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Chapter 9

जनसङ्ख्या अध्ययनका लागि सामान्य सङ्ख्यात्मक विधि

NEB Class 11 past exam questions

Past questions and answers

5 questions set from this chapter. Most repeated first.

  • 2076 (2019) · Regular · 8 marks

The elderly population of a district in 2001 and 2011 census were 28550 and 35420 respectively. Calculate the annual exponential growth rate of elderly population (rr) for the intercensal period.

Answer

Given: Elderly population in 2001, P0=28,550P_0 = 28{,}550; in 2011, Pt=35,420P_t = 35{,}420; time t=2011−2001=10t = 2011 - 2001 = 10 years.

Formula (exponential growth method):

Pt=P0ert⇒r=ln⁡(Pt/P0)tP_t = P_0 e^{rt} \quad\Rightarrow\quad r = \frac{\ln(P_t / P_0)}{t}

Calculation:

PtP0=35,42028,550=1.2406\frac{P_t}{P_0} = \frac{35{,}420}{28{,}550} = 1.2406

ln⁡(1.2406)=0.2156\ln(1.2406) = 0.2156

r=0.215610=0.02156r = \frac{0.2156}{10} = 0.02156

In percentage, r=0.02156×100≈2.16%r = 0.02156 \times 100 \approx 2.16\%.

Result: The annual exponential growth rate of the elderly population of the district during 2001-2011 is about 2.16% per year.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • CDC/NEB Class 11 Population Studies Model Question 2078 · 1 mark

State the formula for estimating population-doubling time.

Answer

The formula for estimating population-doubling time is:

Td=70rT_d = \frac{70}{r}

where TdT_d is the doubling time in years and rr is the annual population growth rate in percent.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • CDC/NEB Class 11 Population Studies Model Question 2078 · 1 mark

What is the doubling time for the population of Nepal as per the population growth rate of 1.35% according to census 2011 AD?

Answer

Using the rule of 70:

Td=701.35≈51.85≈52 yearsT_d = \frac{70}{1.35} \approx 51.85 \approx 52 \text{ years}

So Nepal's population would double in about 52 years at the 2011 growth rate of 1.35%.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • CDC/NEB Class 11 Population Studies Model Question 2078 · 5 marks

The population of Nepal was 23,151,523 and 26,494,504 respectively in 2001 and 2011. Find out the population growth rate by using exponential growth method.

Answer

Given: P0=23,151,523P_0 = 23{,}151{,}523 (2001), Pt=26,494,504P_t = 26{,}494{,}504 (2011), t=2011−2001=10t = 2011-2001 = 10 years.

Formula (exponential growth method):

Pt=P0ert⇒r=ln⁡(Pt/P0)tP_t = P_0 e^{rt} \quad\Rightarrow\quad r = \frac{\ln(P_t/P_0)}{t}

Calculation:

PtP0=26,494,50423,151,523=1.1444\frac{P_t}{P_0} = \frac{26{,}494{,}504}{23{,}151{,}523} = 1.1444

ln⁡(1.1444)=0.1349\ln(1.1444) = 0.1349

r=0.134910=0.01349r = \frac{0.1349}{10} = 0.01349

Growth rate in percentage: r=0.01349×100≈1.35%r = 0.01349 \times 100 \approx 1.35\%.

Result: The annual population growth rate of Nepal during 2001–2011 by the exponential method is about 1.35% per year.

Answer checked by Claude Sonnet · Oct 21, 2026

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  • NEB Grade XI Population Education/Studies, Sub.Code 146 · 8 marks

The elderly population of a city in 2001 and 2011 censuses were 18,250 and 23,140 respectively. Compute the annual population growth rate of elderly population using exponential growth rate.

Answer

Given: Elderly population in 2001, P0=18,250P_0 = 18{,}250; in 2011, Pt=23,140P_t = 23{,}140; time t=2011−2001=10t = 2011 - 2001 = 10 years.

Formula (exponential growth method):

Pt=P0ert⇒r=ln⁡(Pt/P0)tP_t = P_0 e^{rt} \quad\Rightarrow\quad r = \frac{\ln(P_t / P_0)}{t}

Calculation:

PtP0=23,14018,250=1.2679\frac{P_t}{P_0} = \frac{23{,}140}{18{,}250} = 1.2679

ln⁡(1.2679)=0.2374\ln(1.2679) = 0.2374

r=0.237410=0.02374r = \frac{0.2374}{10} = 0.02374

In percentage, r=0.02374×100≈2.37%r = 0.02374 \times 100 \approx 2.37\%.

Result: The annual exponential growth rate of the elderly population of the city during 2001-2011 is about 2.37% per year.

Answer checked by Claude Sonnet · Oct 21, 2026

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Questions from CDC/NEB Class 11 Population Studies Model Question 2078 (New Course) (CDC model paper, Sub.Code 2231, new course), NEB Grade XI Population Education/Studies 2076 (2019), Sub.Code 146 'B' (NEB board exam (regular), old course, FM 80. Only questions fitting the current outline were taken.) and NEB Grade XI Population Education/Studies, Sub.Code 146 (year not printed) (NEB board exam paper (official NEB Drive), old course, FM 80, year not printed. Only questions fitting the current outline were taken.). Answers are written for this site; check them against your class notes.

Chapter titles and hours from the official syllabus ↗