1}{2}H_2O}

Properties

  1. It is a white powder, slightly soluble in water.
  2. Setting: when mixed with water to a paste, it takes up water and sets into a hard, porous solid mass of gypsum, with a slight expansion in volume:

CaSO4⋅12H2O+112H2O→CaSO4⋅2H2O\mathrm{CaSO_4\cdot\tfrac{1}{2}H_2O + 1\tfrac{1}{2}H_2O \rightarrow CaSO_4\cdot 2H_2O}

  1. Overheating: at about 200∘C200^\circ\mathrm{C} it loses all its water to form anhydrous CaSO4\mathrm{CaSO_4} (dead burnt plaster), which does not set with water.

CaSO4⋅12H2O→200∘CCaSO4+12H2O\mathrm{CaSO_4\cdot\tfrac{1}{2}H_2O \xrightarrow{200^\circ C} CaSO_4 + \tfrac{1}{2}H_2O}

Because of this, POP must be stored in a moisture-proof container.

Uses

  • In hospitals, to make plaster casts for setting fractured bones.
  • To make statues, toys, models and decorative articles.
  • For plastering walls and ceilings, and false ceilings.
  • In dentistry, to make moulds and casts.
  • In making chalk, and as a fire-proofing material.

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  • NEB Class 11 Chemistry Model Question · 1 mark

Which is the correct order of ease of carbon dioxide production by heating the Group II metal carbonates? (a) MgCO3_3 > BeCO3_3 > CaCO3_3 > RaCO3_3 (b) CaCO3_3 > MgCO3_3 > BeCO3_3 > RaCO3_3 (c) BeCO3_3 > MgCO3_3 > CaCO3_3 > BaCO3_3 (d) BeCO3_3 < MgCO3_3 < CaCO3_3 < RaCO3_3

Answer

(c) BeCO3_3 > MgCO3_3 > CaCO3_3 > BaCO3_3

Thermal stability of Group II carbonates increases down the group, so the ease of giving off CO2_2 decreases down the group. The small Be2+^{2+} ion has high polarising power and distorts the carbonate ion most, weakening its C–O bond, so BeCO3_3 decomposes most easily; the large Ba2+^{2+} ion polarises least, so BaCO3_3 is the most stable and needs the highest temperature. (Option (d) gives the reverse order, i.e. order of thermal stability.)

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  • NEB Class 11 Chemistry Model Question · 1 mark

When electricity is passed through the molten NaCl in the presence of CaCl2_2 in the ratio of 2:3 by weight using graphite anode and iron cathode as electrodes, sodium metal is deposited at cathode and chlorine gas is liberated at anode in the electrolytic cell. i. Define electrolytic cell.

Answer

An electrolytic cell is an electrochemical cell in which electrical energy from an external source is used to bring about a non-spontaneous chemical change, e.g. the decomposition of molten NaCl into sodium metal at the cathode and chlorine gas at the anode.

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  • NEB Class 11 Chemistry Model Question · 1 mark

Why does calcium metal not deposit instead of sodium at the cathode?

Answer

Calcium is more electropositive than sodium (standard reduction potential −2.87-2.87 V for Ca2+^{2+}/Ca against −2.71-2.71 V for Na+^+/Na), so Ca2+^{2+} ions are harder to reduce than Na+^+ ions. CaCl2_2 is added only to lower the melting point of NaCl, and at the controlled voltage used, Na+^+ is preferentially discharged at the cathode:

Na++e−→Na\text{Na}^+ + e^- \rightarrow \text{Na}

So sodium, not calcium, is deposited.

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  • NEB Class 11 Chemistry Model Question · 1 mark

Aqueous solution of sodium chloride cannot be instead of molten sodium chloride for the same intended product? Give reason.

Answer

In aqueous NaCl, water is also present. Water is reduced at the cathode more easily than Na+^+ (Na is much more electropositive than hydrogen), so hydrogen gas is liberated instead of sodium:

2H2O+2e−→H2+2OH−2\text{H}_2\text{O} + 2e^- \rightarrow \text{H}_2 + 2\text{OH}^-

Any sodium formed would also react with water. Metallic sodium is therefore obtained only by electrolysis of molten NaCl, so aqueous NaCl cannot replace it for the same product.

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  • NEB Class 11 Chemistry Model Question · 2 marks

Depending upon the nature of minerals present in the ores, calcination and roasting are mainly used for the conversion of ores into their respective oxides. i. What do you mean by roasting and calcination in the metallurgical process?

Answer

Roasting is the process of heating a sulphide ore strongly in the presence of excess air (oxygen) to convert it into its oxide. Sulphur is removed as sulphur dioxide gas.

2ZnS+3O2→heat2ZnO+2SO22ZnS + 3O_2 \xrightarrow{\text{heat}} 2ZnO + 2SO_2

Calcination is the process of heating a carbonate or hydrated oxide ore strongly in the absence (limited supply) of air to convert it into its oxide. Carbon dioxide or water vapour is removed.

ZnCO3→heatZnO+CO2ZnCO_3 \xrightarrow{\text{heat}} ZnO + CO_2

So the key difference is the atmosphere: roasting needs air and is used for sulphide ores, while calcination is done in the absence of air and is used for carbonate ores.

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  • NEB Class 11 Chemistry Model Question · 1 mark

Name the vessel in which roasting is carried out.

Answer

Roasting is carried out in a reverberatory furnace, where the ore is heated strongly in a plentiful supply of air, below its melting point, to convert sulphide ores into oxides.

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  • NEB Class 11 Chemistry Model Question · 2 marks

Write the name of two possible impurities that are removed in the roasting.

Answer

Two impurities removed during roasting:

  1. Sulphur — present as sulphide ores (e.g. ZnS, PbS, Cu₂S); it is oxidised to sulphur dioxide gas and escapes.
  2. Arsenic (and antimony) — present as arsenides; they are oxidised to volatile oxides (As₂O₃) which sublime off.

Roasting is the heating of an ore in a plentiful supply of air, so the impurities removed are those that form volatile products — mainly sulphur (as SO₂) and arsenic/antimony (as their volatile oxides).

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Questions from NEB Class 11 Chemistry Model Question (New Course, Code 3011) (NEB/CDC model paper, Grade 11, 2077/2078), Practice questions written for this site (Written from the official syllabus and specification grid where no past papers cover a chapter), NEB Grade XI 2074 (2017) Chemistry 112 'A' (old course) (Old HSEB/NEB Grade XI regular board exam, 2074 (2017). Old-course paper; only questions fitting the current outline taken.), NEB Grade XI 2074 (2018) Chemistry 112 Upgrading (Supplementary) (Old-course NEB Grade XI upgrading/supplementary exam, 2074 (2018).), NEB Grade XI 2075 (2018) Chemistry 112 'B' (old course) (Old-course NEB Grade XI board exam, 2075 (2018), set B.) and NEB Grade XI 2076 (2019) Chemistry 112 'B' (old course) (Old-course NEB Grade XI board exam, 2076 (2019), set B.). Answers are written for this site; check them against your class notes.

Chapter titles and hours from the official syllabus ↗