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Chapter 4

Classification of Elements and Periodic Table

NEB Class 11 past exam questions

Past questions and answers

11 questions set from this chapter, 2 of them more than once. Most repeated first.

  • Asked 2 times
  • 2074 (2017) · Regular, 112 'A' · 2 marks
  • 2074 (2018) · Upgrading (Supplementary) · 1+1 marks

Which ion would you expect to have larger size and why? Mg2+\mathrm{Mg^{2+}} or Na+\mathrm{Na^{+}}

Answer

Na+^+ is larger than Mg2+^{2+}.

Both are isoelectronic (10 electrons, configuration 1s22s22p61s^2 2s^2 2p^6), so they have the same electron shells. Mg2+^{2+} has 12 protons and Na+^+ has only 11, so the nuclear charge on the same 10 electrons is higher in Mg2+^{2+}. It pulls the electron cloud in more strongly, making Mg2+^{2+} smaller.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • Asked 2 times
  • 2076 (2019) · 112 'B' · 5 marks
  • 2074 (2018) · Upgrading (Supplementary) · 5 marks

Write a short note on the advantages of the modern periodic table.

Answer

Advantages of the modern periodic table

The modern periodic table is based on the modern periodic law: the properties of elements are a periodic function of their atomic numbers. It is arranged in 1818 groups and 77 periods, and has the following advantages.

  1. Based on atomic number. Atomic number is a fundamental property, so the arrangement is exact and removes the anomalies of Mendeleev's table (e.g. Ar and K, Te and I are now in the right order even though atomic masses are reversed).
  2. Correlates with electronic configuration. The position of an element shows its configuration: the period number is the number of the outermost shell, and the group shows the number of valence electrons. Elements are divided into ss, pp, dd and ff blocks.
  3. Clear groups. Elements of a group have similar outer electronic configurations, hence similar properties, which makes them easy to study as families.
  4. Isotopes. Isotopes of an element share one atomic number, so they occupy one position, which removes the problem of finding places for them.
  5. Separation of metals, non-metals and metalloids. They lie in separate regions, and trends in properties (atomic size, ionisation energy, electronegativity, metallic character) are easy to see across periods and down groups.
  6. Places transition and inner-transition elements properly, and separates the sub-groups A and B of Mendeleev's table so the confusion between them is removed.
  7. Easy to remember, and helps predict properties of unknown elements and their compounds.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2074 (2017) · Regular, 112 'A' · 5 marks

Write a short note on Mendeleev's periodic table and its anomalies.

Answer

Mendeleev's periodic law: The physical and chemical properties of the elements are a periodic function of their atomic masses.

Mendeleev's periodic table: The elements were arranged in order of increasing atomic mass in 7 horizontal rows called periods and 8 vertical columns called groups (I to VIII, with the subgroups A and B). Elements in the same group showed similar properties. Mendeleev left gaps for undiscovered elements and predicted their properties, e.g. eka-aluminium (gallium) and eka-silicon (germanium), and these predictions were later confirmed.

Merits:

  • It classified the known elements systematically and made study easier.
  • It predicted new elements and corrected doubtful atomic masses.

Anomalies (defects):

  1. Hydrogen had no fixed position, since it resembles both alkali metals and halogens.
  2. Isotopes have different atomic masses but the same properties, yet had no separate place in the table.
  3. Some elements of higher atomic mass were placed before those of lower atomic mass to keep similar elements together, e.g. Ar (39.9) before K (39.1), Co (58.9) before Ni (58.7), Te (127.6) before I (126.9).
  4. Dissimilar elements were placed in the same group, e.g. alkali metals (Li, Na, K) with coinage metals (Cu, Ag, Au) in group I.
  5. There was no proper place for the lanthanides and actinides, and the position of the eighth group was unclear.

These anomalies were removed when Moseley showed that properties depend on atomic number rather than atomic mass, giving the modern periodic law.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 (2018) · 112 'B' · 2 marks

Which of the following is the smallest in size? N3−\mathrm{N^{3-}}, O2−\mathrm{O^{2-}}, F−\mathrm{F^-}, and Na+\mathrm{Na^+} Give appropriate reason.

Answer

Na⁺ is the smallest.

All four ions are isoelectronic (10 electrons, 1s22s22p61s^2 2s^2 2p^6), so their size depends on nuclear charge: the greater the number of protons, the stronger the pull on the same number of electrons and the smaller the ion.

Nuclear charge: N3−(+7)<O2−(+8)<F−(+9)<Na+(+11)\mathrm{N^{3-}}(+7) < \mathrm{O^{2-}}(+8) < \mathrm{F^-}(+9) < \mathrm{Na^+}(+11), so size is N3−>O2−>F−>Na+\mathrm{N^{3-}} > \mathrm{O^{2-}} > \mathrm{F^-} > \mathrm{Na^+}.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2075 (2018) · 112 'B' · 5 marks

Write a short note on the demerits of Mendeleev's periodic table.

Answer

Mendeleev arranged the elements in order of increasing atomic mass, and this led to several defects.

  1. Position of hydrogen. Hydrogen resembles both alkali metals (group I) and halogens (group VII), but has no fixed place.
  2. Anomalous pairs. Some elements of higher atomic mass come before those of lower atomic mass to maintain the properties, e.g. Ar (39.9) before K (39.1), Co (58.9) before Ni (58.7), Te (127.6) before I (126.9). This breaks the basic rule.
  3. Isotopes. Isotopes of an element have different atomic masses but identical chemical properties. By mass they should occupy different places, but no place was provided for them.
  4. Dissimilar elements placed together. Alkali metals (Li, Na, K) and coinage metals (Cu, Ag, Au) were placed in the same group I although their properties differ greatly.
  5. Similar elements placed apart. Chemically similar elements, e.g. Cu and Hg or Pt and Au, were placed in different groups.
  6. Lanthanides and actinides (14 + 14 elements) had no proper place in the table.
  7. Noble gases were not known at the time and had to be added later as a new group; the position of group VIII (Fe, Co, Ni) was also doubtful.
  8. Atomic mass does not vary regularly from one element to the next, so the missing elements could not always be predicted reliably.

These defects were removed by the modern periodic law, which uses atomic number (Moseley) as the basis.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • 2076 (2019) · 112 'B' · 2 marks

Which one has greater electron affinity and why? Cl or F

Answer

Chlorine has the greater electron affinity (about 349 kJ mol−1349\ \text{kJ mol}^{-1} for Cl against 328 kJ mol−1328\ \text{kJ mol}^{-1} for F).

Fluorine is very small, and its 2p2p subshell is compact. The electron density there is high, so an incoming electron is strongly repelled by the electrons already present. In chlorine the electron enters the larger 3p3p subshell, where the repulsion is much less, so more energy is released.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • NEB Class 11 Chemistry Model Question · 1 mark

Size of X3−^{3-} ion is greater than that of X atom though both contain the same number of protons. Give reason.

Answer

The X3−X^{3-} ion is formed when the atom gains three electrons, so it has three more electrons than protons, while the nuclear charge (number of protons) stays the same. The same nuclear pull is now shared among more electrons, and the increased electron-electron repulsion makes the electron cloud spread out. Hence the effective nuclear attraction per electron decreases and the ion is larger than the atom.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • NEB Class 11 Chemistry Model Question · 1 mark

Know-how about ionization energy (IE) of elements is crucial aspect in the study of chemical bonding whether they form ionic or covalent bond. The first ionization energies of period second elements are given below:
Name of ElementsLiBeBONOFNe
First ionization energy (kJ/mol)52089980110861403141016812080
i. Define first ionization energy.
Figure: Table of first ionization energies of period 2 elements.

Answer

First ionization energy is the minimum amount of energy required to remove the most loosely bound (outermost) electron from an isolated gaseous atom in its ground state to form a gaseous unipositive ion.

M(g)+IE1→M+(g)+e−\text{M}(g) + \text{IE}_1 \rightarrow \text{M}^+(g) + e^-

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  • NEB Class 11 Chemistry Model Question · 1 mark

Name a factor that affects the value of IE.

Answer

Atomic size (or nuclear charge / shielding effect).

Ionisation enthalpy decreases as atomic size increases (the outer electron lies farther from the nucleus, so it is held less tightly), and increases with greater nuclear charge.

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  • NEB Class 11 Chemistry Model Question · 1 mark

Which of the element is most difficult to ionize?

Answer

(b) Helium

Helium has the highest ionization enthalpy in the periodic table (2372 kJ/mol) because its single electron lies in the tightly held, fully filled 1s orbital closest to the nucleus. Removing this electron requires the most energy, so helium is the most difficult element to ionize.

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  • NEB Class 11 Chemistry Model Question · 2 marks

Why is there steep rise in IE from carbon to nitrogen?

Answer

Reason: Nitrogen has a half-filled stable p-subshell (2p32p^3), while carbon has only a partially filled p-subshell (2p22p^2).

  • Carbon: 1s2 2s2 2p21s^2\,2s^2\,2p^2 — one p-orbital is empty.
  • Nitrogen: 1s2 2s2 2p31s^2\,2s^2\,2p^3 — all three p-orbitals are singly occupied (half-filled).

A half-filled subshell has extra stability due to greater exchange energy and symmetrical charge distribution. Therefore, removing an electron from nitrogen requires much more energy than from carbon, causing a steep rise in ionisation enthalpy from carbon to nitrogen.

Answer checked by Claude Sonnet · Oct 21, 2026

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Questions from NEB Class 11 Chemistry Model Question (New Course, Code 3011) (NEB/CDC model paper, Grade 11, 2077/2078), Practice questions written for this site (Written from the official syllabus and specification grid where no past papers cover a chapter), NEB Grade XI 2074 (2017) Chemistry 112 'A' (old course) (Old HSEB/NEB Grade XI regular board exam, 2074 (2017). Old-course paper; only questions fitting the current outline taken.), NEB Grade XI 2074 (2018) Chemistry 112 Upgrading (Supplementary) (Old-course NEB Grade XI upgrading/supplementary exam, 2074 (2018).), NEB Grade XI 2075 (2018) Chemistry 112 'B' (old course) (Old-course NEB Grade XI board exam, 2075 (2018), set B.) and NEB Grade XI 2076 (2019) Chemistry 112 'B' (old course) (Old-course NEB Grade XI board exam, 2076 (2019), set B.). Answers are written for this site; check them against your class notes.

Chapter titles and hours from the official syllabus ↗